MFA Posted February 16, 2013 Share Posted February 16, 2013 my code doesnt seem to work.. the radio buttons appear but nothing beside them .. what i know already: mysql_fetch_row is working - i have tested this using mysqli_num_rows() mysqli_query is working - testing in phpmyadmin and also proven above the problem seems to be with $a ..... $e .. i have tried to echo these variables outside teh form but they dont work. i have also tried to echo them directly ie. $retrieve['question']; and this doesnt work either. could someone please advise what is wrong? cheers ps. i am new at this. this is my code. <?php include 'dbyear2.php'; $qnumber = ($_REQUEST['uqn']); // obtain question number from URL $find = mysqli_query($condbyear2, "SELECT * FROM Renal WHERE UQN='$qnumber'"); while($retrieve=mysqli_fetch_row($find)); { $question = $retrieve['question']; $a = $retrieve['MCQ_A']; $b = $retrieve['MCQ_B']; $c = $retrieve['MCQ_C']; $d = $retrieve['MCQ_D']; $e = $retrieve['MCQ_E']; $answer = $retrieve['answer']; $correct = $retrieve['MCQ_correct']; } ?> <form action='check.php' method='POST'> <table> <tr><td></td><td></td></tr> <tr></tr> <tr><td><input type='radio' name='group1' value='A' /></td><td> <?php echo $a; ?></td></tr> <tr><td><input type='radio' name='group1' value='B' /></td><td> <?php echo $b; ?></td></tr> <tr><td><input type='radio' name='group1' value='C' /></td><td> <?php echo $c; ?></td></tr> <tr><td><input type='radio' name='group1' value='D' /></td><td> <?php echo $d; ?></td></tr> <tr><td><input type='radio' name='group1' value='E' /></td><td> <?php echo $e; ?></td></tr> <tr> <?php // sending the retrieved information from MYSQL via POST for use in check.php file $qnumber; $a; $b; $c; $d; $e; $answer; $correct; ?></tr> <tr><td><input type="submit" value="Submit"></td></tr> </table> </form> Quote Link to comment https://forums.phpfreaks.com/topic/274548-php-echo-in-form-is-not-working/ Share on other sites More sharing options...
Psycho Posted February 16, 2013 Share Posted February 16, 2013 Well, one question I have is why are you using a while() loop to get the result from the query? You are apparently only expecting one result so a while loop() is unnecessary and unintuitive. But, your problem is simple. Here is what the manual states about mysqli_fetch_row() Get a result row as an enumerated array In other words it makes the keys of the array 0, 1, 2, etc. I never use fetch_row because of that. Use mysql-_fetch_assoc() instead so the keys of the array are the names of the fields in the query - as you apparently expect them to be. By the way, you could have verified this very easily by doing some simple debugging such as using print_r() or var_dump() on $retrieve Quote Link to comment https://forums.phpfreaks.com/topic/274548-php-echo-in-form-is-not-working/#findComment-1412726 Share on other sites More sharing options...
MFA Posted February 16, 2013 Author Share Posted February 16, 2013 Well, one question I have is why are you using a while() loop to get the result from the query? You are apparently only expecting one result so a while loop() is unnecessary and unintuitive. But, your problem is simple. Here is what the manual states about mysqli_fetch_row() In other words it makes the keys of the array 0, 1, 2, etc. I never use fetch_row because of that. Use mysql-_fetch_assoc() instead so the keys of the array are the names of the fields in the query - as you apparently expect them to be. By the way, you could have verified this very easily by doing some simple debugging such as using print_r() or var_dump() on $retrieve It works now and I understood your explanation. Thank you. I will look into the debugging methods you suggested for next time however like I said I'm very new. Quote Link to comment https://forums.phpfreaks.com/topic/274548-php-echo-in-form-is-not-working/#findComment-1412729 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.