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Do anyone know how i can put the html tags in the same line as the other html tags?

 

Here's an example:

 

Images | Link | Delete | Enabled

 

 

On my code, it break the tags to the new line without put on the same line as the other tags.

 

 

Here's the code:

 

[code]<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'myusername');
    define('DB_PASSWORD', 'mypass');
    define('DB_DATABASE', 'mydbtable');

    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {
  die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }

    $username = clean($_GET['user']);
    $password = clean($_GET['pass']);
    if($username == '') {
  $errmsg_arr[] = 'username ID missing';
  $errflag = true;
    }
    if($password == '') {
  $errmsg_arr[] = 'PASSWORD ID missing';
  $errflag = true;
    }

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
  $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password'";
  $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error());

if(mysql_num_rows($result) > 0) {
  $qrytable1="SELECT images, id, public FROM members WHERE username='$username'";
  $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());

  while ($row = mysql_fetch_array($result1)) {  
  echo '<p id="images"> <a href="images.php?id='.$row['id'].'">Images</a></td> | <a href="http://' .  $row["links"] . '">Link</a> </td> | <a href="delete.php?id='.$row['id'].'">Delete</a> </td> |  <p> <p id="test">'.$row['Public'].'</td>'';
  }
}
}
?>

[/code]

Yes, because that's what paragraph tags are supposed to do. They start a new paragraph.

 

i don't want a new paragraph in the same line as the other tags. Do you know how to put that tags of <p id="test">'.$row['Public'].' in the same line as the other tags?

 

if so plz can you post an example code.

Try this...

<?php
session_start();
define('DB_HOST', 'localhost');
define('DB_USER', 'myusername');
define('DB_PASSWORD', 'mypass');
define('DB_DATABASE', 'mydbtable');

$errmsg_arr = array();
$errflag = false;

$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {die('Failed to connect to server: ' . mysql_error());}
$db = mysql_select_db(DB_DATABASE);
if(!$db) { die("Unable to select database"); }
function clean($var){
return mysql_real_escape_string(strip_tags($var));
}
$username = clean($_GET['user']);
$password = clean($_GET['pass']);
if($username == '') {
  $errmsg_arr[] = 'username ID missing';
  $errflag = true;
}
if($password == '') {
$errmsg_arr[] = 'PASSWORD ID missing';
$errflag = true;
}

if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
echo implode('<br />',$errmsg_arr);
}else{
  $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password'";
  $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error());
if(mysql_num_rows($result) > 0) {
  $qrytable1="SELECT images, id, public FROM members WHERE username='$username'";
  $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());
	?>
	<table>
	<?PHP
	while ($row = mysql_fetch_array($result1)) {
		?>
			<tr>
					<td><a href="images.php?id="<?PHP echo $row['id']; ?>">Images</a></td>
					<td> | </td>
					<td><a href="http://<?PHP echo $row['links']; ?>">Link</a></td>
					<td> | </td>
					<td><a href="delete.php?id="<?PHP echo $row['id']; ?>">Delete</a></td>
					<td> | </td>
					<td><?PHP echo $row['Public']; ?></td>
			</tr>
		<?PHP
  	}
}
}
?>

 

I don't like that idea and this isn't what i want, i still want to use the code like this:

 

  echo '<p id="images"> <a href="images.php?id='.$row['id'].'">Images</a></td> | <a href="http://' .  $row["links"] . '">Link</a> </td> | <a href="delete.php?id='.$row['id'].'">Delete</a> </td> |  <p> <p id="test">'.$row['Public'].'</td>'';

 

I can't find out how to use the code to allow to use in each paragragh.

 

You can see what my data is showing on my php at the moment.

my data 1 |

Images | Link | Delete |

Enabled

my data 2 |

Images | Link | Delete |

Disabled

 

I want something to be shown on my php like this:

 

my data 1 | Images | Link | Delete | Enabled

my data 2 | Images | Link | Delete | Disabled

 

 

Any idea how i can do this?

Yes, because that's what paragraph tags are supposed to do. They start a new paragraph.

 

i don't want a new paragraph in the same line as the other tags. Do you know how to put that tags of <p id="test">'.$row['Public'].' in the same line as the other tags?

 

if so please can you post an example code.

 

If you don't want a new paragraph, what do you think might be the solution? Not using a paragraph tag, perhaps?

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