scm22ri Posted October 1, 2012 Share Posted October 1, 2012 (edited) Hi Everyone, I want to display the vehicles every user is selling but for some reason I'm getting duplicate information. I think the answer to my question is the array_unique function but I'm having a hard time trying to figure out where the function should go? Any help would be appreciated. Thanks <?php include_once "init.php"; echo "<table border='1'>"; echo "<tr> <th>User ID</th> <th>First Name</th> <th>Last Name</th> <th>Car Desc ID</th> <th>Price</th> <th>Mileage</th> <th>Transmission</th> <th>Color</th> <th>Year</th> <th>Make</th> <th>Model</th> </tr>"; $query = "SELECT users.user_id, users.firstname, users.lastname, prices.car_desc_id, prices.price, \n" . "\n" . "prices.mileage, prices.transmission, prices.color, car_desc.year, car_desc.make, car_desc.model\n" . "\n" . "FROM users, prices, car_desc\n" . "\n" . "WHERE prices.car_desc_id LIMIT 0, 30 "; // $result = array_unique($query); // $query = "SELECT * FROM car_desc ORDER BY id ASC"; $thedude = mysql_query($query) or die(mysql_error()); // $result = array_unique($thedude); while ($row = mysql_fetch_array($thedude)) { $user_id = ($row['user_id']); $firstname = ($row['firstname']); $lastname = ($row['lastname']); $car_desc_id = ($row['car_desc_id']); $price = ($row['price']); $mileage = ($row['mileage']); $transmission = ($row['transmission']); $color = ($row['color']); $year = ($row['year']); $make = ($row['make']); $model = ($row['model']); // keeps getting the next row until there are no more to get /*while ($row = mysql_fetch_array($result))*/ { // Print out the contents of each row into a table ?> <tr> <td><?php echo "$user_id"; ?></td> <td><?php echo "$firstname"; ?></td> <td><?php echo "$lastname"; ?></td> <td><?php echo "$car_desc_id"; ?></td> <td><?php echo "$price"; ?></td> <td><?php echo "$mileage"; ?></td> <td><?php echo "$transmission"; ?></td> <td><?php echo "$color"; ?></td> <td><?php echo "$year"; ?></td> <td><?php echo "$make"; ?></td> <td><?php echo "$model"; ?></td> </tr> <?php } /*echo "</table>";*/ } /*else*/ { /*trigger_error(mysql_error()); // for development only; remove when in production*/ } ?> Edited October 1, 2012 by scm22ri Link to comment Share on other sites More sharing options...
Jessica Posted October 1, 2012 Share Posted October 1, 2012 You need to specify on what columns to join those tables. Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted October 1, 2012 Share Posted October 1, 2012 Locking this thread because you already have an active thread for this. Link to comment Share on other sites More sharing options...
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