preg_replace woes

[ianco]

Evening all,

 

I'm looking to use preg_replace to change:

 

{{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}}

 

into

 

<figure><img src='http://en.wikipedia.org/wiki/File:Wiki.png' alt='wikipedia logo' /><figcaption>This is the wikipedia logo</figcaption></figure>

 

for example

 

so far i have

 

	$befor = array(); 
$befor[1] = "/({{)(.*?)(|)/";
$befor[2] = "/(|)(.*?)(|)/";
$befor[3] = "/(|)(.*?)(}})/";


$aftr = array();
$aftr[1] = "<figure><img src='$1'";
$aftr[2] = " alt='$2' />";
$aftr[3] = "<figcaption>$3</figcaption></figure>";


$content = preg_replace($befor, $aftr, $content);	

 

I'm obviously way out because it's just spitting out

 

alt='' /> alt='<' /> alt='' /> alt='f' />...etc

 

can anyone help me out?

 

Many thanks

 

Ian

 

[Psycho]

<< Moved to Regex Forum >>

 

$input = "some text before {{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}} some text after";

$regex = "#{{([^|]*)\|\|([^|]*)\|\|([^|]*)}}#";
$replace = "<figure><img src='$1' alt='$2' /><figcaption>$3</figcaption></figure>";
$output = preg_replace($regex, $replace, $input);

echo $output;
//Output:
//some text before <figure><img src='http://en.wikipedia.org/wiki/File:Wiki.png' alt='wikipedia logo' /><figcaption>This is the wikipedia logo</figcaption></figure> some text after

[ianco]

That's much simpler,

 

Thanks a lot

 

Ian

[ianco]

I want to now reverse it. SO, I've got

 

$regex1 = '{{$1||$2||$3}}';								
$replace1 = '#<figure><img src="([^<]+)" alt="([^<]+)" /><figcaption>([^<]+)</figcaption></figure>#i';

$content = preg_replace($replace, $regex, $content);

 

but this isn't working. I must be near...

Any ideas?

 

Thanks

 

Ian

 

[Psycho]

That makes absolutely no sense. What is in "$content" and what are you trying to search for and what are you wanting to replace it with?

[ianco]

Sorry, I've just replaced input and output from the previous example above with content. Either way I want to reverse the first situation so that my HTML turns into short hand:

 

{{http://en.wikipedia.org/wiki/File:Wiki.png||wikipedia logo||This is the wikipedia logo}}

[Psycho]

That is a much, much different situation.

 

$regex = "#<figure><img src='([^']*)' alt='([^']*)' /><figcaption>([^']*)</figcaption></figure>#";
$replace = "{{$1||$2||$3}}";
$output = preg_replace($regex, $replace, $input);

[ianco]

for some reason

 

$replace = "{{$1||$2||$3}}";

 

is killing my script. I just get a blank page unless  I delete it.

 

Why would this be??

 

Ian

[requinix]

"{$" is interpreted as the start of a variable. Which, in this case, it is not. Thus PHP barfs.

 

Use single quotes or escape the $.

[ianco]

Hi Sorry to bang on about this but i'm still not having any luck with this.

 

$regex = "#<figure><img src='([^']*)' alt='([^']*)' /><figcaption>([^']*)</figcaption></figure>#";
$replace = "(($1**$2**$3))";
$pagecontent = preg_replace($regex, $replace, $pagecontent);

 

no curly brackets now and still won't preg_replace

 

any ideas?

 

Thanks folks

 

 

Ian

[Psycho]

Hi Sorry to bang on about this but i'm still not having any luck with this.

 

You were already given the solution by requinix:

Use single quotes or escape the $.

 

Use single quotes

$replace = '{{$1||$2||$3}}';

 

or escape the dollar sign

$replace = "{{\$1||\$2||\$3}}";

[ianco]

I played about with it a bit more and found that in the $regex line i needed \ (slash) before the apostrophe.

 

so, here it is. thanks guys

 

$regex = '#<figure><img src="([^\']*)" alt="([^\']*)" /><figcaption>([^\']*)</figcaption></figure>#';
$replace = '{{$1||$2||$3}}';
$pagecontent = preg_replace($regex, $replace, $pagecontent);

[Psycho]

I played about with it a bit more and found that in the $regex line i needed \ (slash) before the apostrophe.

 

Well, if you would have followed directions you wouldn't have had that problem. The regex I supplied was defined using double quotes around the string for a reason - so you wouldn't need to escape the single quotes inside the string.