Preceded by newline?

[Undrium]

I have this:

 

#(?<=\n|^|\s|\()

 

I also want to squeeze in that it's okey if it is preceded by a newline, how do I write that?

[requinix]

If what's preceded by a newline? What you posted is just a fragment of a regular expression.

[Undrium]

Sorry I wasn't clear enough, I am writing an assertion and this is how far I have come. I want to preg_replace a word if it does have a whitespace, is the start of string or a newline is preceded. Problem is I do not know how to write newline in the assertion. I know that \s for instance means any whitespace so I have that sorted out.

[requinix]

Well, "whitespace" already includes newlines, so

(?

[Undrium]

It's not doing the trick, though. Sat some hours yesterday with this problem:

 

$s = preg_replace('#(?<=^|\s|\()(http://[^\s\)]+)#', '[url=$1]$1[/url]', $data); 

 

Everything works fine until a newline occurs, if the URL is located after a newline it won't activate. However if I make a space after the newline it will replace. Also it works if the URL is at the start of a string.

 

This will work:

 

Some text
http://www.address.com

 

This won't work:

 

 

Some text
http://www.address.com

 

[requinix]

Works fine for me.

echo preg_replace('#(?

What's the rest of your code?

[Undrium]

Yeah, you are right, it is working. I turned off all my other processing of the text and it turned out to be my antiinjectfunction screwing it up. Thanks for the second view.