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Trying to update table using isset() function shows nothing

psonawane

By psonawane
in PHP Coding Help

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psonawane Newbie

psonawane

Posted
Posted (edited)

Hi all am trying to update the database table by submitting a form and used isset (0 function but is shows nothing what can I do? here's my code!!!

 

<html>
   <head>
       <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
       <title></title>
       <link rel="stylesheet" href="main.css" type="text/css">
   </head>
   <body background="media/dark_blue_background-wallpaper-1920x1200.jpg">
   <center>
       <?php
       session_start();
       if ($_SESSION['uname']) {
           ?>   
           <div id="bus">
               <p><img src="media/rk_logo2.png" height="100" width="220"></p>
               <ul>
                   <li style="float: right; padding-right: 10px; font-family: sans-serif; font-weight: bold;">You are Logged in as, <?php echo "" . $_SESSION['uname'] . "!"; ?></li>
               </ul><br><hr>
               <?php
           }
           $host = "localhost";
           $uname = "root";
           $pass = "pranit";
           $db_name = "rk_bookings";
           $tbl_name = "bus_details";[/size][/color][/font]


[font="Verdana, Geneva, sans-serif"][color="#333333"][size=3]            mysql_connect("$host", "$uname", "$pass") or die("cannot connect");
           mysql_select_db("$db_name") or die("cannot select DB");[/size][/color][/font]


[font="Verdana, Geneva, sans-serif"][color="#333333"][size=3]            $coname = $_POST['coname'];
           $dest = $_POST['destination'];
           $sql = "SELECT * FROM $tbl_name WHERE company='$coname' and destination='$dest'";
           $result = mysql_query($sql) or die(mysql_error());
           $rows = mysql_fetch_array($result, MYSQLI_ASSOC);
           ?>
           <div id="disp">
               <form action="update.php">
                   <table>                
                       <tr>
                           <th>Company Name</th>
                           <th>Bus Facilities</th>
                           <th>Depart Time</th>
                           <th>Arrival Time</th>
                       </tr>                                        
                       <tr>
                           <td><input type="text" name="coname" value="<?php echo $rows['company']; ?>"></td>
                           <td><input type="text" name="aminities" value="<?php echo $rows['aminities']; ?>"></td>
                           <td><input type="text" name="depart" value="<?php echo $rows['depart']; ?>"></td>
                           <td><input type="text" name="arrive" value="<?php echo $rows['arrive']; ?>"></td>
                       </tr>
                       <tr>
                           <th>Duration</th>
                           <th>Rate</th>
                           <th>From</th>
                           <th>To</th>                    
                       </tr>
                       <tr>
                           <td><input type="text" name="duration" value="<?php echo $rows['duration']; ?>"></td>
                           <td><input type="text" name="rate" value="<?php echo $rows['price']; ?>"></td>
                           <td><input type="text" name="start" value="<?php echo $rows['start']; ?>"></td>
                           <td><input type="text" name="destination" value="<?php echo $rows['destination']; ?>"></td>
                       </tr> 
                       <tr>
                           <th style="border: none; background: none;"></th>
                           <td></td>
                           <th style="border: none; background: none; float: right;"></th>                
                       </tr>
                   </table>
                   <button type="submit" name="submit">Update!</button><br><br><br>
               </form>                                
               <strong><a href="home.php">Click Here to Go Back!</a></strong>
               <br><br><br>
           </div>
           </body>
           </html>[/size][/color][/font]
[font="Verdana, Geneva, sans-serif"][color="#333333"][size=3]
Edited by psonawane
psonawane Newbie

psonawane

Posted
  • Author
Posted

Hi as per ur instruction I tried this

 

<html>
   <head>
       <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
       <title></title>
       <link rel="stylesheet" href="main.css" type="text/css">
   </head>
   <body background="media/dark_blue_background-wallpaper-1920x1200.jpg">
   <center>
       <?php
       session_start();
       if ($_SESSION['uname']) {
           ?>   
           <div id="bus">
               <p><img src="media/rk_logo2.png" height="100" width="220"></p>
               <ul>
                   <li style="float: right; padding-right: 10px; font-family: sans-serif; font-weight: bold;">You are Logged in as, <?php echo "" . $_SESSION['uname'] . "!"; ?></li>
               </ul><br>
               <div id="menu">                
                   <ul>
                       <li><a href="add.php">Add Bus and Service</a></li>
                       <li><a href="edit.php">Change Bus and Service</a></li>
                       <li><a href="del.php">Delete Bus and Service</a></li>
                       <li><a href="show.php">View Bus and Service</a></li>                        
                   </ul>                
               </div>
               <?php
           }
           $host = "localhost";
           $uname = "root";
           $pass = "pranit";
           $db_name = "rk_bookings";
           $tbl_name = "bus_details";
           if (empty($_POST['update'])) {


               $rate = $_POST['rate'];
               $coname = $_POST['coname'];
               $dest = $_POST['destination'];


               mysql_connect("$host", "$uname", "$pass") or die(mysql_error());
               mysql_select_db($db_name);


               $sql1 = "UPDATE $tbl_name SET price='$rate' WHERE company='$coname' AND destination='$dest'";
               $result = mysql_query($sql1);
               if ($result) {
                   echo "Successful";
               } else {
                   echo mysql_error();
               }
           }
           ?>
           </body>
           </html>

 

and its now saying

Notice: Undefined index: rate in C:\xampp\htdocs\RK_files\update.php on line 40

 

Notice: Undefined index: coname in C:\xampp\htdocs\RK_files\update.php on line 41

 

Notice: Undefined index: destination in C:\xampp\htdocs\RK_files\update.php on line 42

DavidAM Member

DavidAM

Posted
Posted

and one more thing which I dint understand is in 

if (isset($_POST['update']))

 

what does update mean?

 

I don't know why you chose "update" when you added that line of code. But that line is supposed to be checking to see if the form was submitted. Usually, I use the name of the submit INPUT element there. In your code, that would be "submit". Except that your second post did not include the form that was in the first post, so ...

 

You need to check if one of the fields from the form isset (in the $_POST array) which means the form was submitted, before you do any database updates. When you switched to empty, you effectively reversed the IF test so you should have added NOT --

if (! empty($_POST['submit']))

(However isset() is the way to go.)

 

Note: session_start needs to be called before anything is sent to the browser. By the time you call it you have already sent the HEAD so, your session may not be working properly.

 

For form processing, you generally want to move the processing code above the HTML anyway. It would go something like this:

 

1. Start a Session (if one is needed)

2. If the form was submitted ...

A. Validate the data

B. If the data is valid update the database

 

3. Build the form page

Now you can include any error messages from the validation on the page

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