dmirsch Posted October 26, 2011 Share Posted October 26, 2011 I am getting the following error: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /data/23/2/100/53/2263053/user/2487001/htdocs/centerstage/centertix-ticketsellers/knowledgebase-forms.php on line 37 Warning: Invalid argument supplied for foreach() in /data/23/2/100/53/2263053/user/2487001/htdocs/centerstage/centertix-ticketsellers/knowledgebase-forms.php on line 41 Here is my code: <?php @$DB = mysqli_connect($server,$username,$password,$database); if (mysqli_connect_errno()){ echo 'Cannot connect to database: ' . mysqli_connect_error(); } else { $Query = 'SELECT KBcategory.Category, KBcategory.SUBcategory, knowledgeBase.faqID, knowledgeBase.SubCategoryID, knowledgeBase.CreationDate, knowledgeBase.ModificationDate, knowledgeBase.HomePage, knowledgeBase.Author, knowledgeBase.Views, knowledgeBase.Item, knowledgeBase.Description, knowledgeBase.Attachment, knowledgeBase.Image FROM knowledgeBase LEFT JOIN KBcategory ON knowledgeBase.SubCategoryID = KBcategory.kbcatID WHERE KBcategory.Category = "Forms" ORDER BY KBcategory.Category, KBcategory.SUBcategory'; $Result = mysqli_query($DB,$Query); $subcats = mysql_fetch_array($Result); $NumResults = mysqli_num_rows($Result); foreach ($subcats as $key => $Row['SUBcategory']) { echo '<h1>'.$Row['SUBcategory']. '</h1>'; while ($Row = mysqli_fetch_assoc($Result)){ echo '<h2>'. $Row['Item'] . '</h2>'; //CODE REMOVED AS IT'S NOT NECESSARY FOR MY QUESTION echo $Row['Description']; echo '<hr /><hr />'; } } ?> What I would like is to have the first SUBcategory listing with all the pertinent Item/Description, then list the next SUBcategory with all the pertinent Item/Description, and so on... Where did I go wrong? Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/ Share on other sites More sharing options...
Pikachu2000 Posted October 26, 2011 Share Posted October 26, 2011 Off the bat, I'd say the query is failing. What does mysqli_error() show? Once that's cleared up, you can work on formatting the output. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282517 Share on other sites More sharing options...
dmirsch Posted October 26, 2011 Author Share Posted October 26, 2011 I know the query works, because I plug that right into my SQL in phpMyAdmin and it comes back with 7 results. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282528 Share on other sites More sharing options...
Pikachu2000 Posted October 26, 2011 Share Posted October 26, 2011 Just spotted the problem. You're mixing mysql and mysqli extension functions. They aren't interchangeable. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282539 Share on other sites More sharing options...
dmirsch Posted October 26, 2011 Author Share Posted October 26, 2011 OK, so I changed it all to mysqli functions, but it still does not help me to get what I originally wanted... I would like is to have the first SUBcategory listing with all the pertinent Item/Description, then list the next SUBcategory with all the pertinent Item/Description, and so on... It still lists it out as SUBcategory#1, Item/Description#A; then SUBcategory#1, Item/Description#B; then SUBcategory#1, Item/Description#C; then SUBcategory#2, Item/Description#A; then SUBcategory#2, Item/Description#B... What I want is SUBcategory#1, Item/Description#A, Item/Description#B, Item/Description#C; then SUBcategory#2, Item/Description#A, Item/Description#B... How do I get this to work? Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282542 Share on other sites More sharing options...
PFMaBiSmAd Posted October 26, 2011 Share Posted October 26, 2011 You would remember/detect when the subcategory changes and just output the heading when it does. See the $last_cat logic in the following similar thread - http://www.phpfreaks.com/forums/index.php?topic=342485.msg1615743#msg1615743 Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282546 Share on other sites More sharing options...
fenway Posted October 27, 2011 Share Posted October 27, 2011 Or, pre-process the results, and make a hash. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1282557 Share on other sites More sharing options...
polycap9 Posted October 31, 2011 Share Posted October 31, 2011 hey pikachu What do you mean by "They aren't interchangeable". Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1283649 Share on other sites More sharing options...
