ginerjm Posted April 14, 2011 Share Posted April 14, 2011 Been reading all afternoon. Here is where I am at with ONE big error. Everytime I call the function 'gn(n)' I get the message that "jsgolfers is undefined'. echo '<script type="text/javascript">'; echo 'var jsgolfers = new array["<?php echo join(":\", $golfers); ?>"];'; echo '</script>'; echo '<script type="text/javascript">'; echo 'function gn(str)'; echo '{'; echo 'alert(jsgolfers[$str]);'; echo '}'; echo '</script>'; First - the $golfers array is created and has values which I've displayed on my page I've had a lot of difficulty with the join function - the example I found on the web didn't work so I've whittled it down to what it is. Will appreciate any pointers one can provide. Supposedly this code will take a php-produced array var and build a JS array var for me to use in an onclick event on my page. Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/ Share on other sites More sharing options...
ginerjm Posted April 14, 2011 Author Share Posted April 14, 2011 And Yes - I have tried using a reference to $jsgolfers as well as just plain jsgolfers. Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201760 Share on other sites More sharing options...
ginerjm Posted April 14, 2011 Author Share Posted April 14, 2011 Eureka! After dumping my generated html page to an editor I saw that someone (php? js?) was inserting error messages (<a .....> even) into my html and that was causing a lot of trouble apparently. I massaged my code and this now does what I expect. echo '<script type="text/javascript">'; ?> var jsgolfers = ["<?php echo implode("\",\"",$golfers); ?>"]; <?php echo 'function gn(str)'; echo '{'; echo 'alert(jsgolfers[str]);'; echo '}'; echo '</script>'; Basically - the $golfers array is built using php and sql early in my script. then the js creates a global array and loads it from $golfers. Then my onclick attribute on a d/e field calls the function which properly displays the corresponding golfer depending upon the input I entered. Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201767 Share on other sites More sharing options...
gizmola Posted April 14, 2011 Share Posted April 14, 2011 As an aside, when I need to output js from php I will either include it, or use a Heredoc. The code you provided is not valid php, so I'm not confident in answering your question, when I don't know what the real code is. For example, you have echo statements (php) and then you start a new php section right in the middle of what is already php. That code would cause an error. Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201768 Share on other sites More sharing options...
ginerjm Posted April 14, 2011 Author Share Posted April 14, 2011 Lifted from examples on "helpful" web pages. I had to modify that just to get a response out of it - which took me hours! Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201770 Share on other sites More sharing options...
gizmola Posted April 14, 2011 Share Posted April 14, 2011 Here's a heredoc. Heredocs interpolate variables in the same way that using the double quotes does. $golfers = implode("\",\"",$golfers); $js =<br /> var jsgolfers = ["$golfers"];<br /> <br /> function gn(str)<br /> {<br /> alert(jsgolfers[str]);<br /> }<br /> JS; echo $js; Eliminates all the annoying quoting, and escaping etc. Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201771 Share on other sites More sharing options...
ginerjm Posted April 14, 2011 Author Share Posted April 14, 2011 MUCH better. Thanks! Quote Link to comment https://forums.phpfreaks.com/topic/233758-php-arrays-into-js/#findComment-1201788 Share on other sites More sharing options...
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