Jump to content

Search the Community

Showing results for tags 'echo'.



More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • Welcome to PHP Freaks
    • Announcements
    • Introductions
  • PHP Coding
    • PHP Coding Help
    • Regex Help
    • Third Party Scripts
    • FAQ/Code Snippet Repository
  • SQL / Database
    • MySQL Help
    • PostgreSQL
    • Microsoft SQL - MSSQL
    • Other RDBMS and SQL dialects
  • Client Side
    • HTML Help
    • CSS Help
    • Javascript Help
    • Other
  • Applications and Frameworks
    • Applications
    • Frameworks
    • Other Libraries
  • Web Server Administration
    • PHP Installation and Configuration
    • Linux
    • Apache HTTP Server
    • Microsoft IIS
    • Other Web Server Software
  • Other
    • Application Design
    • Other Programming Languages
    • Editor Help (Dreamweaver, Zend, etc)
    • Website Critique
    • Beta Test Your Stuff!
  • Freelance, Contracts, Employment, etc.
    • Services Offered
    • Job Offerings
  • General Discussion
    • PHPFreaks.com Website Feedback
    • Miscellaneous

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Age


Donation Link

Found 7 results

  1. foreach($text as $key => $value) { echo "test"; echo "value: " . $value . "<br />"; $tab=explode("\t", trim($value)); echo "<br />" . $tab[0] . $tab[$i1] . $tab[$i2] . $tab[$i3] . $tab[$i4] . $tab[$i5]. "<br />"; ... So this snippet is driving me mad. I'm trying to clean up some code that I've been working on in order to move on to the next segment. When I comment out the "echo value . $value" line, the whole thing 500's on me. I added in the echo test statement just to see if there was something weird going on with the open brace in the foreach statement. Does anyone have any idea why this would be acting this way. More code available upon request, but literally all I'm doing in between saves is adding a // in front of the word echo (I've tried at the very front of the line as well as directly in front of the e in echo with the same results). Thanks.
  2. I'm making my own CMS for my company so going through making the pages for the back end. What I want to do that I'm stuck on is -------------- I want to allow the user to specify how many input text fields they want shown on the page. I'm thinking that they could write a number then click submit, send the data to the same page (PHP self or action blank) and then the required amount of input fields would be echoed out. Echoing out is easy, I want to know how to find out how many fields are required, and then process it. Thanks in advance.
  3. <?php function getFullMonthName($num) { if ($num < 1 || $num > 12) { return "Unknown"; } return ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"][$num - 1]; } $ids = mysqli_real_escape_string($db, $id); $sql = "SELECT * FROM multimedia, keertan WHERE multimedia.id LIKE '$ids' AND keertan.multimediaid LIKE '$ids' ORDER BY k_order ASC"; $result = mysqli_query($db, $sql); $title_list = "xyz"; $done = "xyz"; while ($myrow = mysqli_fetch_array($result)) { $location = $myrow["location"]; $program = $myrow["program"]; $year = sprintf("%04s", $myrow["year"]); $month = sprintf("%02s", $myrow["month"]); $monthName = getFullMonthName($month); $isnew = $myrow["isnew"]; if ($done != "true") { echo "<h3><b>$location $program $monthName $year</b></h3>"; } $done = "true"; while ($title_list != $myrow["title"]) { $title_list = $myrow["title"]; $sublist = $myrow["sub_title"]; echo "<div class=\"panel panel-primary\"><div class=\"panel-heading clickable\"><h3 class=\"panel-title\"><b>$title_list</b></h3>"; echo "<small>$sublist</small><span class=\"pull-right\"><i class=\"fa fa-minus\"></i></span></div><div class=\"panel-sarabveer-table\"><table class=\"table\"><thead><tr><th>Time</th><th>Kirtani</th><th>MP3</th><th>Video</th></thead>"; } if (strtotime($myrow["created"]) > strtotime("3 weeks ago")) { $newed = "NEW"; } elseif (strtotime($myrow["modified"]) > strtotime("3 weeks ago")) { $newed = "UPDATED"; } else { $newed = ""; } printf("<tr><td>%s</td><td>%s <small>%s</small></td>", $myrow["length"], $myrow["keertaneeya"], $newed); $mp3f = urlencode($myrow['mp3_link']); if ($myrow["mp3_link"] != "") { printf("<td><a target=\"_blank\" href=\"http://www.akji.org.uk/multimedia/%s/%s/%s\"><img src=\"images/play.png\" border=\"0\" width=\"25\" height=\"25\"></a></td>", $myrow["location"], $year, $mp3f); } else { echo "<td></td>"; } if ($myrow["rv1_link"] != "") { printf("<td><a target=\"_blank\" href=\"%s\"><img src=\"images/vplay.png\" border=\"0\" width=\"25\" height=\"25\"></a></td></tr>", $myrow["rv1_link"]); } else { echo "<td></td></tr>"; } echo "</table></div></div>"; } ?> So Basically I have this code that displays this page: https://akjmobile.org/keertannew.php?id=532 The problem is that the echo on line 97 runs to early and cuts of rest of the table information, making the other table information be spit out outside of the Bootstrap Panel. How would I fix this?
  4. Hi I echo out images from a folder. The problem is that I have a html file in the same folder but I don't want to echo that out. How can I write my code to get rid of the html in the output? Here my code: <?php $filetype = '*.html'; $dirname = substr('$filetype'); $i=0; if (isset($_POST['submit2'])) { //get the dir from POST $selected_dir = $_POST['myDirs']; //now get the files from within the selected dir and echo them to the screen foreach(glob($selected_dir . DIRECTORY_SEPARATOR . '*') as $dirname) { echo substr($dirname, 0, -4); echo '<img src="'.$dirname.'" />'; echo "<label><div class=\"radiobt\"><input type='radio' name='radio1' value='$i'/></div></label>"; } } ?> P.S. when I echo out : substr($dirname, 0, -4); I want to get ride of the html filename there too. How can I do so something like this?
  5. Hi all, I want to echo two variables inside the body of automatic email. i am trying to get those two variables from the form that customer just submitted. i am posting my code below, please help ASAP. Thanks in advance <?php if(isset($_POST['button_pressed'])) { $to=$Email; $subject='Hi There!!'; $body='Hi'; $Title . '' . $Surname; ', This is a demo email sent using PHP on XAMPP'; if (mail($to,$subject,$body)){ echo 'Mail sent successfully!'; } else{ echo 'Mail not sent!'; }} ?>
  6. Hi I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems. 1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that? for($x = 1;$x<=40;$x++) { $lines = file("$filename.html"); echo $lines[rand(0, count($lines)-1)]."<br>"; } I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one. 2nd Problem: As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file? My code: if($_POST['submitPasswordIT']){ if ($_POST['passIT']== $password ){ $my_file = file_get_contents("$filename.html"); echo $my_file; } else{ echo "You entered wrong password"; } } If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that. // get the filename of the file $fileinfo = pathinfo($selected_file); $filename = $fileinfo['dirname'] . DIRECTORY_SEPARATOR . $fileinfo['filename']; You may need this lines to: $selected_file = $_POST['radio1']; // get the filename of the file $fileinfo = pathinfo($selected_file); $filename = $fileinfo['dirname'] . DIRECTORY_SEPARATOR . $fileinfo['filename']; Help would be very much appreciated.
  7. i have proof, hold on. In PHP there are two basic ways to get output: echo and print. meant there was more ways but they werent basic.
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.