thara Posted June 25, 2012 Share Posted June 25, 2012 hi.. everyone.. This is a sql query problem that I have uncounted and have been in the same script for hours. But Still I couldn't get it to work. I need to get a image from database and its type should be one of a value from my $designation array. The query should check $designation array's value with database and if its match with one of a value in database then query can retrieve one row. This is my designation array. its value I use for image type in my db. $designation = array ( 'Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master'); My problem is how can I check these value exit in my table and how can I make a query for this. In query where condition is confusing to me... any comments are greatly appreciated. Thank you.. Quote Link to comment Share on other sites More sharing options...
Barand Posted June 25, 2012 Share Posted June 25, 2012 SELECT .... FROM mytablename WHERE somecolumn IN ( 'Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master') Quote Link to comment Share on other sites More sharing options...
Maq Posted June 25, 2012 Share Posted June 25, 2012 Going off Barand's example, with implode and a bit of string manipulation you can do: $designation = array ( 'Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master'); $sql = "SELECT .... FROM mytablename WHERE somecolumn IN('" . str_replace(',', '\', \'', implode(',', $designation)) . "')"; echo $sql; Output: SELECT .... FROM mytablename WHERE somecolumn IN('Managing Director', 'Manager', 'Director', 'The Principal', 'Deputy Principal', 'Proprietor', 'Assistant Manager', 'Head Master') EDIT: This is probably easier to read (replaced single quotes in function with double quotes): $sql = "SELECT .... FROM mytablename WHERE somecolumn IN('" . str_replace(",", "', '", implode(",", $designation)) . "')"; Quote Link to comment Share on other sites More sharing options...
Psycho Posted June 25, 2012 Share Posted June 25, 2012 I'm curious. If you have a defined list of image_types then would you have records in your image table that do not have one of those defined types? Or, are the types in the array a subset of all the types (that would make sense)? Also, having a hard-coded array of types will make any changes much harder to implement and it will have a greater potential for bugs since a single typo in one type can go unnoticed unless you did testing for each and every type. A better solution, IMHO, is to have a separate table for the types and then use the id for those types in your current table. Assuming the list above is only a subset of all the types that you want to use for that particular query, the types table might need a field to identify that subset. Here's an example id | type | admin 1 Managing Director 1 2 Manager 1 3 Director 1 4 The Principal 1 5 Teacher 0 6 Custodian 0 Then using the same type of logic Barand provided you can simplify things and, more importantly, you can add/delete types without any changes needed to the core code SELECT .... FROM mytablename WHERE type IN (SELECT id FROM types WHERE admin=1) Quote Link to comment Share on other sites More sharing options...
thara Posted June 26, 2012 Author Share Posted June 26, 2012 Psycho's idea was very imported for me do my job. In common, Thanks for all 3 replies. Its greatly appreciated. Quote Link to comment Share on other sites More sharing options...
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