How To Get The Value Of My Button

[DrRossi]

I am trying to get the radio's button value from the form to the javascript onclick function to my database.

 

I define my $output in first.php then echo it in second.php. Here is my first.php

 

 

$name = 100;

$answer = "some text";

$output .= '<div id="'.$k.'">

 

 

<form id='.$f.' >

<input type="radio" name='.$name.' value="yes" checked>Accurate

<input type="radio" name='.$name.' value="no">Not Accurate

<input type="button" id='.$j.' value="Submit" onclick="sendData(\''.$answer.'\','.$name.',)">

</form>

</div>'

 

;

$name++;

 

 

 

My jquery function in second.php

 

function sendData(feel, rID)

{

var accu = $("input[@name=rID]:checked").val();

 

$.get("test.php", { feeling: feel , accuracy: accu} );

}

 

 

 

 

When I click my button nothing is submitted. If i manually define var accu to "YES" or something it works. So the problem must be on how to check if my radio button its checked and get its value.

• 
   
  

Edited December 1, 2012 by DrRossi

[trq]

Variables are not interpolated within quotes in Javascript.

[DrRossi]

well i tried it without quotes, single quotes..... nothing worked.

 

 

Any suggestions?

[trq]

What does chrome developer tool have to say about...

 

$("input[name=" + rID + "]:checked");

[DrRossi]

what do you mean? Sorry I am new to php and javascript.

 

 

$("input[name=" + rID + "]:checked");

 

is in my function.

If i view the source code I can see my button's attributes...

[trq]

If your developing Javascript you need to learn how to use the tools available to debug it.

 

Firebug (for firefox) and Developer Tools (for chrome).

 

Using these tools you can type your code into a console, and the console shows various data.

[DrRossi]

Okay found it. well I never used the console before just the html button to check the source code. Thanks for that tip.

 

When I just define the accu as a number or text or even as rID it will come up with

the "POST test.php" and the parameters etc. But when i try

$("input[name=" + rID + "]:checked");

it will not do the POST test.php

Edited December 2, 2012 by DrRossi

[DrRossi]

error found when I click the button

 

 

Syntax error, unrecognized expression: input[@name=510]:checked

 

throw new Error( "Syntax error, unrecognized expression: " + msg );

 

 

By the way that error won't show up in chrome's firebug, but it comes up in firefox firebug.

Edited December 2, 2012 by DrRossi

[DrRossi]

anyone?

[DrRossi]

OMG removed the "@" symbol and now it works smoothly!

 

 

Thanks for your help!!!