gender not working

[Monkuar]

$user['gender'] = ($user['gender'] == 1) ? 'Male' : '';
	$user['gender'] = ($user['gender'] == 2) ? 'Female' : '';
	$user['gender'] = ($user['gender'] == 3) ? 'Hermaphrodite' : '';

 

I echo out $user['gender'] and it doesn't show the values i put in the terny operator, but if I delete all that, and echo it out it echo's out "1" which is what I have selected, any idea?

 

do i have to use variables other than the mysql $user['gender'] ?

[Monkuar]

blah i fixed it

 

if ($user['gender'] == 1){
	$g = 'Male';
	}else if ($user['gender'] == 2){
	$g = 'Female';
	}else if ($user['gender'] == 3){
	$g = 'Hermaphrodite';
	}

srry

[Pikachu2000]

Or a more compact way to do it, sans conditionals.

 

$genders = array(1=> 'Male', 'Female', 'Hermaphrodite');
$g = $genders[$user['gender']];

[Monkuar]

  Quote

Or a more compact way to do it, sans conditionals.

 

$genders = array(1=> 'Male', 'Female', 'Hermaphrodite');
$g = $genders[$user['gender']];

 

WHOA

 

now that is sexy

 

ima use that, lol thank you