flashvenom Posted December 13, 2012 Share Posted December 13, 2012 Hi There I am trying to to simply declare an id with an echo inside and then replace the string, if that makes sense. The issue is clearly with the first line of code This works $str1 = "myimage.jpg" <img src="<?php print preg_replace("/\.jpg$/i","-313x174.jpg",$str1);?>"/> output = myimage-313x174.jpg This doesnt $str1 = "<?php the_field('grid_tile_one'); ?>" <img src="<?php print preg_replace("/\.jpg$/i","-313x174.jpg",$str1);?>"/> Any help much appreciated. Link to comment https://forums.phpfreaks.com/topic/271953-echo-isnide-a-string-id/ Share on other sites More sharing options...
MDCode Posted December 13, 2012 Share Posted December 13, 2012 Well, "this doesn't" isn't a good explanation of your problem. What is happening that shouldn't? What is the value of $str1? Link to comment https://forums.phpfreaks.com/topic/271953-echo-isnide-a-string-id/#findComment-1399144 Share on other sites More sharing options...
Jessica Posted December 13, 2012 Share Posted December 13, 2012 Stop opening new PHP tags when you're already writing PHP. Link to comment https://forums.phpfreaks.com/topic/271953-echo-isnide-a-string-id/#findComment-1399212 Share on other sites More sharing options...
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