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Found 245 results

  1. exceedinglife

    Php bootstrap 4 email from form

    Hello all, I have a website with a form that I want a user to fill out then if it is valid I have the button submit and I want it to email me. The message. If success full I want a message to popup on screen saying success I am using bootstrap 4 <div class="messageSuccess"></div> <div class="row"> <div class="col-md-9 mb-md-0 mb-5"> <form id="contact-form" name="contact-form" action="" method="post"> <!--action="contactEmail.php" --> <div class="row "> <div class="col-md-6 "> <div class="md-form mb-0 "> <input class="form-control" type="text" id="txtName" name="txtName" required /> <label for="txtName">Your Name </label> <div class="nameError"></div> </div> </div> <div class="col-md-6 "> <div class="md-form mb-0 "> <input class="form-control" type="text" id="txtEmail" name="txtEmail" required /> <label id="lblEmail" for="txtEmail">Your Email Address </label> </div> </div> </div> <div class="row"> <div class="col-md-12"> <div class="md-form mb-0"> <input class="form-control" type="text" id="txtSubject" name="txtSubject" data-error="Subject Here" required /> <label for="txtSubject">Subject </label> <div class="help-block with-errors"></div> </div> </div> </div> <div class="row"> <div class="col-md-12"> <div class="md-form"> <textarea class="form-control" type="text" id="txtMessage" name="txtMessage" rows="4" required data-error="Please leave us a message."></textarea> <label for="txtMessage">Your Message </label> </div> </div> </div> <div class="text-center text-md-left"> <input type="submit" id="BtnFormSubmit" class="btn btn-primary btn-xl text-white" value="Send Message" /> </div> <div class="status"></div> </form> <!-- JavaScript Inner File Form Validation --> <script type="text/javascript"> $(document).ready(function () { var form = $("#contact-form"); var name = $("#txtName").val(); var email = $("#txtEmail").val(); var subject = $("#txtSubject").val(); var message = $("#txtMessage").val(); var btnSubmit = $("BtnFormSubmit"); $(form).submit(function (event) { if (this.checkValidity() == false) { $(this).addClass("was-validated"); event.preventDefault(); event.stopPropagation(); } alert("Form Valid to create message"); if (!event.isDefaultPrevented) { alert("passed prevent default"); var url = "testemail.php"; // POST values 'ajax' $.ajax({ type: "POST", url: url, data: $(this).serialize(), success: function (data) { // done: // data = JSON object object for contactEmail.php // recieve message type: success | danger var messageAlert = "alert- " + data.type; var messageText = data.message; // Bootstrap alert box HTML var alertBox = '<div class="alert ' + messageAlert + ' alert-dismissable"><button type="button" class="close" ' + 'data-dismiss="alert" aria-hidden="true">&times;</button>' + messageText + '</div>'; // if messageAlert and messageText if (messageAlert && messageText) { // Put message on page in messageSuccess section. $(form).find("#messageSuccess").html(alertBox); // Reset the form. $(form)[0].reset(); } } }); //return false; } }); //$(name).blur(function () { //}) // Validate :inputs $(":input").blur(function () { let controlType = this.type; switch (controlType) { case "text": case "password": case "textarea": validateText($(this)); break; case "email": validateEmail($(this)); break; default: break; } }); // each :input focusin remove existing validation messages if any. $(":input").click(function () { $(this).removeClass("is-valid is-invalid"); }) /* OPTIONAL ':input' KEYDOWN validation messages remove */ // Reset Form and remove all validation messages. $(":reset").click(function () { $(":input").removeClass("is-valid is-invalid"); $(form).removeClass("was-validated"); }); }); // Validate Text Function function validateText(control) { let textField = control.val(); if (textField.length > 1) { $(control).addClass("is-valid"); } else { $(control).addClass("is-invalid"); } } // Validate Email Function (Email newer regex: /^([\w-\.]+@([\w-]+\.)+[\w-]{2,6})?$/ ) function validateEmail(control) { let textField = control.val(); let regexPattern = /^\b[A-Z0-9._%-]+@[A-Z0-9.-]+\.[A-Z]{2,6}\b$/i; if (regexPattern.test(textField)) { $(control).addClass("is-valid"); } else { $(control).addClass("is-invalid"); } } </script> <?php $from = 'SampleEmail@YourEmail.com'; $sendTo = 'sample@Gmail.com'; $subject = 'Your Message Subject Here';// Email Message Contact Form Fields // Array - ($varName => Text from controls) $controls = array('txtName' => 'Name', 'txtEmail' => 'Email', 'txtSubjext' => 'Subject', 'txtMessage' => 'Message'); $successMessage = 'Contact Message Successfully Sent. Thank you, I will get back to you soon.'; $errorMessage = 'There was an error submitting your message, Please try again. Or try later.'; error_reporting(E_ALL & ~E_NOTICE); try { if(count($_POST) == 0) throw new \Exception('Contact Form Message is empty'); $emailText = "You have a new message from your contact form\n------------------------------------------------------\n"; foreach($_POST as $key => $value) { if(isset($controls[$key])) { $emailText .= "$controls[$key]: $value\n"; } } $headers = array('Content-Type: text/plain; charset="UTF-8";', 'From: ' . $from, 'Reply-To: ' . $from, 'Return-Path: ' . $from, ); // Send email mail($sendTo, $subject, $emailText, implode("\n", $headers)); $responseArray = array('type' => 'success', 'message' => $successMessage); } catch(\Exception $e) { $responseArray = array('type' => 'danger', 'message' => $errorMessage); } // If AJAX request return JSON response **RARE** if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') { $encodedJSON = json_encode($responseArray); header('Content-Type: application/json'); echo $encodedJSON; } else { echo $responseArray['message']; } ?>
  2. ttsprez

