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I have a page which shows me submissions made through a webpage.

 

As I deal with those submissions, i.e. as I answer them, I want to update an 'answered' column to 1 (so that those flagged records won't be retrieved for display on the page any more).

 

My retrieval query is like this:

$q = "SELECT id, name, email, submission, submission_type, DATE_FORMAT(date_left, '%a, %D %b %Y @ %l:%i%p') date_left
FROM submissions WHERE answered = 0 ORDER BY id DESC";
$r = mysqli_query($dbc, $q);

 

The form displaying the found set has these lines:

...
<input type='checkbox' name='answered[]' id='answered[]' /></p>
<input type='hidden' name='id[]' id='id[]' value='$id' />
...

 

... and the code I hoped would run the update is this:

if(isset($_POST['submit'])) {
$size = count($_POST['id']);
$i=0;
while($i<$size){
$id = $_POST['id'][$i];
if(isset($_POST['answered'][$i])) {
$answered = 1;
} else {
$answered = 0;
}
$q = "UPDATE submissions SET answered = '$answered' WHERE id = '$id'";
$r = mysqli_query($dbc, $q);
$i++;
}

 

 

It's not working, however. If I check, let's say 3 different records from the found set, the answered flag for the 3 most recent records' is being updated.

 

Can anyone help? Thanks in advance.

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https://forums.phpfreaks.com/topic/271498-flagging-certain-records-in-a-found-set/
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Get rid of the hidden field, you don't need it.

 

Put to record's ID in the name of the checkbox:

echo "<input type='checkbox' name='answered[$id]' /></p>"

 

Then process the answered array:

if (isset($_POST['answered'])) {
 foreach ($_POST['answered'] as $id => $value) {
   UPDATE ... WHERE id = $id
 }
}

 

Note: Checkboxes are only POSTed if they are actually checked. So, if none are checked, the "answered" element of the POST array will not exist.

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