ricky spires Posted September 4, 2012 Share Posted September 4, 2012 hello. how do i get how many 30's there are in x amount and then strip the remainder in 29 there is 0 in 59 there is 1 Quote Link to comment Share on other sites More sharing options...
MMDE Posted September 4, 2012 Share Posted September 4, 2012 hello. how do i get how many 30's there are in x amount and then strip the remainder in 29 there is 0 in 59 there is 1 floor($x/30); Quote Link to comment Share on other sites More sharing options...
DavidAM Posted September 5, 2012 Share Posted September 5, 2012 $count = 0; while ($x >= 30) { $count = $count + 1; $x = $x - 30; } unset($x); echo $count; Quote Link to comment Share on other sites More sharing options...
Psycho Posted September 5, 2012 Share Posted September 5, 2012 $count = 0; while ($x >= 30) { $count = $count + 1; $x = $x - 30; } unset($x); echo $count; That's too efficient. You need to step through one by one $count = 0; $subCount = 0; for ($i=0; $i<$x; $i++) { $subCount++; if($subCount==30) { $count = $count + 1; $subCount = 0; } } echo $count; Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.