Pikachu2000 Posted October 31, 2011 Share Posted October 31, 2011 I mean you have to use the same extension for the whole process. You can't use mysqli_connect, then mysql_query with it. Basically, pick either mysql* or mysqli* and stick with it. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1283655 Share on other sites More sharing options...
dmirsch Posted November 23, 2011 Author Share Posted November 23, 2011 OK, I have three issues -- one is the same thing I have not yet been able to resolve: I need to list out EventTitle then have a sub-listing of each performance. Also for some reason I get "free event" for all EventTitles instead of for only those that are free. Lastly, my "at [time]" is not displaying. Here is my code: <?php @$DB = mysqli_connect('server','login','password','database'); if (mysqli_connect_errno()){ echo 'Cannot connect to database: ' . mysqli_connect_error(); } else { $TheatreQuery = "SELECT Performance.PerfType, Performance.startDateTime, Events.EventTitle, Events.thumb,Events.ShoWareEventLink, If(Events.startDATE<Now()-INTERVAL 1 DAY,'over','running') AS enddateOver, Events.Theatre, Events.FreeEvents, Promoters.Presenter, Promoters.website, venues.VenueName, venues.VenueSite, venues.Ranking FROM ((Events LEFT JOIN Performance ON Events.EventID = Performance.EventID) LEFT JOIN Promoters ON Events.PromoterCode = Promoters.PromoterCode) LEFT JOIN venues ON Performance.VenueCode = venues.VenueCode WHERE Events.Theatre=TRUE AND Performance.PerfType='Public Event' AND Events.endDATE>Now()-INTERVAL 1 DAY AND Events.endDATE<=Now()+INTERVAL 31 DAY AND Performance.startDateTime>=Now()-INTERVAL 1 DAY ORDER BY Events.EventTitle, Performance.startDateTime"; $TheatreResult = mysqli_query($DB,$TheatreQuery); $TheatreNumResults = mysqli_num_rows($TheatreResult); <p bgcolor="#BDA45E" class="categoryHeader">Theatre</p><?php while ($Row = mysqli_fetch_assoc($TheatreResult)){ if ($Row['Theatre']==TRUE){ //THEATER echo '<p>'; if($Row['Ranking']<10){ echo '<img src="http://www.myalaskacenter.com/images/logos/acpa/weblogo-small_nowords.jpg" alt="Alaska Center for the Performing Arts" width="80" height="80" border="0" align="right">'; } if ($Row['FreeEvents']=TRUE){ echo '<img src="http://www.myalaskacenter.com/images/free.gif" alt="Free Event" width="67" height="64" align="right" border="0">'; } echo '<a href="' . $Row['ShoWareEventLink'] . '"><img src="https://alaskapac.centertix.net/UPLImage/' . $Row['thumb'] . '" alt="' . $Row['EventTitle'] . '" title="' . $Row['EventTitle'] . '" align="left" border="0" style="padding-right:5px"><span class="Heading3_blue"><br />' . $Row['EventTitle'] . '</span>'; echo '<br />Presented by <a href="' . $Row['website'] .'" target="_blank">' . $Row['Presenter'] . '</a><br />'; echo date("l, F j, Y", strtotime($Row['startDateTime']). ' at ' . date("g:i a", strtotime($Row['startDateTime']))).' - <a href="'.$Row['VenueSite'].'" target="_blank">'.$Row['VenueName'].'</a>'; echo '<br /><br /></p><hr>'; }} mysqli_free_result($TheatreResult); mysqli_close($DB); } ?> Please help! If you would like to see my working webpage you can find it at http://www.myalaskacenter.com/centermail/_upcomingevents.php Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1290845 Share on other sites More sharing options...
