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php echo in form is not working


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my code doesnt seem to work.. the radio buttons appear but nothing beside them ..

 

what i know already:

 

mysql_fetch_row is working - i have tested this using mysqli_num_rows()

mysqli_query is working - testing in phpmyadmin and also proven above

 

the problem seems to be with $a ..... $e .. i have tried to echo these variables outside teh form but they dont work. i have also tried to echo them directly ie. $retrieve['question']; and this doesnt work either.

 

could someone please advise what is wrong? cheers ps. i am new at this.

 

this is my code.

 

<?php

 

include 'dbyear2.php';

 

$qnumber = ($_REQUEST['uqn']); // obtain question number from URL

 

$find = mysqli_query($condbyear2, "SELECT * FROM Renal WHERE UQN='$qnumber'");

 

while($retrieve=mysqli_fetch_row($find));

 

 

{

$question = $retrieve['question'];

$a = $retrieve['MCQ_A'];

$b = $retrieve['MCQ_B'];

$c = $retrieve['MCQ_C'];

$d = $retrieve['MCQ_D'];

$e = $retrieve['MCQ_E'];

$answer = $retrieve['answer'];

$correct = $retrieve['MCQ_correct'];

 

}

 

 

?>

 

 

 

<form action='check.php' method='POST'>

 

<table>

 

<tr><td></td><td></td></tr>

<tr></tr>

<tr><td><input type='radio' name='group1' value='A' /></td><td> <?php echo $a; ?></td></tr>

<tr><td><input type='radio' name='group1' value='B' /></td><td> <?php echo $b; ?></td></tr>

<tr><td><input type='radio' name='group1' value='C' /></td><td> <?php echo $c; ?></td></tr>

<tr><td><input type='radio' name='group1' value='D' /></td><td> <?php echo $d; ?></td></tr>

<tr><td><input type='radio' name='group1' value='E' /></td><td> <?php echo $e; ?></td></tr>

<tr>

 

<?php

 

// sending the retrieved information from MYSQL via POST for use in check.php file

 

$qnumber;

$a;

$b;

$c;

$d;

$e;

$answer;

$correct;

 

 

?></tr>

<tr><td><input type="submit" value="Submit"></td></tr>

 

 

 

 

 

</table>

 

</form>

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Well, one question I have is why are you using a while() loop to get the result from the query? You are apparently only expecting one result so a while loop() is unnecessary and unintuitive.

 

But, your problem is simple. Here is what the manual states about mysqli_fetch_row()

  Quote
Get a result row as an enumerated array

 

In other words it makes the keys of the array 0, 1, 2, etc. I never use fetch_row because of that. Use mysql-_fetch_assoc() instead so the keys of the array are the names of the fields in the query - as you apparently expect them to be.

 

By the way, you could have verified this very easily by doing some simple debugging such as using print_r() or var_dump() on $retrieve

  On 2/16/2013 at 12:53 AM, Psycho said:

Well, one question I have is why are you using a while() loop to get the result from the query? You are apparently only expecting one result so a while loop() is unnecessary and unintuitive.

 

But, your problem is simple. Here is what the manual states about mysqli_fetch_row()

 

 

In other words it makes the keys of the array 0, 1, 2, etc. I never use fetch_row because of that. Use mysql-_fetch_assoc() instead so the keys of the array are the names of the fields in the query - as you apparently expect them to be.

 

By the way, you could have verified this very easily by doing some simple debugging such as using print_r() or var_dump() on $retrieve

 

It works now and I understood your explanation. Thank you. I will look into the debugging methods you suggested for next time however like I said I'm very new.

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