Simple strtotime() converstion with offset

[Shadowing]

Trying to convert my UNIX time into a users offset time. Gathering the users offset in this format -1200

 

so I was reading about the date function in the PHP manual. but all the examples are using location words as offsets

 

string date ( string $format [, int $timestamp = time() ] )

 

cant I just do $time = strtotime('-1200')

 

I know i saw the conversion for this somewhere in this forum few days back but cant find it now.

Im only wanting to convert the time when displaying it to the user only.

[kicken]

Just add/subtract the users offset from your timestamp.  You'd probably want to set your script to use the UTC timezone by default.

 

 

date_default_timezone_set('UTC');
date('m/d/Y', time()-1200);

 

[Shadowing]

ok want to make sure I understand this right

since my server is -6 i cant use my user inputed offset cause it would be going against my -6

so i have to set it to UTC which is 0. so when someone has -12 it will be really -12 when comparing it to time().

 

when I do date_default_timezone_set('UTC');

does that change the server time to UTC always? or is that only for that script that is currently running

 

I read someone in the forum where someone couldnt use the date_default_timezone_set('UTC'); cause it was dissallowed on the server. right now im using local host but will upload to a live host one day and id hate to be using something that wont work on a live server

[kicken]

date_default_timezone_set affects only that script.  If you wanted to affect every php script you would have to set the timezone in the php.ini file.  The server's configured timezone is only used as a last resort.  The latest PHP versions will complain with a warning if you don't set the timezone explicitly either via the php.ini setting or the date_default_timezone_set function.

 

[Shadowing]

thanks kicken big help

is this how I do hour minute and second too?

 

date('m/d/Y/H:i:s', time()-1200);

 

also can I turn this as a variable like this

 

$timezone = date('m/d/Y/H:i:s', time()-1200);

 

and then echo it

 

echo "This is your time $timezone";

 

am I doing this right?

[shankarganesh]

Hi,

 

Use this to reduce the hours and minutes,

 

$unix_time = strtotime('January 1 2010 '.$time); // create a unix timestamp

echo date( "H:i", strtotime('-30 minutes', $unix_time) );

 

[Shadowing]

This isnt working for me for some reason

its almost 7 hours off

and the minutes are like 5 minutes off

 

 

date_default_timezone_set('UTC');

 

$new = date('m/d/Y/H:i:s', time()-0600);

 

echo $new;

 

 

 

and if I only do this "with out the UTC set" its not even giving me my own time. 10 hours off

 

$new = date('m/d/Y/H:i:s', time());

 

echo $new;

[Shadowing]

Alright I found out whats happending. i was wrong. This works fine its showing GMT time

 

date_default_timezone_set('UTC');

$new = date('m/d/Y/H:i:s', time());

 

 

but when I add this it doesnt work. it subtracts 6 minutes and not 6 hours

 

$new = date('m/d/Y/H:i:s', time()-0600);

 

 

anyone know what im doing wrong here?

[Shadowing]

Alright I found something that works

apparently using time doesnt work had to replace it with strotime.

will daylight saving time get adjusted according for this?

 

date_default_timezone_set('UTC');

 

$new = date('m/d/Y/H:i:s', strtotime("-0600"));

 

echo $new;

[kicken]

but when I add this it doesnt work. it subtracts 6 minutes and not 6 hours

 

The return value of time() is in seconds.  Thus, your offset needs to be in number of seconds as well.  Just use a little math to turn your 6 hours into seconds.

 

Also, prefixing a number with  a 0 causes it to be interpreted as an octal value which is not what you want.  Remove the leading zero prefix.

[Shadowing]

thanks alot Kicken i got it working

 

but now I have a snytax issue when inserting it the seconds into this

 

$new = date('m/d/Y/H:i:s', time()$send1['time_offset']);

 

how did you solve that?

 

 

[Shadowing]

ahh I figured it out i had to add a + sign

 

$new = date('m/d/Y/H:i:s', time()+$send1['time_offset']);

 

[Shadowing]

Hey Kicken how do you add a variable in to offset the variable

 

$recieved

 

$recieved is a stored Unix time in mysql that i want to add the offset to

 

 <?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?> 

[kicken]

Just replace time() with the variable.

$offset = date('m/d/Y/H:i:s', $received+$send1['time_offset']);

[Shadowing]

thanks for the responce

 

yah i tried that gives me the wrong time. its 6 hours off which is exactly waht the offset is

hmm so its not addig the time offset in.

so maybe the + is wrong

[Shadowing]

is there a way to just make time function into my variable?

 

so when I use time it equals the variable

 

tried alot of combinations with changing the + with stuff and using ()

 

 

[Shadowing]

I came up with a solution maybe

since its not adding in  the offset. i could apply the offset first and then format it

but my $time variable isnt doing the offset

 

 <?php                                                 $recieved = $row['time'];
		                       $time = ($recieved + $send1['time_offset']);

date_default_timezone_set('UTC');

$offset = date('m/d/Y/H:i:s', $time);  ?> 

[Shadowing]

I got the code to work in my last reply

 

what was wrong was $send1 was suppose to be $take1 lol.

 

but this code out puts 12/31/1969/18:00:00

 

 <?php $offset = date('m/d/Y/H:i:s', $received+$take1['time_offset']); ?>