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I have this function which uses ajax ,but this function is not working ,I tried a lot ,but not able to figure out where is the problem ,I am trying to create alert if user inserts duplicate entry in database using check-box selection

 

 


<script>
function func(e,eid,emprid) {

if(document.getElementById(e).checked){
var dataString =        'eid='+eid
+'&emprid='+emprid
;


$.ajax({
type:"POST",
url: "mylistcheck.php",
data: dataString,
success: function(result){

if(result!='0')
{
modal.open({content: "<span style=\"color:red\" ><h2>You have already selected  candidate </h2></span>"});
document.getElementById(e).checked=false;
}

}
});
}

}

</script>

mylistcheck.php file

 

<?php require_once("includes/session.php"); ?>
<?php require_once("includes/connection.php"); ?>
<?php require_once("includes/functions.php"); ?>
<?php
$eid=$_POST['eid'];
echo "eid".$eid;
$emprid=$_POST['emprid'];
echo "rid".$emprid;

$sqlchecklist="SELECT * FROM selected_candidate WHERE eid='{$eid}' AND rid='{$emprid}' ";
$checklistres=mysql_query($sqlchecklist);
$list_check=mysql_num_rows($checklistres);
echo "numrows listcheck".$list_check;
if($list_check>0)
{
   echo "1";
}
else
{
   echo "0";
}
?>

check-box code

 

echo "<td><input id=\"select_candi{$i}\" onclick=\"javascript:func(this.id,{$data_set['eid']},{$emprid})\" type=\"checkbox\" name=\"check_candi[]\" value=\"{$data_set['eid']},{$emprid}\"/></td>"; 

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https://forums.phpfreaks.com/topic/273303-ajax-code-not-working/
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you would o the trim in the Javascript :

success: function (result){
var myResult = trim(result);
alert(myResult); //<---test to see what's actualy coming back from the php page, delete this line when all is working
modal.......//<<the rest of your code

Edited by Muddy_Funster
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