Jump to content

Recommended Posts

You need to terminate the variable assignment with a semicolon before continuing on to echo anything. If you're trying to assign the value of $r['feedusername'] as well, you need the concatenation operator, not echo.

Link to comment
https://forums.phpfreaks.com/topic/238784-php-syntax-error/#findComment-1226953
Share on other sites

Because it's not?

 

You have two options - use double quotes and have the variable value automatically substituted for you, like:

 

$s = "<a href='../u/{$r['feedusername']}'>";

 

Or use single quotes and concatenation:

 

$s = '<a href="../u/' . $r['feedusername'] . '">';

Link to comment
https://forums.phpfreaks.com/topic/238784-php-syntax-error/#findComment-1226957
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.