mysqli_connect()

[White_Lily]

Hi, I have ahd a slight problem with the deprecation of mysql_*() functions, and so are swapping them for mysqli_*() functions, how I have come across an error which states that $connect is undefined.

 

<?php

$GLOBALS["host"] = "localhost";
$GLOBALS["user"] = "web113-social-1";
$GLOBALS["pass"] = "********";
$GLOBALS["database"] = "***************";

$connect = mysqli_connect($GLOBALS["host"], $GLOBALS["user"], $GLOBALS["pass"], $GLOBALS["database"]);
?>

 

I have compared this against php.net's examples, and this code looks almost exact. I dont know what the problem is. Any help would be appreciated.

 

- Lily

[Jessica]

Why are you putting sensitive information into the globals array? Use constants.

 

The code you've posted would not produce an error about an undefined variable. You're also not checking for errors.

[White_Lily]

• 
  Notice: Undefined variable: connect in/home/sites/janedealsart.co.uk/public_html/social/inc/functions.php on line 17
  

Actually Jessica - yes it is producing an undefined variable error.

[White_Lily]

Okay, so I looked back at php.net to see what error checking they use...

 

<?php

$connect = mysqli_connect("localhost", "username", "password", "database");

if(!$connect){
die('Connect Error (' . mysqli_connect_errno() . ') '. mysqli_connect_error());
}

echo 'Success... ' . mysqli_get_host_info($connect) . "\n";
?>

 

Guess what... Still getting an Undefined $connect error... dispite manually typing in the connection settings.

[Jessica]

Line 17... So there's a whole bunch of code you didn't post. Like I said - the code YOU ORIGINALLY POSTED could not produce that error.

 

 

[White_Lily]

I figured it out, it was the $connect variable being undefined, how I don't know, but all I did was re-type the connection details re-uploaded the file, and the error disappeared and data from the database showed.

[Jessica]

*smh* Whatever.