Query Problem

[designanddev]

I keep getting this error ----> Warning: mysql_fetch_assoc() expects parameter 1 to be resource,

 

Code below

 

$sql = "SELECT id FROM users WHERE first_name =".$this->first_name;
$result = mysql_query($sql,$database->connection);
while($row = mysql_fetch_assoc($result)){
echo $row['firstname'];
}

[atticus]

I don't know, but does MySQL need an additional " at the end of line 1?

[designanddev]

I don't know, but does MySQL need an additional " at the end of line 1?

 

i tried that it breaks my code

[designanddev]

when i change my query to select everything it works i am trying to pass in a post variable from my form to check if that name already exists.

[devilsvein]

$firstname = $_POST['firstname'];

$sql = "SELECT id FROM users WHERE first_name =" . $firstname . " LIMIT 1";


$result = mysqli_query($mysqli, $sql);
$row = mysqli_fetch_assoc($result);


echo $row['Firstname'];

 

$mysqli is the database connection.

 

Sorry I did it procedure style, I never learnt object style.

[designanddev]

Its still coming up with that error

[devilsvein]

then its something else in your code

[designanddev]

I manage to get the error message for when fields have not been filled out, now i am beginning to write the process of checking to see

if a current user already exists, is my method query being past the post? i am not sure if it is that why it may have the error

 

Kind Regards

 

Heres my function...

 

// Check for an email first name:
public function Reg() {
global $database;
if(empty($this->last_name)){
  $this->errors['one'] = "You forgot to enter your
  last name."; 
}
if(empty($this->first_name)){
  $this->errors['two'] = "You forgot to enter your
  first name.";   
}
elseif(empty($this->errors)){
// Register the user in the database...
$sql = "SELECT id FROM users WHERE first_name =" . $first_name . " LIMIT 1";
$result = mysql_query($sql,$database->connection);
while($row = mysql_fetch_assoc($result)){
echo $row['first_name'];
}
}
}//End of Reg

 

 

Heres the call...

if(isset($_POST['submit'])) {
$new_user = new User();
$new_user->first_name = $_POST['first_name'];
$new_user->last_name = $_POST['last_name'];
if($new_user->reg()){


}
else {
$first_name = "";
$last_name = "";
}
}

[devilsvein]

shouldnt it all be mysqli and not mysql

[designanddev]

shouldnt it all be mysqli and not mysql

 

im not sure if that matters... i need this resolving

[Jessica]

im not sure if that matters... i need this resolving

It does matter.

[PFMaBiSmAd]

It does matter.

+1

 

In programming, EVERYTHING matters, because computers only do EXACTLY what your code tells them to do.

 

$this->first_name contains a string and must be enclosed in single-quotes within the query statement so that it will be treated as a literal string instead of a mysql keyword or a column/table/database name. If you had some error checking logic in your code to get the mysql error message that is occurring, it would be complaining about an unknown column name that is the value of the entered first_name.

[designanddev]

+1

 

In programming, EVERYTHING matters, because computers only do EXACTLY what your code tells them to do.

 

$this->first_name contains a string and must be enclosed in single-quotes within the query statement so that it will be treated as a literal string instead of a mysql keyword or a column/table/database name. If you had some error checking logic in your code to get the mysql error message that is occurring, it would be complaining about an unknown column name that is the value of the entered first_name.

 

ok could you show me an example, i can not structure this logic

[designanddev]

Sorry ladies and gents i am still having trouble passing the posted form values into my method query, i can select all and it works fine but when i start to use WHERE clauses it goes all wrong here's my code please take a look.

 

Kind Regards

Submit

if(isset($_POST['submit'])) {
$new_user = new User();
$first_name = $new_user->first_name = $_POST['first_name'];
$last_name = $new_user->last_name = $_POST['last_name'];
if($new_user->reg()){

}
else {
$first_name = "";
$last_name = "";
}
}

 

Method

public function Reg() {
global $database;	
if(empty($this->last_name)){
  $this->errors['one'] = "You forgot to enter your
					last name.";		
}
if(empty($this->first_name)){
  $this->errors['two'] = "You forgot to enter your
					first name.";				
}

elseif(empty($this->errors)){
// Register the user in the database...

$sql = "SELECT id FROM users WHERE first_name =".$this->first_name." LIMIT 1";
$result = mysql_query($sql,$database->connection);
while($row = mysql_fetch_assoc($result)){
echo $row['first_name'];
}

}
}//End of Reg

[designanddev]

I fixed the problem i by changing my query syntax to this...

 

$sql = "SELECT * FROM users WHERE first_name ='{$this->first_name}' LIMIT 1";

 

But i am not sure why this works and the way i normally do my variables in queries did not work,

would be nice to hear that explanation.

 

Kind Regards

 

Leo Scott

[PFMaBiSmAd]

Don't start new threads for the same problem. Merging this thread with your previous one...

 

In your previous thread, someone specifically stated you needed single quotes around the value in the query and they also specifically stated why you needed them -

 

$this->first_name contains a string and must be enclosed in single-quotes within the query statement so that it will be treated as a literal string instead of a mysql keyword or a column/table/database name.

[designanddev]

Don't start new threads for the same problem. Merging this thread with your previous one...

 

In your previous thread, someone specifically stated you needed single quotes around the value in the query and they also specifically stated why you needed them -

 

What i dnt get is that i have been using double quoutes for my queries all along, can someone explain why?

 

Kind Regards

[PFMaBiSmAd]

Your use of double-quotes was terminating the string you were building (which was started with the opening double-quote), concatenating a value with that string (the first dot), then concatenating (the second dot) another double-quoted string onto the the end of that.

 

$sql = "SELECT id FROM users WHERE first_name =".$this->first_name." LIMIT 1";

 

This is equivalent to doing -

 

$sql = "SELECT id FROM users WHERE first_name ={$this->first_name} LIMIT 1";