same javascript at two places doesnt work

mukeshprasad4u · February 20, 2013

HI ,

I am begineer in the field of webdesigning.

I am facing problem with a java script which is working at one places but doesnot at another.

Test.php -- working fine

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<title>Untitled Document</title>

var clone;

function cloneRow(){

var rows=document.getElementById('mytab').getElementsByTagName('tr');

var index=rows.length;

clone=rows[index-1].cloneNode(true);

var inputs=clone.getElementsByTagName('input'), inp, i=0,n ;

while(inp=inputs[i++]){

inp.name=inp.name.replace(/\d/g,'')+(index+1);

}

function addRow(){

var tbo=document.getElementById('mytab').getElementsByTagName('tbody')[0];

tbo.appendChild(clone);

cloneRow();

}

function addValue(obj){

obj.value=obj.value.replace(/[^\d]/,'');

var fields=document.getElementsByTagName('input'), i=0, tot=0, f;

while(f=fields[i++]){

f.name&&f.name.match(/cost/)?tot+=Number(f.value):null;

}

document.getElementsByName('sum')[0].value=tot;

}

onload=cloneRow;

</script>

</head>

<body>

<?php

$host="localhost"; // Host name

$username="root"; // Mysql username

$password="root"; // Mysql password

$db_name="teanest"; // Database name

// Connect to server and select databse.

$con=mysql_connect("$host", "$username", "$password");

if (!$con)

{

die('Could not connect: ' . mysql_error());

}

mysql_select_db("$db_name")or die("cannot select DB");

$sql="select id,name from items order by name";

$result = mysql_query ($sql);

$sql1="select id,name from suppliers order by name";

$result1=mysql_query($sql1);

?>

<table>

<tr>

</td>

</tr>

<tr>

<td align="right">Supplier:</td>

<?php

echo "<select name=\"suppliers\" value=''>Supplier</option>";

// printing the list box select command

while($nt=mysql_fetch_array($result1)){//Array or records stored in $nt

echo "<option value=$nt[id]>$nt[name]</option>";

/* Option values are added by looping through the array */

}

echo "</select>";// Closing of list box

?>

</td>

<tr>

</tr>

<tr>

</tr>

</table>

<tr>

<th>Quantity</th>

<th>Cost Price</th>

</tr>

<tr>

<td>

<?php

echo "<select name=\"items\" value=''>Item</option>";

// printing the list box select command

while($nt=mysql_fetch_array($result)){//Array or records stored in $nt

echo "<option value=$nt[id]>$nt[name]</option>";

/* Option values are added by looping through the array */

}

echo "</select>";// Closing of list box

?>

</td>

</tr>

</table>

<br>

<p>

Total: <input type="text" name="sum" readonly="readonly" value="Sum of Cost Price inputs">

</form>

</body>

</html>

receivings.php-- doesnot work ... same javascript included in header part

<?php

include 'includes/header.inc.php';

?>

<li><a href="#receive">Receive</a></li>

<li><a href="#">Link three</a></li>

</ul>

</div>

<?php

$host="localhost"; // Host name

$username="root"; // Mysql username

$password="root"; // Mysql password

$db_name="teanest"; // Database name

// Connect to server and select databse.

$con=mysql_connect("$host", "$username", "$password");

if (!$con)

{

die('Could not connect: ' . mysql_error());

}

mysql_select_db("$db_name")or die("cannot select DB");

$sql="select id,name from items order by name";

$result = mysql_query ($sql);

$sql1="select id,name from suppliers order by name";

$result1=mysql_query($sql1);

?>

<div>

<legend>Receive:</legend>

<table>

<tr>

<td align="right">Supplier:</td>

<?php

echo "<select name=\"suppliers\" value=''>Supplier</option>";

// printing the list box select command

while($nt=mysql_fetch_array($result1)){//Array or records stored in $nt

echo "<option value=$nt[id]>$nt[name]</option>";

/* Option values are added by looping through the array */

}

echo "</select>";// Closing of list box

?>

</td>

<tr>

</tr>

<tr>

</tr>

</table>

<tr>

<th>Quantity</th>

<th>Cost Price</th>

</tr>

<tr>

<td>

<?php

echo "<select name=\"items\" value=''>Item</option>";

// printing the list box select command

while($nt=mysql_fetch_array($result)){//Array or records stored in $nt

echo "<option value=$nt[id]>$nt[name]</option>";

/* Option values are added by looping through the array */

}

echo "</select>";// Closing of list box

?>

</td>

</tr>

</table>

<br>

<p>

Total: <input type="text" name="sum" readonly="readonly" value="Sum of Cost Price inputs">

</fieldset>

</form>

</div>

<h1>List Of Receivings:</h1>

</div>

</div>

<?php

include 'includes/footer.inc.php';

?>

Please help !!!

codefossa · February 20, 2013

Code boxes with formatted code would be nice. Also, for your protection, you shouldn't include your SQL information.

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same javascript at two places doesnt work

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