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Hello PHPers,

 

One more help I think may be wrong.  I currently have code as $_GET['width'] . "x" . $_GET['height'];.  This provides continually with 640 * 480. 

 

believe this to be incorrect as I do not think that everyones screen is set to this.  Neither is my screen resolution and is still capturing these figures.

 

Is there something wrong with the variable that should be changed so that it can pick up the visitors screen resolution.

Thank you kindly,

HJ

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https://forums.phpfreaks.com/topic/247238-screen-resolution-capture-from-visitors/
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OR

You could just pass the resolution from a Javascript page using $_GET which is less attractive but easier.

<?php

if( empty($_GET['w'] ))
{
?> 
<script type="text/javascript">
window.location.href = '1002.php?w=' + screen.width + '&h=' + screen.height;
</script>
<?php
}
else
{
	echo "Your screen resolution is set at ". $_GET['w']. " X " . $_GET['h'];
}
?>

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