Vel Posted May 10, 2011 Share Posted May 10, 2011 Hello all. I'm getting a syntax error that I don't understand. When the result is 0 it throws an error, but when the result is 1 it works perfectly fine. Can someone explain why? <?php //Check if character is in a fleet $_SESSION['charIsInFleet'] = FALSE; //Set fleet flag false $sqlLoadFleetNames = "SELECT * FROM `activefleets`"; //Set sql search $queryLoadFleetNames = mysql_query($sqlLoadFleetNames); //Set query $i = 0; while($row = mysql_fetch_array($queryLoadFleetNames)) { $fleetNames[$i] = $row['fleetName']; $i++; } $numberOfFleets = $i; for($i = 0; $i <= $numberOfFleets; $i++) { $fleetName = $fleetNames[$i]; $sqlSearchFleet = "SELECT * FROM `" . $fleetName . "` WHERE `charId` = '" . $charId . "'"; //Set sql search $querySearchFleet = mysql_query($sqlSearchFleet) or die('Error: ' . mysql_error()); $resultSearchFleet = mysql_num_rows($querySearchFleet); if($resultSearchFleet > 0) { $rowSearchFleet = mysql_fetch_array($querySearchFleet); $_SESSION['charIsInFleet'] = TRUE; $_SESSION['charFleetName'] = $fleetName; $_SESSION['charShipHull'] = $rowSearchFleet['shipHull']; $_SESSION['charShipType'] = $rowSearchFleet['shipType']; break; } } When it finds a person in a fleet then it works. When someone is not in an active fleet it throws the error: Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE charId = '90613880'' at line 1 Quote Link to comment https://forums.phpfreaks.com/topic/236030-mysql-syntax-error/ Share on other sites More sharing options...
Maq Posted May 10, 2011 Share Posted May 10, 2011 Echo out $sqlSearchFleet and paste the output. Quote Link to comment https://forums.phpfreaks.com/topic/236030-mysql-syntax-error/#findComment-1213422 Share on other sites More sharing options...
Vel Posted May 10, 2011 Author Share Posted May 10, 2011 It's now throwing up another error as well, which I've not seen before. I've included everything in the page. Notice: Undefined offset: 1 in /usr/home/nhrpgame/public_html/btl/includes/initiate.php on line 57 Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE charId = '90613880'' at line 1 sqlSearchFleet: SELECT * FROM WHERE charId = '90613880' It seems the table name isn't being loaded. But why does it work when a person is in a fleet? Line 57 is $fleetName = $fleetNames[$i]; btw. EDIT: That brings up another question. Why is it trying to search for number 1? There is only 1 fleet, so it should be 0. If I ignore the first row in the array (0) will that work? Nope, that just changes it to undefined offset 0. Is it because I add an extra i++ even when there is no more fleets and it's not hitting that when there is someone in the fleet. I need to change it to $numberOfFleets = $i-1. That was it. Solved. Either $numberOfFleets = $i-1 or use $i < $numberOfFleets instead of <=. It was trying to access a non-existent array. Quote Link to comment https://forums.phpfreaks.com/topic/236030-mysql-syntax-error/#findComment-1213434 Share on other sites More sharing options...
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