Form and hidden textfields

[Niixie]

Hey all, i have a little problem.

 

I have a form, and when submitting, i need to use the ID that i put in the $_GET array earlier.

 

When you're entering my site, and clicks a certain link, the $_GET will store show=1, and when you're submitting the form on the page, the value of 'show' is needed on the redirect page.. I thought that it would be smart to transfer it with a hidden textfield, but somehow it fails?

 

<form id="comment-form" action="comment_profile.php" method="POST">
                                    <fieldset>
                                        <div class="field">
                                            <textarea name="comment-field" rows="2" cols="66"></textarea>
                                            <input type="hidden" name="pofileid-field" value="<?php echo $_GET['show']; ?>" /> // <--- Here is the hidden field.
                                            <input type="submit" name="submit-field" class="submit" value=""/><i> (HTML tags kan bruges)</i>
                                        </div>
                                    </fieldset>
                                </form>

 

Above you can see a piece of my code, and i marked the hidden field aswell.

What i do not understand is, why isn't the hidden fields value return the value of show when i check in comment_profile.php, as that is where it returns?

 

Thanks in advance

-Niixie

[litebearer]

when you view the source in your browser. is the correct value on the hidden field?

[Niixie]

Yes, the value from 'show' is '1', but no value is returned into the hidden field.

[litebearer]

please show the code where you are retrieving the hidden field

[RobertP]

Not sure how your code is formatted because i see ""// <--- Here is the hidden field."" and that is a php comment lol

but your code looks like it is written in html

 

<?php

echo '<form id="comment-form" action="comment_profile.php" method="POST">
<fieldset>
<div class="field">
<textarea name="comment-field" rows="2" cols="66"></textarea>
<input type="hidden" name="pofileid-field" value="'.((array_key_exists('show',$_GET))?$_GET['show']:null).'" />
<input type="submit" name="submit-field" class="submit" value=""/><i> (HTML tags kan bruges)</i>
</div>
</fieldset>
</form>';

?>

[Niixie]

I added the "// <--" manually when i copied it to here.

 

Can you explain what you are doing there?

 

EDIT:

I found a way myself, thank you very much for helping me anyways!

[RobertP]

((array_key_exists('show',$_GET))?$_GET['show']:null)

 

if show is set in $_GET, then it will return the value, it if is not set, then it will return null.

 

will not display a notice error

[litebearer]

If show=1, when OP views source, the value is being set properly (per his comment that GET was 1); therefore, we NEED to see the code that is attempting to retrieve the hidden field.