Get part of a domain

[jarvis]

Hi,

I've the following URL

http://www.domain.com/category/projects/airports

 

How can I get projects from the URL?

 

I had something like:

$ref = $_SERVER["REQUEST_URI"];
$array = explode("/", $ref, 2);
echo $array[2];

Sadly it didn't work 

 

Anyone able to point me in the right direction?

 

TIA

[cssfreakie]

this maybe?

 

            $ref = 'http://www.domain.com/category/projects/airports';
            $array = explode("/", $ref);
            echo $array[4];

[jarvis]

Thanks cssfreakie, that put me in the right direction, I needed this:

$array = explode("/", $ref);            
echo $array[6];	

Thanks :-)

[Pikachu2000]

What you're asking makes no sense, at least not the way you're asking it. What problem are you trying to solve with this code?

[jarvis]

Thanks Pikachu2000  but I don't know how else to explain it.

 

I have this domain:

http://www.domain.com/category/projects/airports

 

I need to get the projects part of the domain from it. As this may change to something else, like:

http://www.domain.com/category/location/usa

 

So I can then use the code to get locations. Depending on whether it's location or projects, depends on what I then show on screen.

 

Does that help?

Thanks

[AbraCadaver]

echo basename(dirname($ref));