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I'm trying to display certain data from database phpmyadmin by inserting 'student_id' in my search box... but after I submit the data inside the search box, I get this error message in my html page..

 

Error: Column 'student_id' in where clause is ambiguous
In Query: SELECT * FROM student,surat WHERE student_id like '%12-121212-1212%'

 

Is there something wrong with my phpmyadmin or my php code?

 

Here my full php code named "searchres.php" :

 

<?php
$host_name = "localhost";
$user_name = "root";
$password = "";
$db_name = "finalproject";

$StudentID1=$_POST['Field0'];
$StudentID2=$_POST['Field1'];
$StudentID3=$_POST['Field2'];
$term =$StudentID1.-$StudentID2.-$StudentID3;



mysql_connect("$host_name" , "$user_name" , "$password");
mysql_select_db("$db_name");


$sql = "SELECT * FROM student,surat WHERE student_id like '%$term%' AND student.student_id=surat.student_id" ;


$query = mysql_query($sql) or die("Error: " . mysql_error() . "<br />In Query: " . $sql);


while ($row = mysql_fetch_array($query)){
echo 'Student ID: '.$row['student_id'];
echo '<br/> Fullname: '.$row['fullname'];
echo '<br/> IC No.: '.$row['ic_number'];
echo '<br/> Course: '.$row['course'];
echo '<br/> Type Of Letter: '.$row['jenissurat'];
echo '<br/><br/>';
}


?>

 

I'm new in php and mysql, the code above I take it from google and edit some of the code by myself according to my usage.

Hope someone can give me an advice,solution or corrections maybee.. Thank You. :)

I already upload my php file here.

Search.php

searchres.php

If both tables have a student_id column you need to specify which table to select it from.

 

Do you mean from my phpmyadmin? If that so.. my mysql code below is wrong?

 

$sql = "SELECT * FROM student,surat WHERE student_id like '%$term%' AND student.student_id=surat.student_id" ;

 

I think my direction in this code are correct.. maybee.. :sweat:

Thank you for your reply.

 

But how to specify it? Sorry because I'm new in PHP and MySQL .. :-\ Sorry for that.

 

The table that I have is

 

student :

 

student_id : 12-121212-12121

fullname : EZWAN

ic_number : 121212-12-1212

password :

course : IT-Software

 

surat :

 

id_surat : 1

studennt_id : 12-121212-12121

jenissurat : TamatBelajar

status :

Edited by EzwanAbid

Did you mean

$sql = "SELECT * FROM student,surat WHERE table_name.student_id like '%$term%' AND student.student_id=surat.student_id";

 

I'm using this code and IT'S WORKING !! I already can display data from both table using search now..

Thank you alot !! I'm stuck with this problem for over 2 weeks .. :'(

Thank You @SocialCloud for helping me . :happy-04:

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