    Pdf to html Converter needed

    So I've done a search for pdf to html converters and there are plenty of free online options. The only problem is that they don't convert the pdf to html in an actual 8.5 x11 size, so that when you go to print or use them to be filled by code and then printed, they are to small. Now, some would say, simply resize the html file, but the issue there is when created it actually consists of two files. One an html file with absolute position values for all your text and the second as a jpeg for any backgrounds, frames or images. You can adjust the size of the background, borders and images, but then that would also mean you'd have to go line for line in the html to adjust the absolute positions of all the text. So my question would be, is there a converter that would create an html file in the actual 8.5 x 11 size that anyone knows of? And don't say, Acrobat, cause their conversion doesn't even come close to looking like the original document. Any insight on this matter would be greatly appreciated.
  3. I have a form that I decided to include Google recaptcha as an added measure of security. When I added the recaptcha it triggers an error because the recaptcha is not whitelisted. I read that HTML5 does not allow assigning the name attribute to div. i.e. <div name="myName"></div>. Against convention, I tried adding a name to the recaptcha div and adding that name to the whitelist. That approach failed. There is an iframe within the div that has the name attribute. I tried using the iframe name in the whitelist. That approach also failed. There is a hidden input that has an id="recaptcha-token". I added 'recaptcha-token' to the whitelist. This approach also failed. The hidden input is generated by the recaptcha api, so I don't think I have a means of assigning a name attribute to this input. Does anyone have a workaround or suggestion ? Note: form validation and whitelist all worked as expected prior to adding recaptcha. This is the div within the form. <div class="row"> <div class="col-md-12"> <div class="g-recaptcha" data-sitekey="<?php print $public_key;?>"></div> </div> </div> This is the code block using the whitelist. // VERIFY LEGITIMACY OF TOKEN if (verifyFormToken('form1')) { // Building a whitelist array with keys which will send through the form, no others would be accepted later on $whitelist = array('token','req-fName','req-lName','req-email','req-phone','req-address','req-city','req-state','req-zip','req-message','req_method','req-dateDepart','req-dateReturn','recaptcha-token','submit'); // Building an array with the $_POST-superglobal foreach ($_POST as $key=>$item) { // Check if the value $key (fieldname from $_POST) can be found in the whitelisting array, if not, die with a short message to the hacker if (!in_array($key, $whitelist)) { writeLog('Unknown form fields'); die('Hack-Attempt detected. Only the fields originally included in the form are allowed!'); } } } Thanks in advance for having a look at this.
  4. I'm having an issue related to creating forms within a foreach loop. As of now, I have 3 forms in a div, each with their own datepicker instance and submit button ( also using a hidden input for the pageID) The datepickers are unique and working independently, but when it comes to posting the data via ajax and handling it in a php script, It's not inserting data into my db because the names of my two inputs are not unique. I don't really know how to make them unique on the form and then handle those unique names back in the script. Only one form will be submitted at a time so I'm trying to make it to where the user can click on any of these datepickers, select a date and submit, and the ajax will handle only the page ID and the datepicker value for that form submitted and the PHP script will then insert. The sql in my php script works but my POST variables are where I'm having the issue here. Any help is much appreciated. <?php foreach($expiredPages as $expiredPage): ?> <form id="updateTime_<?php echo $expiredPage['id']?>" class="updateTime" method="POST"> <input type="hidden" name="currentPageID<?php echo $expiredPage['id']?>" value="<?php echo $expiredPage['id']?>"> <div class="datepick input-group date" id="datetimepicker_<?php echo $expiredPage['id']?>" data-target-input="nearest"> <input type="text" class="form-control datetimepicker-input" data-target="#datetimepicker_<?php echo $expiredPage['id']?>" name="datePicker<?php echo $expiredPage['id']?>" /> <span class="input-group-addon" data-target="#datetimepicker_<?php echo $expiredPage['id']?>" data-toggle="datetimepicker"> <span class="fa fa-calendar"></span> </span> </div> <input type="submit" name="Extend Date" class="extendDate"> </form> <?php endforeach; ?> <script type="text/javascript"> $(".extendDate").click(function(){ event.preventDefault(); var string = $('.updateTime').serialize(); console.log(string); // AJAX Code To Submit Form. $.ajax({ type: "POST", url: "extendTime.php", data: string, dataType: 'json', cache: false, success: function(response){ location.reload(); } }); }); </script> extendTime.php $pageID = $_POST['currentPageID']; $newTime = $_POST[$dtPick]; $newEndTime = DateTime::createFromFormat('m/d/Y h:i A', $newTime); $convertedDateTime = $newEndTime->format('Y-m-d H:i:s'); $extendExpiration = " UPDATE pages SET end_time = '$convertedDateTime' WHERE id = '$pageID'; "; if($mysqlConn->query($extendExpiration)=== TRUE){ echo "SUCCESS"; }else{ echo "Could not extend Time"; }
  5. Hi all, I currently have a table listed, with one of the rows being hyperlinked and linking to an input form, should be autopopulated from the code (ID or other unique identifier) of the row, however, when clicking the link the form does not load. I will insert relevant code to this thread and if anyone would be able to shed some light on this that would be great. NOTE: SQL code has already been tested using PHPMyAdmin and works fine. Although, it may need changed to help with this issue - I'm not quite sure. Please see screenshots for relevant code.
