Why isn't the jquery working

alena1347 · January 29, 2013

I have inserted a jquery in my html page but it is not fading out

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<link href="programmers.css" rel="stylesheet" type="text/css" />
<?php
include('conn.php');
include('header.php');
?>

<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>User Allotment</title>
<script src="//ajax.aspnetcdn.com/ajax/jQuery/jquery-1.8.3.min.js" type="text/javascript"></script>

		<script type="text/javascript">
			$(document).ready(function(){
				$("#detail").hide();

				$("#view").click(function() {
					$("#form").fadeout();
					$("#detail").fadeIn();

				});
			});
		</script>
</head>

<body>
<form id="form1" name="form1" method="post" action="" id="form">
<table align="center" width="100%" id="form">
<tr>
<td height="25" width="100%" bgcolor="#CCCCCC" align="center"><a href="user_allotment.php">User Allotment</a>   <a href="view_users.php">View Users</a>   <a href="">Pending Aprovals</a>   <a href="freelancers_pending.php">Freelancer Pending</a>   <a href="search.php">Search</a>   <a href="admin_login.htm">Logout</a></td>
</tr>
<tr>
<td><br/>
 <table width="1019" border="1" align="center" bgcolor="#FFFFFF">
<tr>
  <td colspan="13" align="center"><strong>PENDING APPROVALS</strong></td>
</tr>
<tr align="center">
  <td width="60" align="center" >Id</td>
  <td width="60" align="center">First Name</td>
  <td width="60" align="center">Last Name</td>
  <td width="65" align="center">Company</td>
  <td width="50" align="center">Phone</td>
  <td width="40" align="center">Ext</td>
  <td width="50" align="center">E-mail</td>
  <td width="70" align="center">Skill required</td>
  <td width="75" align="center">Experience</td>
  <td width="70" align="center">Duration of hire</td>
  <td width="70" align="center">Location of hire</td>	
  <td width="110" align="center">Brief project description</td>

  <td width="60" align="center">view</td>
</tr>
<?php

 mysql_select_db("programmers") or die(mysql_error());

$data = mysql_query("SELECT * FROM hire")
or die(mysql_error());

while($info = mysql_fetch_array( $data ))
{ ?>
<tr>
<td><?php echo $info['id'];?></td>
<td><?php echo $info['fname'];?></td>
<td><?php echo $info['lname'];?></td>
<td><?php echo $info['cname'];?></td>
<td><?php echo $info['cnum'];?></td>
<td><?php echo $info['enum'];?></td>
<td><?php echo $info['email'];?></td>
<?php
$id=$info['id'];
$fetch=mysql_query("SELECT sname FROM skill WHERE id=$id");
while($row=mysql_fetch_array($fetch))
{
$sname=$row['sname'];
$sk[]=$sname;
 }
 $arr=implode(',',$sk);
 ?>
<td><?php echo $arr;?></td>
<td><?php echo $info['exnum'];?></td>
<td><?php echo $info['dnum'];?></td>
<td><?php echo $info['lhname'];?></td>  
<td><?php echo $info['task'];?></td>
<td><label><input type="button" class="view" id="view" value="view"/></label></td>
</tr>

<?php }
?>
	</table>

   </td>

</tr>

 </table>
</form>
</body>
</html>
<?php
include('footer.php');
?>

trq · January 29, 2013

And you have done what to debug your code?

kicken · January 29, 2013

<form id="form1" name="form1" method="post" action="" id="form">

You can't specify the id attribute twice.

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Why isn't the jquery working

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