Why does php date do this? most annoying thing ever..

[Monkuar]

$timestamp = time();
$date_end = strtotime("+2 days",$timestamp);

 

 

 

Okay so I do +2days right?

 

Then in database it shows:

 

date_end -> 1346472794

 

 

2 days 24 hours 60 min 58 seconds

 

 

Why in the hell, does it add 24hours + 60minutes + 1minute?

 

It's supposed to be for 2 DAYS, so the remaining time should be 1day 24hours 59 minutes 59 seconds, why the hell does it add that extra time? It's so annoying.

 

It does the same crap let's say if I add +90 days:

 

 

3 month 4 week 1 day 2 hours 24 min

why the hell does it add a whole nother month and 1 day 2hours 24minute? Makes absolutely no sense, last time I checked 3 months was 90 days, not 3 months 4weeks 1 day 2 hours 24 minutes?

 

 

This is the php code to xfer that timestamp that I make into the time remaining:

 

 

function  timeAgo2($timestamp, $granularity=5, $format='d:H:i:s'){
        $difference = $timestamp;
        if($difference < 0) return '0 seconds ago';
        elseif($difference < 8640000){
                   $periods = array('month' => 2630880, 'week' => 604800,'day' => 86400,'hours' => 3600,'min' => 60,'seconds' => 1);
                $output = '';
                foreach($periods as $key => $value){
                        if($difference >= $value){
                                $time = round($difference / $value);
                                $difference %= $value;
                                $output .= ($output ? ' ' : '').$time.' ';
                                $output .= (($time > 1 && $key == 'day') ? $key.'s' : $key);
                                $granularity--;
                        }
                        if($granularity == 0) break;
                }
                return ($output ? $output : '0 seconds').'';
        }
        else return date($format, $timestamp);
}

 

If anyone could please help, much appreciated...

 

 

 

[Pikachu2000]

date() isn't doing anything wrong. Your function is. And 3 months isn't necessarily 90 days.

 

<?php
$date_end = strtotime("+2 days", time() );
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS: 0 Years, 2 Days, 0 Hours, 0 Minutes, 0 Seconds

 

$date_end = strtotime("+90 days", time() );

$sec = $date_end - time();
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS: 0 Years, 90 Days, 0 Hours, 0 Minutes, 0 Seconds

 

$date_end = strtotime("+90 days", time() );

$sec = $date_end - time();
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS 0 Years, 92 Days, 1 Hours, 0 Minutes, 0 Seconds

[Monkuar]

date() isn't doing anything wrong. Your function is. And 3 months isn't necessarily 90 days.

 

<?php
$seconds Sec(s)<br>";
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS: 0 Years, 2 Days, 0 Hours, 0 Minutes, 0 Seconds

 

$date_end = strtotime("+90 days", time() );

$sec = $date_end - time();
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS: 0 Years, 90 Days, 0 Hours, 0 Minutes, 0 Seconds

 

$date_end = strtotime("+90 days", time() );

$sec = $date_end - time();
echo intval( $sec / 31536000 ) === 1 ? intval( $sec / 31536000 ) . ' Year, ' : intval( $sec / 31536000 ) . ' Years, ';
echo
intval( ($sec % 31536000) / 86400 ) . ' Days, ' .
intval( ($sec % 86400) / 3600 ) . ' Hours, ' .
intval( ($sec % 3600) / 60 ) . ' Minutes, ' .
intval( $sec % 60 ) . ' Seconds';

// RETURNS 0 Years, 92 Days, 1 Hours, 0 Minutes, 0 Seconds

 

solved, im not going to us that stupid ass function, im just going to use your simple echo intval stuff, works fine.

 

thanks pikachu.