  6. As the browser is made smaller, or the text larger, and a text line no longer can be placed on a single line, is there an event that signals the browser to wrap it? Is this an event which can be used? Say the text line was contained within a div element. Could I recognize a 'wrap' event, if there is one, for text within that div element? Thank you.
  7. In the following pages I'm trying to validate if a user is signed in or not. If the user is signed in I would like to see 'Log Out' printed to the screen(I'll do more with that later). If the user is not signed in I would like to see a login form at the top right of the screen. As it stands I'm only seeing 'Log Out' on the screen, I can't get the form to show up anymore. I thought it might be because the session variable was still hanging around but I restarted my computer to make absolutely sure but I'm still just getting 'Log Out'. At the moment I need this program to work as is as much as possible. If you see an entirely different approach that you would use that's fine but I don't currently have the time to go changing a lot, I need to get this going kinda quick. Thanks. records-board.php <?php require_once('includes/init.php'); if(!isset($_SESSION)) { init_session(); } ?> <html> <head> <Title>Pop Report</title> <link rel="stylesheet" type="text/css" href="styles/popreport2.css"> <h1>Pop Report</h1> </head> <body> <?php if(isset($_POST['nameinput']) && isset($_POST['passinput'])) { $nameinput = $_POST['nameinput']; $passinput = $_POST['passinput']; User::sign_in($nameinput, $passinput); } if(!isset($_SESSION['user'])) { print_form(); } else { echo "Log Out "; echo $_SESSION['user']->name; // this line was just trouble shooting, it told me nothing! } ?> user.php <?php if(!isset($_SESSION)) { init_session(); } class User { public $name; public function __construct($username, $password) { $connection = get_db_connection(); $query = $connection->query("SELECT * FROM users WHERE username='$username' AND password='$password'"); if(!$query) { echo "Invalid username or password"; } else { $result = $query->fetch(PDO::FETCH_ASSOC); if(!$result['username'] == $username || !$result['password'] == $password) { echo "Invalid username or password"; } else { $this->name = $result['username']; } } } public static function sign_in($username, $password) { $_SESSION['user'] = new User($username, $password); } } ?> <?php function print_form() { echo "<form id='loginform' name='loginform' action='records-board.php' method='post'>"; echo "Username: <input type='text' name='nameinput'>"; echo "Password: <input type='text' name='passinput'><br />"; echo "<input type='submit' value='Sign In'>"; echo "</form>"; } ?>
  8. Great site!, Im trying to understand a bit more pdo.. I have the following: I have a svg and when I click on the map the country name is loaded into a var on the click event by the code below: <script> function fill_contact(evt) //display click event { var country_id = evt.target.id document.getElementById('country_name').firstChild.data = country_id } </script> My php code is as follows: <?php //Define constants define('DB_DRIVER', "mysql"); define('DB_SERVER', "127.0.0.1"); define('DB_DATABASE', "aeea"); define('DB_USER', "root"); define('DB_PASSWORD', "root"); //Database connection try { $dbh = new PDO(DB_DRIVER . ":dbname=" . DB_DATABASE . ";host=" . DB_SERVER, DB_USER, DB_PASSWORD); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch(PDOException $e){ die("Sorry, we could not connect you to this database, please contact the Administrator to sort this out.". $e->getMessage()); } //Get data $query = "SELECT firstname, lastname, email, photo FROM reps WHERE country like ?"; $country = 'country_name'; //Create the statement $stmt = $dbh->prepare($query); $stmt->execute(array($country)); //Use data $row = $stmt->fetch(PDO::FETCH_ASSOC); echo '<pre>', print_r($row), '</pre>'; ?> My Html code is as follows: <div id="IndexPage"> <div id="IndexPage_Left"> <div id="IndexPage_Left_top"> <h3>Country: <span class="label" id="country_name"> </span></h3><!—This works fine--> <p></p> <h4>Regional Representative: <span class="label" id="firstname"> </span></h3></h4><!--get Rep ” firstname, lastname” from database based on country from svg to display--> <p></p> <h4>Photo</h4><!--get Rep “photo” from database based on country from svg to display--> <p></p> <input style='margin-top: 20px;' type="submit" value="Contact me." id='jqxSubmitButton' /><!-- if clicked, it opens a contact form below, the email address is hidden--> </div> <div id="IndexPage_Left_bottom"> <h4>email form here<h4><!-- if email is clicked, it opens a contact form here with “email” address from database --> </div> </div> <div id="IndexPage_Right"> <svg id="map" version="1.1" and rest of svg code. My database has a table called reps. It had dta of representatives in each country in Africa. It has a number of fields ie. rep_id(unique indexed), firstname, lastname, email, postal, city, state, country, contact_no, photo etc. I want to be able to get the fields in the database and display them in the html form on the click events. Ie. The database must also refresh the query every time a click event happens. Guests might click a few countries to look at reps. If they click off the map, it blanks out the details. How do I go about doing this? I’ve heard about XMLHttpRequest but don’t know how to go about doing it. Another question: Once I get the information, how do I display it correctly in the Html? I used <span>, but is it correct? Last question: Once I get the information email address, how do I show a contact form on "conact me" button? and then when guests click on another country, remove the contact form? This is my first website. Please help
  9. adke001458

