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Found 216 results

  1. exceedinglife

    Php bootstrap 4 email from form

    Hello all, I have a website with a form that I want a user to fill out then if it is valid I have the button submit and I want it to email me. The message. If success full I want a message to popup on screen saying success I am using bootstrap 4 <div class="messageSuccess"></div> <div class="row"> <div class="col-md-9 mb-md-0 mb-5"> <form id="contact-form" name="contact-form" action="" method="post"> <!--action="contactEmail.php" --> <div class="row "> <div class="col-md-6 "> <div class="md-form mb-0 "> <input class="form-control" type="text" id="txtName" name="txtName" required /> <label for="txtName">Your Name </label> <div class="nameError"></div> </div> </div> <div class="col-md-6 "> <div class="md-form mb-0 "> <input class="form-control" type="text" id="txtEmail" name="txtEmail" required /> <label id="lblEmail" for="txtEmail">Your Email Address </label> </div> </div> </div> <div class="row"> <div class="col-md-12"> <div class="md-form mb-0"> <input class="form-control" type="text" id="txtSubject" name="txtSubject" data-error="Subject Here" required /> <label for="txtSubject">Subject </label> <div class="help-block with-errors"></div> </div> </div> </div> <div class="row"> <div class="col-md-12"> <div class="md-form"> <textarea class="form-control" type="text" id="txtMessage" name="txtMessage" rows="4" required data-error="Please leave us a message."></textarea> <label for="txtMessage">Your Message </label> </div> </div> </div> <div class="text-center text-md-left"> <input type="submit" id="BtnFormSubmit" class="btn btn-primary btn-xl text-white" value="Send Message" /> </div> <div class="status"></div> </form> <!-- JavaScript Inner File Form Validation --> <script type="text/javascript"> $(document).ready(function () { var form = $("#contact-form"); var name = $("#txtName").val(); var email = $("#txtEmail").val(); var subject = $("#txtSubject").val(); var message = $("#txtMessage").val(); var btnSubmit = $("BtnFormSubmit"); $(form).submit(function (event) { if (this.checkValidity() == false) { $(this).addClass("was-validated"); event.preventDefault(); event.stopPropagation(); } alert("Form Valid to create message"); if (!event.isDefaultPrevented) { alert("passed prevent default"); var url = "testemail.php"; // POST values 'ajax' $.ajax({ type: "POST", url: url, data: $(this).serialize(), success: function (data) { // done: // data = JSON object object for contactEmail.php // recieve message type: success | danger var messageAlert = "alert- " + data.type; var messageText = data.message; // Bootstrap alert box HTML var alertBox = '<div class="alert ' + messageAlert + ' alert-dismissable"><button type="button" class="close" ' + 'data-dismiss="alert" aria-hidden="true">&times;</button>' + messageText + '</div>'; // if messageAlert and messageText if (messageAlert && messageText) { // Put message on page in messageSuccess section. $(form).find("#messageSuccess").html(alertBox); // Reset the form. $(form)[0].reset(); } } }); //return false; } }); //$(name).blur(function () { //}) // