alena1347 Posted January 29, 2013 Share Posted January 29, 2013 I have inserted a jquery in my html page but it is not fading out <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <link href="programmers.css" rel="stylesheet" type="text/css" /> <?php include('conn.php'); include('header.php'); ?> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>User Allotment</title> <script src="//ajax.aspnetcdn.com/ajax/jQuery/jquery-1.8.3.min.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function(){ $("#detail").hide(); $("#view").click(function() { $("#form").fadeout(); $("#detail").fadeIn(); }); }); </script> </head> <body> <form id="form1" name="form1" method="post" action="" id="form"> <table align="center" width="100%" id="form"> <tr> <td height="25" width="100%" bgcolor="#CCCCCC" align="center"><a href="user_allotment.php">User Allotment</a> <a href="view_users.php">View Users</a> <a href="">Pending Aprovals</a> <a href="freelancers_pending.php">Freelancer Pending</a> <a href="search.php">Search</a> <a href="admin_login.htm">Logout</a></td> </tr> <tr> <td><br/> <table width="1019" border="1" align="center" bgcolor="#FFFFFF"> <tr> <td colspan="13" align="center"><strong>PENDING APPROVALS</strong></td> </tr> <tr align="center"> <td width="60" align="center" >Id</td> <td width="60" align="center">First Name</td> <td width="60" align="center">Last Name</td> <td width="65" align="center">Company</td> <td width="50" align="center">Phone</td> <td width="40" align="center">Ext</td> <td width="50" align="center">E-mail</td> <td width="70" align="center">Skill required</td> <td width="75" align="center">Experience</td> <td width="70" align="center">Duration of hire</td> <td width="70" align="center">Location of hire</td> <td width="110" align="center">Brief project description</td> <td width="60" align="center">view</td> </tr> <?php mysql_select_db("programmers") or die(mysql_error()); $data = mysql_query("SELECT * FROM hire") or die(mysql_error()); while($info = mysql_fetch_array( $data )) { ?> <tr> <td><?php echo $info['id'];?></td> <td><?php echo $info['fname'];?></td> <td><?php echo $info['lname'];?></td> <td><?php echo $info['cname'];?></td> <td><?php echo $info['cnum'];?></td> <td><?php echo $info['enum'];?></td> <td><?php echo $info['email'];?></td> <?php $id=$info['id']; $fetch=mysql_query("SELECT sname FROM skill WHERE id=$id"); while($row=mysql_fetch_array($fetch)) { $sname=$row['sname']; $sk[]=$sname; } $arr=implode(',',$sk); ?> <td><?php echo $arr;?></td> <td><?php echo $info['exnum'];?></td> <td><?php echo $info['dnum'];?></td> <td><?php echo $info['lhname'];?></td> <td><?php echo $info['task'];?></td> <td><label><input type="button" class="view" id="view" value="view"/></label></td> </tr> <?php } ?> </table> </td> </tr> </table> </form> </body> </html> <?php include('footer.php'); ?> Quote Link to comment https://forums.phpfreaks.com/topic/273783-why-isnt-the-jquery-working/ Share on other sites More sharing options...
trq Posted January 29, 2013 Share Posted January 29, 2013 And you have done what to debug your code? Quote Link to comment https://forums.phpfreaks.com/topic/273783-why-isnt-the-jquery-working/#findComment-1408928 Share on other sites More sharing options...
kicken Posted January 29, 2013 Share Posted January 29, 2013 <form id="form1" name="form1" method="post" action="" id="form"> You can't specify the id attribute twice. Quote Link to comment https://forums.phpfreaks.com/topic/273783-why-isnt-the-jquery-working/#findComment-1408956 Share on other sites More sharing options...
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