    href to php function

    Hello, I have created a webpage that essentially generates an sql query and then puts the results into a table that is displayed. On one of the columns in this displayed table, I want to allow the user to click on each of the values which will in turn execute a php function. I have the hyperlink working but this is to a separate page. What I actually need to do is firstly - just ran a php function that will create a new table beneath the currently displayed one. Secondly, once this is achieved, I need to pass some value to the function so that the generated table is dependent on the value that was clicked. I've tried a few things and researched but I am struggling. I am a beginner. Any help would be greatly appreciated. Here is an extract of the code used for inputting data into the original table - showValuesSR is the function name <?php while (!$rsMetrics->EOF) { ?> <tr> <?php for ($x=0; $x<$numberOfFields; $x++) { if ($fieldNames[$x] == "Values_SR"){ ?> <td><a href= ?showValuesSR><?php echo $rsMetrics->fields[$fieldNames[$x]]->Value?></a></td> <?php } else{ ?> <td><?php echo $rsMetrics->fields[$fieldNames[$x]]->Value?></td> <?php } } ?> </tr> <?php $rsMetrics->MoveNext(); } ?> </table> <?php function showValuesSR(){ ?> <table border="0" cellpadding="5" width="100%"> <tr><td background="../images/table_toolbar_bkg.gif" align="center"><font color="Blue" face="verdana" size="2"><strong>function working</strong></td></tr> </table> <?php } ?>
  10. I am running this query and the only thing i want is the title and for some reason it is giving me this. Recourse id # 7 ? Here is my query that i am running. $photo = $_GET['image']; $retrievetitle = "SELECT title FROM photo_from_user WHERE picture = '$photo' limit 1"; $title = mysql_query($retrievetitle);
  11. fanboime

