extract ID from url

[devWhiz]

how can I use preg_match to take aHjpOzsQ9YI out of www.youtube.com/watch?v=aHjpOzsQ9YI, I am still unfamiliar with regex, I've been writing php for alomost 4 years now and still don't know regex lol

 

Any help is appreciated.. Thanks

 

-CLUEL3SS

[requinix]

parse_url followed by parse_str. No regex needed.

[MarPlo]

Hi,

Try this code:

$url = 'www.youtube.com/watch?v=aHjpOzsQ9YI';
preg_match('/v=([a-z0-9]+)$/i', $url, $mc);
echo $mc[1];      // aHjpOzsQ9YI

[The Little Guy]

Hi,

Try this code:

$url = 'www.youtube.com/watch?v=aHjpOzsQ9YI';
preg_match('/v=([a-z0-9]+)$/i', $url, $mc);
echo $mc[1];      // aHjpOzsQ9YI

 

That won't always work, youtube uses other characters as well.

 

as requinix said do this:

$url = "www.youtube.com/watch?v=aHjpOzsQ9YI";
$pu = parse_url($url);
// php 5.4: $query = parse_url($url)["query"];
// other:
$query = $pu["query"];
$parameters = parse_str($query);
print_r($parameters);

[.josh]

TLG parse_url() accepts an optional 2nd argument to only return the portion you want.  Also, parse_str() returns void.  You have to specify the array as the 2nd argument.

 

url = "www.youtube.com/watch?v=aHjpOzsQ9YI";
$query = parse_url($url,PHP_URL_QUERY);
parse_str($query,$params);
echo $params['v'];