asmith6 Posted April 20, 2011 Share Posted April 20, 2011 I'm tired and just about given up. Can anybody help me? <?php $objConnect = mysql_connect("localhost","","root") or die(mysql_error()); $objDB = mysql_select_db("sdf"); $pic2 = "SELECT * FROM images"; if (!isset($_GET['Page'])) $_GET['Page']='0'; $pic1 = mysql_query($pic2); $Num_Rows = mysql_num_rows($pic1); $Per_Page = 16; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) {$Page=1;} $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) {$Num_Pages =1;} else if(($Num_Rows % $Per_Page)==0) {$Num_Pages =($Num_Rows/$Per_Page) ;} else {$Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages;} $pic2 .=" order by thumbnailID ASC LIMIT $Page_Start , $Per_Page"; $pic1 = mysql_query($pic2); $cell = 0; $link1 = "SELECT * FROM images"; $result_link1 = mysql_query($link1); $link = mysql_fetch_array($result_link1); $alt1 = "SELECT * FROM images"; $alt = mysql_fetch_array(mysql_query($alt1)); echo ' <div id="tablediv"> <table border="0" cellpadding="17" cellspacing="0" class="table"> <tr>'; while($pic = mysql_fetch_array($pic1)) { if($cell % 4 == 0) { echo '</tr><tr>'; } if($cell == 2) { echo ' <td> fillerspace </td>'; } elseif ($cell == 3) { echo ' <td> Fillerspace2 </td>'; } else { echo ' <td> <a href="/' . $link["link"] . '.php"> <div class="image"> <img src="https://s3.amazonaws.com/image/' . $pic["pic"] . '.png" alt="' . $alt["alt"] . '" height="200" width="200" /> </div> </a> </td>'; } $cell++; } echo '</tr></table></div>'; ?> Basically, there are a couple of faults with this code. I didn't include the pagination part, but there is, for simplicity. But right now, when I insert a new record such as this: INSERT INTO `images` VALUES (' ', 'blog', 'yo', '6', 'hello', '2011-02-15T07:24:17Z') The columns go in order of thumbnailID, folder, link, pic, alt, and time.^^^^^^^^ several problem arises. One, the new record is not displayed as the newest entry on my site. So the record is actually placed in one of the paginated pages. How can I reverse the order? The other thing is, it seems like my pic column is the only thing being understood. You see, when I inserted the above record, I checked my site and saw the pic 6, but the link wasn't 'yo', and the alt wasn't 'hello'. Why is that? By the way, my host is awfully terrible. Maybe it's just having a major delay in reading the link and alt? I don't know. That would be the only reasonable answer, unless my code is off. Thank you, and I'll check 10hours from now. Quote Link to comment https://forums.phpfreaks.com/topic/234230-my-image-gallery-code-isnt-working/ Share on other sites More sharing options...
spiderwell Posted April 20, 2011 Share Posted April 20, 2011 the first thing i spotted is you are listed by ASC, so you want to change it to DESC, this will put the new image at the top. there seems to be an awful lot of extra code that you dont really need. why is $pic2 and $link1 and $alt1 all the same SQL command? (well you add ordering and paging to $pic2 but this is the only recordset you need) give me a moment and Ill post a stripped out version for you Quote Link to comment https://forums.phpfreaks.com/topic/234230-my-image-gallery-code-isnt-working/#findComment-1203905 Share on other sites More sharing options...
spiderwell Posted April 20, 2011 Share Posted April 20, 2011 <?php $objConnect = mysql_connect("localhost","","root") or die(mysql_error()); $objDB = mysql_select_db("sdf"); $pic2 = "SELECT * FROM images"; if (!isset($_GET['Page'])) $_GET['Page']='0'; $pic1 = mysql_query($pic2); $Num_Rows = mysql_num_rows($pic1); $Per_Page = 16; // Per Page $Page = $_GET["Page"]; if(!$_GET["Page"]) {$Page=1;} $Prev_Page = $Page-1; $Next_Page = $Page+1; $Page_Start = (($Per_Page*$Page)-$Per_Page); if($Num_Rows<=$Per_Page) {$Num_Pages =1;} else if(($Num_Rows % $Per_Page)==0) {$Num_Pages =($Num_Rows/$Per_Page) ;} else {$Num_Pages =($Num_Rows/$Per_Page)+1; $Num_Pages = (int)$Num_Pages;} $pic2 .=" order by thumbnailID ASC LIMIT $Page_Start , $Per_Page"; $pic1 = mysql_query($pic2); $cell = 0; echo ' <div id="tablediv"> <table border="0" cellpadding="17" cellspacing="0" class="table"> <tr>'; while($pic = mysql_fetch_array($pic1)) { if($cell % 4 == 0) { echo '</tr><tr>'; } if($cell == 2) { echo ' <td> fillerspace </td>'; } elseif ($cell == 3) { echo ' <td> Fillerspace2 </td>'; } else { echo ' <td> <a href="/' . $pic["link"] . '.php"> <div class="image"> <img src="https://s3.amazonaws.com/image/' . $pic["pic"] . '.png" alt="' . $pic["alt"] . '" height="200" width="200" /> </div> </a> </td>'; } $cell++; } echo '</tr></table></div>'; ?> Quote Link to comment https://forums.phpfreaks.com/topic/234230-my-image-gallery-code-isnt-working/#findComment-1203911 Share on other sites More sharing options...
asmith6 Posted April 20, 2011 Author Share Posted April 20, 2011 Thanks man, can't believe I didn't notice the ASC before. Quote Link to comment https://forums.phpfreaks.com/topic/234230-my-image-gallery-code-isnt-working/#findComment-1204030 Share on other sites More sharing options...
KevinM1 Posted April 20, 2011 Share Posted April 20, 2011 Please place all of your code within tags in the future. Quote Link to comment https://forums.phpfreaks.com/topic/234230-my-image-gallery-code-isnt-working/#findComment-1204032 Share on other sites More sharing options...
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