    Help with JSON in PHP

    here is my insert method public function add($values) { $sql = "insert into vehicles(`vehicle_plates`,`DA`,`type`, `model`, `driver`) values('$values')"; if(!mysql_query($sql)) { $this->error = mysql_error(); return true; } else { return false; } } And here is my Button click funtion $( "#button" ).button(); $( "#button" ).click(function( event ) { <?PHP if(isset($_POST["subBtn"])) { $fName = $g->clean($_POST["fullname"],1); $sDate = date('Y-m-d', strtotime($_POST["startdate"])); $roomNum = $g->clean($_POST["roomnumber"]); $driver = $g->clean($_POST["driver"],1); $model = $g->clean($_POST["model"],1); $json = '{"a":$fName, "b":$sDate, "c":$roomNum, "d":$model, "e":$driver}'; $array = json_decode($json, true); $values = implode(",", $array); $g->add($values); } ?> }); Everytime i click my button it Postsback and nothing inserts in my database...
  12. Pawan_Agarwal

    re-direct php page with ajax

    I know how to implement ajax with php and get output with the help of java-script and ajax... Well, I am just trying to re-direct the page using ajax, but, it is not happening........ What I am doing is that after user logged-in successfully, the email and password are going to check by ajax and if the inputs are correct, the page must re-direct to another page... So, far I am able to verify the correct details, but, the page is not re-directing... You must also see that I want to re-direct the page with ajax only................I am able to redirect the page with java-script but I do not want to include re-direction with java-script in my website !! Thanks for helping me out !!
  13. Hello everyone, i'm Osiris and i'm stuck with this PHP/HTML code, i'm fairly new at this so this might be a dumb question. i have a database, but i want to output all data into a table from the database using HTML codes. i had it so far that i could outpust the info in just plain text but it doesn't output in the HTML table. Can anyone see what i did wrong? This is my PHP code its in the body section <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'password'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); if(! $conn ) { die('Could not connect: ' . mysql_error()); } $sql = 'SELECT `Name`, `Color`, `Type`, `Subtype`, `Power`, `Toughness`, `Manacost`, `Rarity`, `Expansion`, `Foil`, `Stock` FROM `mtgtabel`'; mysql_select_db('mtgstock'); $retval = mysql_query( $sql, $conn ); if(! $retval ) { die('Could not get data: ' . mysql_error()); } echo '<table class=mytable>'; echo "<tr><th >Name</th><th >Color</th><th >Type</th><th >Sub Type</th><th >Power</th><th >Toughness</th><th >Converted mana cost</th><th >Rarity</th><th >Expansion</th><th >Foil</th><th >Stock</th></tr>"; while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) { echo "<tr><td>"; echo $row['Name'] echo "</td><td>"; echo $row['Color']; echo "</td><td>"; echo $row['Type']; echo "</td><td>"; echo $row['Subtype']; echo "</td><td>"; echo $row['Power']; echo "</td><td>"; echo $row['Toughness']; echo "</td><td>"; echo $row['Manacost']; echo "</td><td>"; echo $row['Rarity']; echo "</td><td>"; echo $row['Expansion']; echo "</td><td>"; echo $row['Foil']; echo "</td><td>"; echo $row['Stock']; echo "</td></tr>"; } echo "</table>"; mysql_close($conn); ?> Thanks in advance!
  14. There is no SEO section so I do not know where exactly to ask this question, but here it is. https://www.google.ca/?gfe_rd=cr&ei=jgm3VIqFNtCy8wfH3YD4CA#q=twitter.com Do you see how Google lists Twitter results in two columbs underneath the main heading title? How does one achieve that result with their website? Does only Google decides to make it show up that way?
  15. I ran into this confusion while trying to write a script for uploading a file using AJAX which would work in IE8. Apparently there is a hack to achieve this which involves the usage of iframes. What I've tried so far is submitting a form with just action attribute which redirects to another page. <form method="post" action="test.php"> <input type="text" name="name" /> <input type="submit" name="send" value="Send" /> </form> Even if I set the attribute to _self(default value), the page redirects to test.php and shows what ever is printed by the php script. Now when I set the target to _blank, the page test.php opens in a new tab and shows what ever is printed by the php script. <form method="post" action="test.php" target="_blank"> <input type="text" name="name" /> <input type="submit" name="send" value="Send" /> </form> And if I set the target to an iframe name present in the same page, the php response is printed in the iframe(which is the hack to upload a file) <form method="post" action="test.php" target="some_frame"> <input type="text" name="name" /> <input type="submit" name="send" value="Send" /> </form> <iframe name="some_frame" /> So what I want to know is how does the action and target attribute work once the form is submitted? When the target attribute is set to _self, the page redirects and then prints(action first and then target), but if the target attribute is set to _blank, first a new tab is opened and then the response is printed(first the target and then action) and when the target attribute is set to a frame_name, it prints within the frame(does it load the response from the page into the frame?). It would be really helpful if someone could assist me with a link or an explanation of the flow of a form submission, the order of execution of the action and target attributes and how do they work and in what order do they run.
  16. matt20687

