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using include() within an echo as variable


leijae

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$desc = include($path/$file/descriptions.txt);
echo "<div class='sshot'><img src='$path/$file/screenshot.jpg' /><div class='randcont'> $desc </div>";

 

i've tried concatenation and:

 

echo "<div class='sshot'><img src='$path/$file/screenshot.jpg' /></div><div class='randcont'>";
include($path/$file/descriptions.txt);
echo "</div>";

 

errors:

 

Warning: Division by zero in C:\xampp\htdocs\project\include\vars.php on line 21

 

Notice: Use of undefined constant descriptions - assumed 'descriptions' in C:\xampp\htdocs\project\include\vars.php on line 21

 

Warning: Division by zero in C:\xampp\htdocs\project\include\vars.php on line 21

 

Notice: Use of undefined constant txt - assumed 'txt' in C:\xampp\htdocs\project\include\vars.php on line 21

 

Warning: include(txt) [function.include]: failed to open stream: No such file or directory in C:\xampp\htdocs\project\include\vars.php on line 21

 

Warning: include() [function.include]: Failed opening 'txt' for inclusion (include_path='.;C:\xampp\php\PEAR') in C:\xampp\htdocs\project\include\vars.php on line 21

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