PFMaBiSmAd Posted November 23, 2011 Share Posted November 23, 2011 I need to list out EventTitle then have a sub-listing of each performance. Someone (me) posted a link to a thread showing how to do that (you remember the title and output a new heading when the title changes.) I get "free event" for all EventTitles An equal comparison is two == (an assignment is one = sign) You have an if() statement using one = sign, instead of two ==. my "at [time]" is not displaying What format is your startDateTime value? Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1290846 Share on other sites More sharing options...
dmirsch Posted November 23, 2011 Author Share Posted November 23, 2011 The startDateTime is formatted datetime (2011-11-25 19:00:00). The double equals does not seem to work for the FreeEvents item -- it lists every performance as a Free Event even if the value is FALSE. I will try the suggestion for the sub-listing that you gave. It has been a while since I posted this and when I read your response I was stuck on "Category" but now that I reread it I think I can apply what you suggested for the EventTitle. Thanks for your quick reply PFMaBiSmAd...hopefully these answers will help you help me better! Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1290847 Share on other sites More sharing options...
dmirsch Posted November 24, 2011 Author Share Posted November 24, 2011 Here's how I tried the coding: <p class="categoryHeader">Theatre</p><?php $last_eventtitle = NULL; // remember the last EventTitle while ($Row = mysqli_fetch_assoc($TheatreResult)){ $eventtitle = $Row['EventTitle']; if($last_eventtitle != $eventtitle){ // a new or the first EventTitle was found echo '<p>'; if($Row['Ranking']<10){ echo '<img src="http://www.myalaskacenter.com/images/logos/acpa/weblogo-small_nowords.jpg" alt="Alaska Center for the Performing Arts" width="80" height="80" border="0" align="right">'; } if ($Row['FreeEvents']==TRUE){ echo '<img src="http://www.myalaskacenter.com/images/free.gif" alt="Free Event" width="67" height="64" align="right" border="0">'; } echo '<a href="' . $Row['ShoWareEventLink'] . '"><img src="https://alaskapac.centertix.net/UPLImage/' . $Row['thumb'] . '" alt="' . $Row['EventTitle'] . '" title="' . $Row['EventTitle'] . '" align="left" border="0" style="padding-right:5px"><span class="Heading3_blue"><br />' . $Row['EventTitle'] . '</span>'; echo '<br />Presented by <a href="' . $Row['website'] .'" target="_blank">' . $Row['Presenter'] . '</a><br />'; if($last_eventtitle != NULL){ // not the first EventTitle, close out the previous section echo '<br />'.date("l, F j, Y", strtotime($Row['startDateTime']). ' at ' . date("g:i a", strtotime($Row['startDateTime']))).' - <a href="'.$Row['VenueSite'].'" target="_blank">'.$Row['VenueName'].'</a>'; } $last_eventtitle = $eventtitle; // save the new EventTitle // output the heading/start a new section echo '<br />'.date("l, F j, Y", strtotime($Row['startDateTime']). ' at ' . date("g:i a", strtotime($Row['startDateTime']))).' - <a href="'.$Row['VenueSite'].'" target="_blank">'.$Row['VenueName'].'</a>'; echo '<br /><br /></p><hr>'; } } ?> Now it does not list the performances correctly; although it DOES list just one event regardless of the number of performances -- so almost there. See webpage http://www.myalaskacenter.com/centermail/_upcomingevents.php. For example, Anchorage Youth Symphony only has one performance, but it lists 2; while The Nutcracker Ballet has six performances, but it lists only 2. And since I am still not getting the times in there, I'm not sure if it's listing the same performance twice or not. What am I doing wrong still? Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1290858 Share on other sites More sharing options...
PFMaBiSmAd Posted November 25, 2011 Share Posted November 25, 2011 Ummm. That's not equivalent to the logic that was given. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1291045 Share on other sites More sharing options...
fenway Posted November 25, 2011 Share Posted November 25, 2011 Also, we're now down to a pure php logic issue, not MySQL. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1291115 Share on other sites More sharing options...
dmirsch Posted November 26, 2011 Author Share Posted November 26, 2011 OK, I'll move this to PHP Forum then. Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1291423 Share on other sites More sharing options...
dmirsch Posted November 26, 2011 Author Share Posted November 26, 2011 moved to PHP Forum: http://www.phpfreaks.com/forums/index.php?topic=348604.0 Link to comment https://forums.phpfreaks.com/topic/249870-create-an-array-from-a-mysql-database/#findComment-1291426 Share on other sites More sharing options...
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