    PHP/SQL Nightmare

    Hey, I have an issue where the below script doesnt appear to be working. It doesnt actually display anything on the page, it seems as though after the first PHP tag is just ignores the rest of the script. when looking at the page source all it shows is: <HTML> <HEAD> <TITLE>Logs</TITLE> </HEAD> <BODY> The actual code is below: <HTML> <HEAD> <TITLE>Logs</TITLE> </HEAD> <BODY> <?PHP $mysqlserver="localhost"; $mysqlusername="root"; $mysqlpassword="test"; $dbname = 'test'; $con=mysqli_connect($mysqlserver, $mysqlusername, $mysqlpassword, $dbname); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $result = mysqli_query($con, "SELECT * FROM forwardtable"); echo "<table border='1'> <tr> <th>Acc Num</th> <th>Send Date</th> <th>Send Time</th> </tr>"; while($rowContent = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $rowContent['Acc'] . "</td>"; echo "<td>" . $rowContent['Date'] . "</td>"; echo "<td>" . $rowContent['Time'] . "</td>"; echo "</tr>"; } echo "</table>" ?> </BODY> </HTML> If I remove the PHP from within the code the source code goes as it should and shows the </BODY> and </HTML> tags. Any ideas anyone? Thanks, Matt
  17. iannet14

    Load 2 element in frame

    Hi I have a frame that load a php element, but I want to load at same time a javascript element. The code load correctly the php element in the frame but I can't figure out where to insert the javascript. The javascript is a slide in ads. Here is the code of the php element : <frame src="<?php echo getRandomInterstitualAdUrl(); ?>" noresize/> And here is the javascript code : <script type="text/javascript" src="http://exemple.com/adServe/banners?tid=L_16601_7&type=slider&position=bottom&animate=on&side=left&size=300x250" ></script>
  18. Hi everyone, i recently purchased the jbjobs component for joomla and have been modifying the views to suit my needs. i've reached a dead end though. i have a php bit that needs to be combined with a table, but i have not managed to make it work. can someone please lend a hand? thanks <?php $db=JFactory::getDBO(); $q = "select * from #__jbjobs_employer where user_id=".$job->employer_id; $db->setQuery($q); $employer_record = $db->loadObject(); '<table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td>';echo ($employer_record->show_addr == 'y')? "".$employer_record->street_addr : JText::_('JBJOBS_NOT_DISPLAYED').'</tr> <tr> <td>'; echo ($employer_record->show_location == 'y')? "".$employer_record->city.', '.$employer_record->state : JText::_('JBJOBS_NOT_DISPLAYED').'</td> </tr> <tr> <td>'; echo ($employer_record->show_phone == 'y')? "".$employer_record->primary_phone : JText::_('JBJOBS_NOT_DISPLAYED').'</td> </tr> <tr> <td>'; echo ($employer_record->show_fax == 'y')? "".$employer_record->fax_number : JText::_('JBJOBS_NOT_DISPLAYED').'</td> </tr> <tr> <td>'; $u = JFactory::getUser($job->employer_id); echo ($employer_record->show_email == 'y')? "".$u->email : JText::_('JBJOBS_NOT_DISPLAYED');'</td> </td> </tr> </table>' ?>
  19. carlitosfigue

    Problem with Login form.

