So simple But i do not know Help please

[Mancent]

<?php
//ob_start();
include "../connect.php";
Header('Cache-Control: no-cache');
Header('Pragma: no-cache');




$UserId=$_POST['UserId'];
$UserId = stripslashes($UserId);
$UserId = mysql_real_escape_string($UserId);

$UserName=$_POST['UserName'];
$UserName = stripslashes($UserName);
$UserName = mysql_real_escape_string($UserName);

$UserFirstName=$_POST['UserFirstName']; 
$UserFirstName = stripslashes($UserFirstName);
$UserFirstName = mysql_real_escape_string($UserFirstName); 

$UserLastName=$_POST['UserLastName']; 
$UserLastName = stripslashes($UserLastName);
$UserLastName = mysql_real_escape_string($UserLastName);

$UserGender=$_POST['UserGender']; 
$UserGender = stripslashes($UserGender);
$UserGender = mysql_real_escape_string($UserGender);

$UserLink=$_POST['UserLink']; 
$UserLink = stripslashes($UserLink);
$UserLink = mysql_real_escape_string($UserLink);

$UserPicture=$_POST['UserPicture']; 
$UserPicture = stripslashes($UserPicture);
$UserPicture = mysql_real_escape_string($UserPicture);





$sql="SELECT * FROM Fb_Profile WHERE UserId='$UserId' and UserName ='$UserName' and UserFirstName ='$UserFirstName' and UserLastName ='$UserLastName' and UserGender ='$UserGender' and UserLink ='$UserLink' and UserPicture ='$UserPicture'";

$result=mysql_query($sql);

$count=mysql_num_rows($result);
//Lets add a first time active check 0 or 1 if 1 skip and check for update<br />
if($UserId == 'undefined')
{
return true;
}
if($count==1)
{

echo "&msgText=Facebook MySql Copy Successfully!\n";



return false;
}


else
{
echo "&msgText=Invalid Login!\n";
//THIS HERE IS WHAT I AM HAVING A PROBLEM WITH, IF STATEMENT STATING THAT IF $UserId IS EMPTY AND THE OTHER VARIABLES RETURN NOTHING BUT IF IS HAS A VALUE IT INSERTS
//IF(!empty $UserId)
$FB_Profile_Copy = mysql_query("INSERT INTO Fb_Profile(UserId,UserName,FirstName,LastName,Gender,Link,Picture) VALUES('$UserId','$UserName','$UserFirstName','$UserLastName','$UserGender','$UserLink','$UserPicture')");
$FB_BackGround_Copy = mysql_query("INSERT INTO Fb_BackGround(UserId) VALUES('$UserId')");
return false;
}
?>

[Adam]

Really..?

[Mancent]

Sorry thought php bbcode was what i should use.. HA HA my bad fixed

[Mancent]

//THIS HERE IS WHAT I AM HAVING A PROBLEM WITH, IF STATEMENT STATING THAT IF $UserId IS EMPTY AND THE OTHER VARIABLES RETURN NOTHING BUT IF IS HAS A VALUE IT INSERTS

//IF(!empty $UserId)

{

//something to do here!

}

 

 

 

[KevinM1]

 

The PHP manual is your friend: empty.  Note how the correct syntax is different than what you have.

 

Keep a bookmark to the manual.

[Mancent]

so this is correct

 

If(!empty() $UserId)

{

//so this says that if the variable is empty it will run this condition?

}

[gizmola]

No, it's a function that takes a parameter.  But the entire condition needs to be put inside parens:

 

if (!empty($UserId)) {
  // do whatever
}