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hi,

this is my first post, i hope someone here can give me a hand with this.

i have created a new field in the member_profile table in my database. lets say i named it newfield.

i would like a yes to be placed in this newfield at the same time i give moderator privlages to a member.

i can manually enter a yes in newfield now with phpmyadmin.

 

i believe this code applies the moderator settings, any ideas on a way to have this post yes in my new field as well.

 

 

//make Moderator

//////////////////////

if (isset($_POST['moderator']) && isset($_POST['list'])) {

    foreach ($_POST['list'] as $user_id) {

        managemember($user_id,'moderator');

}

 

    //notifications

    $show_notification = 1;

    $message = notifications(1);

}

 

 

any help greatly appreciated.

 

 

 

 

 

 

 

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Apply the sql to your member table

 

Update

set newfield = "yes" where UserID = $user_id

 

You should just use a bool rather than a varchar for your newfield. So if you field is called "Moderator", insert 1 to allow moderator staus, and 0 for all else

ok set it up as bool and it now takes a value of 1 in newfield but i still have to add it manualy.  i still cant get the script to add a 1 at the same time that i set a member to moderator. it adds a 1 to the moderator field but not to the newfield. any ideas.

hi,

i hope this makes sense i don't have much experience with this stuff.

 

i have this adding a one to newfield in my database what would i need to do to make this check if newfield = 1 change newfield back to 0

 

 

 

$sql = "SELECT * FROM member_profile SET newfield = '1' WHERE  userid = $user_id";

 

 

Many Thanks

 

hi kansas

 

thanks, i pasted the wrong code this is the code that sets newfield to 1.

 

$sql = "UPDATE member_profile SET newfield = '1' WHERE user_id = $user_id";

 

 

what i would like to do is make this code check to see if newfield = 1  and if it does change newfield back to 0

 

 

I think the steps are just about there.  Me being new as well, I still get lost in what I want to do and what I am telling the code to do.

 

 

$sql = "SELECT * FROM member_profile SET newfield = '1' WHERE  userid = $user_id";
$qry = mysql_query($sql);
$res = mysql_assoc($qry)
if($res['newfield'] == 1){
     $sql = "UPDATE member_profile SET newfield = '0' WHERE user_id = $user_id";
     $upresult = mysql_query($sql);
if(mysql_affected_rows()== 1){
	//update successfull
}else{
	//update failed
}
}

 

I think this will get you closer, I did not test it but I tried to make sure the syntax was correct. 

 

I still make a lot of errors when writing code blocks and debug them constantly

 

Kansas

hi Kansas,

 

i have tried the code every way that i can think of but it will not replace the 1 with a 0

 

i get a blank screen with this in the code  $res = mysql_assoc($qry);

when i remove it places a 1 in newfield but won't replace it with 0

 

any ideas?

hi Kansas,

 

i have tried the code every way that i can think of but it will not replace the 1 with a 0

 

i get a blank screen with this in the code  $res = mysql_assoc($qry);

when i remove it places a 1 in newfield but won't replace it with 0

 

any ideas?

 

In the code I posted, I left out the semi colon in the code have you tried it adding a semi colon to terminate the line as you have posted it ?

 

$res = mysql_assoc($qry);
??

 

That syntax error could cause a blank screen. 

Another step in the debugging process I would take would be to do an

 

$sql = "SELECT * FROM member_profile SET newfield = '1' WHERE  userid = $user_id";
$qry = mysql_query($sql);
$res = mysql_assoc($qry);

echo '<pre>';
print_r ($res);
echo '</pre>';

if($res['newfield'] == 1){
     $sql = "UPDATE member_profile SET newfield = '0' WHERE user_id = $user_id";
     $upresult = mysql_query($sql);
if(mysql_affected_rows()== 1){
	//update successfull
}else{
//update failed
}
}

 

the print_r will allow you to see the array values in $res.

 

Kansas

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