    Hello guys, first post here. I have a web system which contains a login form programmed in 3 different languages HTML, PHP and JS. The problem is that it's not working, you can access without entering any data, you just press enter and it will work, I don't know why it is not validating any credentials. I was thinking about some query problems but I don't know. I am a newbie on this. I have read a lot but haven't found an answer. A friend helped me build the system but left that uncompleted and he's nowhere to be found. I was wondering if you could help me out with this. <form role="form" ng-submit="login(user,password)"> <div class="form-group"> <input type="user" class="form-control" ng-model='user' placeholder="Usuario"> </div> <div class="form-group"> <input type="password" class="form-control" ng-model='password' placeholder="Contraseña"> </div> <div class="alert alert-warning" id='alert' style="display:none">Revise la informacion...</div> <div class="alert alert-danger" style="display:none" id='alertErr'>Error Usuario o Contraseña Erronea intentelo de nuevo</div> <button type="submit" class="btn btn-primary">Ingresar</button> </form> <?php require_once 'database.php'; $db = new Database(); $body = json_decode(file_get_contents('php://input')); $user =$db->query("SELECT * FROM usuario WHERE usua_login = '".$body->user."' AND usua_pass = '".$body->password."'"); if($user == false){ http_response_code(404); } else{ http_response_code(200); echo json_encode($user); } ?> 'use strict'; /** * @ngdoc function * @name belkitaerpApp.controller:MainCtrl * @description * # MainCtrl * Controller of the belkitaerpApp */ angular.module('belkitaerpApp') .controller('MainCtrl', function ($scope,$http,$location) { $scope.login = function(user,password){ console.log('Login...'); if(user =='' || password ==''){ $('#alert').show("slow"); setTimeout(function() { $('#alert').hide('slow'); }, 3000); } else{ $http.post('../serverSide/login.php',{user:user,password:password}).success(function(data){ console.log('OK!'); $location.path('/products'); }).error(function(data){ $('#alertErr').show("slow"); setTimeout(function() { $('#alertErr').hide('slow'); }, 3000); }); } } });
  20. I have a page that displays about 12 tables that are filled from database values. These values correspond with a single record but some of these fields are based off of queries I'm making so that if something's wrong in the query, it will display red text. I'm only doing this for a few different fields but I want an option to edit and fix those fields and then save them to the database with an UPDATE. Basically, I don't want to wrap the whole page in a form since only a few fields in a few of the tables will need to be editable. Is there a way to do this so that I can edit only the few fields that need to be fixed? Here's a table as example: <div class="testResults" style=" width: 30%; clear:both; float: left;"> <!--Test Results Table--> <table style="width: 100%;"> <tr> <th colspan="2">Test Results</th> </tr> <tr> <td style="text-align: left;">Tested Within AWWA Standards</td> <td><? echo $row['standards'];?> </td> </tr> <tr> <td style="text-align: left;">Meter Failed on Low Side</td> <td><? echo $row['lowFail'];?> </td> </tr> <tr> <td style="text-align: left;">Meter Failed on High Side</td> <td><? echo $row['highFail'];?> </td> </tr> <tr> <td style="text-align: left;">Meter Failed Low and High Side</td> <td><? echo $row['bothFail'];?> </td> </tr> <tr> <td style="text-align: left;">Unable To Test</td> <td><? echo $row['unableTest'];?> </td> </tr> </table> So, for example, say I want to edit the data for just standards row and lowFail row. I tried this but it didn't work: <td><input type="text" name="test8TRGPM" value="<? echo $row['test8TestRateGPM'];?>"> </td> I know once this is done I'll need to have a submit button that attaches to a query to update with the input name, but right NOw i'm trying to find the best way to edit. Is it easiest to just wrap the whole page in a form and just create the few inputs where I need?
  21. Hi everyone, I'm trying to get my head around blending in and out of php and html. I've seen some simple examples which work great but now I have this variable that comes from the database and I would like to style the variable in-line with html markup. Here's what I'm trying to do: <?php echo "Price : ",'<Font size="100"> $tournament["pricePerPlayer"] </font>'; ....more of the same code goes here... ?> I can't get $tournament["pricePerPlayer"] to be controlled by the font tag. How do I do this? Any help would be greatly appreciated. Thanks,
  22. finder.com.au is making waves in the comparison space, and we are expanding our Design & Technology team massively this year. We are looking for several full-stack Senior PHP Developers who will be responsible for building a wide variety of web-based applications (using PHP and MySQL) in addition to maintaining existing PHP code, optimizing website and database performance and developing custom PHP solutions. This is a great opportunity for web people at heart to join a growing team delivering awesome products that get used by hundreds of thousands of users. As a developer at finder.com.au you will have the freedom, autonomy, and responsiblity to improve the code, tools, and architecture without having to cut through red tape. Why finder.com.au? We've just been named one of the top service companies in the Asia Pacific for 2014, taking silver in the Stevie Awards for Australian Service Company of the year. We’ve also been dubbed one of Anthill’s 50 coolest companies in Australia for 2013 thanks to our amazing team, wonderful users and cool company culture. As a development team, we move quickly, releasing code several times per day. You need to be willing to move fast, rely on automation, make decisions on less than perfect information, trust your teammates, and constantly strive to improve. A new Head of Design and Technology, with experience at two of local startup scene’s biggest success stories, recently joined us to lead the team on a mission to speed up the entire company to become the Australian brand for comparison. The team runs hackdays every other month that give all developers free time to show off their creativity and innovation. You will have choice of OS, laptop or desktop, IDE and toolset, and up to 3 monitors. What’s more, you will experience an ultra modern office located in the heart of the Sydney CBD, catered lunches and breakfast supplied every day and all the snacks and drinks you want! Who are you? You live and breathe development and your code has soul. You are a great PHP coder that wants to join a team where you can flex your skills and grow further. You are an expert who understands complex problems and enjoys deploying solutions to business problems. You are keen to get your projects live and solve business problems and improve the development environment and tooling. You also have experience in getting code live multiple times per day. You may be applying from overseas – We are happy to provide support with sponsored relocation services. We already have a number of people on our team from overseas so you will be joining a community. Must have experience: 4+ years of PHP development experience for Senior Roles Experience with phpunit Knowledge of CI tools (Bamboo, Travis, CircleCI) Knowledge of CD tools (Beanstalk, Capistrano) Knowledge of Git Ability and desire to use and extend Git tools (GitHub, Bitbucket) to enhance workflow Ability to mentor junior developers Experience with Wordpress beneficial Knowledge of Front End technologies beneficial Knowledge of monitoring tools beneficial Please send us a resume to iwantin@finder.com.au and optionally provide us with a link to your GitHub or Bitbucket profile and a personal note as to why you would want to work with us at finder.com.au.
  23. I have HTML form linked with MYSQL database via PHP. If I submit this form, values will save in MYSQL database but not load into form. I see there old values so I have to refresh page to see desired values. I would like to see new values at form submission. *** I solved it when i put header("Location: edit.php?page=zakladni_udaje.php") ( = same as form action) on THE END OF ISSET form submit, it worked fine but I cant print message about success or fail after submiting. <?php ob_start(); session_start(); ?> <form action="edit.php?page=zakladni_udaje.php" method="post"> <?php $con = mysql_connect("localhost", "mairichovci", "ak41801") or die("Nelze se připojit k MySQL: " . mysql_error()); mysql_select_db("mairichovci") or die("Nelze vybrat databázi: ". mysql_error()); if($_SESSION['id'] > 0){ $profil_pomocny = mysql_query("SELECT * from profil where id=".$_SESSION['id'], $con); $profil = MySQL_Fetch_Assoc($profil_pomocny); $or_pomocny = mysql_query("SELECT * from osobaky where id=".$_SESSION['id'], $con); $or = MySQL_Fetch_Assoc($or_pomocny); $zobraz_pomocny = mysql_query("SELECT * from zobraz where id=".$_SESSION['id'], $con); $zobraz = MySQL_Fetch_Assoc($zobraz_pomocny); $id = $_SESSION['id']; $fce = $_POST['fce']; $email = $_POST['email']; $tel = $_POST['tel']; $position = $_POST['position']; $home = $_POST['home']; $omne = $_POST['omne']; if( isset ($_POST['uloz'])): $sql = "UPDATE profil SET fce = '$fce', email = '$email', tel = $tel, position = '$position', home = '$home', omne = '$omne' WHERE id = '$id'"; if (!mysql_query($sql)): die('Chyba: ' . mysql_error()); else: $message = "Údaje byly uloženy"; endif; mysql_close(); endif; echo '<div id="message">'.$message.'</div>'; ?> <table style = "margin-top: -1px" align="center" class="tabulka"> <tr> <td width="40%">Funkce:</td> <td><input type="text" name="fce" placeholder = "(např. Běžec - 800m, 1500m a delší)" maxlength="35" size="48" value="<?php echo $profil['fce']; ?>" class="vstupy" style="width: 350px"></td> </tr> <tr> <td></td> <td><input type="submit" name="uloz" value="Ulož" class="tlacitko2" style="width: 350px; margin-left:4px"></td> </tr> </table> </form> <?php } else{header("Location: prihlas.php");} ob_end_flush(); ?> Can anybody help me? Thanks in advance
  24. oobradersoo

