number_format

[dudejma]

Okay, I've read the manual on number_format and I'm not sure if I'm just not grasping it or I'm missing something but I've found out that when I use number format, it only gives me one digit. Like this:

 

I have my code:

$newPay = number_format($oldPay + $distance * .40, 2);

.

 

I've echoed out $oldPay and it gives the correct number because it comes directly from a database. When I echo out $newPay, I get the same value as $oldPay. Whenever I take away number_format, it still does the same thing. Obviously, I'm pretty new to PHP coding and not very advanced but I'm just not sure what I'm missing. Any help? Thanks.

[requinix]

number_format() doesn't quite do what you're expecting. Try round instead.

[ngreenwood6]

number_format() doesn't quite do what you're expecting. Try round instead.

 

He is correct in saying number_format doesn't quite do what youre expecting. It will only keep the decimal points if there are more than two it will limit them to two places. A solution for you would be:

 

$newPay = round($oldPay + $distance * .40, 2);

[dudejma]

It still gives me the same format.

 

This is what the code is now:

 

$newPay = round($oldPay + $distance * .40, 2);

 

$oldPay = 1,313.40

$distance = 3281

$newPay = 1313.4

[ngreenwood6]

try this then :

 

$newPay = number_format($oldPay + $distance * .40, 2);
$newPay = sprintf("%01.2f", $newPay);

[dudejma]

$newPay = 1.00

[ngreenwood6]

That is what you wanted correct?

[dudejma]

No, I want it to take $oldPay or the amount the pilot already has, and add the $newPay or the amount given for completion of the flight.

[dudejma]

I figured it out. I guess the server side gets confused when it takes a decimal already formatted with number_format directly from the database. Thanks for the help guys!