<?php if ($_POST['Afloop_dag'] == "1") { echo "selected"; } ?>

[stijn0713]

I thought i add this piece of code:

<?php if ($_POST['Afloop_dag'] == "1") { echo "selected"; } ?>

in my options, like:

 

<option value="1" <?php if ($_POST['Afloop_dag'] == "1") { echo "selected"; } ?>>1</option>.

 

However, now it says that Afloop_dag index is undefined. However, i used this before in a signup code and it worked. why does the index need to be defined? im using it in a if statement

[NLT]

Use isset to check if it isn't empty first.

 

<?PHP
if(isset($_POST['Afloop_dag']) && $_POST['Afloop_dag'] == 1)
{
echo "selected"; 
}
?>

[ManiacDan]

That's a standard error message, your code may not have had error reporting turned on before.

 

A more correct version is:

 

<?php if ( isset( $_POST['Afloop_dag'] ) && $_POST['Afloop_dag'] == "1") { echo "selected"; } ?>

-Dan

[stijn0713]

gracias, thought so!

[premiso]

Use isset to check if it isn't empty first.

 

I just felt like nit picking, if you want to check if it is not empty, use empty which will do an is set check as well. However, if you want to know if the variable has been previously set, and do not care if it is empty, false, null etc or not isset is the way to go.

[xyph]

Use isset to check if it isn't empty first.

 

I just felt like nit picking, if you want to check if it is not empty, use empty which will do an is set check as well. However, if you want to know if the variable has been previously set, and do not care if it is empty, false, null etc or not isset is the way to go.

 

More nitpicking, isset will return FALSE if it's argument evaluates to NULL