    variables

    hello there people does any one know how to store a group of variables inside 1 variable. so if i had ($1, $2, $3, $4 ........) i am wanting to store them in 1 variable like so $list
  25. I'm trying to learn jquery and ajax and not doing so well I am trying to pass the id from this dropdown when it is selected to the next ajax script and it is not working. Both scripts pull there data from the same table so if there is a way to do this with one script I would be interested. <select name="customer"id="customer" class="form-control input-sm responsetext" > </select> $( document ).ready(function() { $.ajax({ //create an ajax request to load_page.php type: "GET", url: "customer.php", dataType: "html", //expect html to be returned success: function(response){ $(".responsetext").html(response); //alert(response); } }); }); <?php include("connect.php"); $id = $_SESSION['profile']['id']; echo "<option value=''>SELECT A CUSTOMER</option>"; foreach($db->query("SELECT * FROM customers WHERE pid = '$id'") as $row) { echo "<option value=" . $row['id'] . ">" .$row['name'] . "</option>"; } The above script creates the select box and it works. Now I need the $row['id'] To be picked up by the next script to fill in the input field. <input name="contact" class="form-control input-sm contactresults" id="contact"> $(function() { // document.ready $("#id").on("change", function() { $.ajax({ url: "contact.php", type: "GET", data: { id: $(this).val() }, success: function(data) { $(".contactresults").html(data); } }); }); }); <?php include("connect.php"); $id= $row['id']; echo "<option value=''>SELECT A CUSTOMER</option>"; foreach($db->query("SELECT * FROM customers WHERE id = '$id'") as $row) { echo $row{contact"}; }
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