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Easy PHP Question

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#1 holyearth

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Posted 14 October 2006 - 04:35 AM


#2 trq

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Posted 14 October 2006 - 05:08 AM

Post your code and tell us what part your stuck on.

#3 .josh

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Posted 14 October 2006 - 07:30 AM

...or go post in the freelance forum if you would rather someone do it for you.
Did I help you? Feeling generous? Buy me lunch! 
Please, take the time and do some research and find out how much it would have cost you to get your help from a decent paid-for source. A "roll-of-the-dice" freelancer will charge you $5-$15/hr. A decent entry level freelancer will charge you around $15-30/hr. A professional will charge you anywhere from $50-$100/hr. An agency will charge anywhere from $100-$250/hr. Think about all this when soliciting for help here. Think about how much money you are making from the work you are asking for help on. No, we do not expect you to pay for the help given here, but donating a few bucks is a fraction of the cost of what you would have paid, shows your appreciation, helps motivate people to keep offering help without the pricetag, and helps make this a higher quality free-help community :)

#4 extrovertive

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Posted 14 October 2006 - 09:14 AM

<form action="process.php" method="post" target="submit">
Starting Number: <input type="text" name="startnum" /><br />
Numbers: <input type="text" name="numbers" /><br />
<select name="updown">
	<option value="up">Increment</option>
	<option value="down">Decrement</option>
</select><br />
<input type="submit" name="submit" value="Submit" />

$startnum = $_POST['startnum']; //starting number
$numbers = $_POST['numbers']; //increment of
$updown = $_POST['updown']; //increasing or decreasing
$endnum = $startnum + $numbers; //ending number

$num_array = ($updown == "up") ? range($startnum, $endnum) : range($endnum, $startnum);

	foreach($num_array as $key=>$val)
	  $urlstring .= "n" . ($key+1) . "=" . $val . "&";
	$urlstring = "submit.php?" . substr($urlstring, 0, -1);

header("Location: $urlstring");

Whatever goes here...

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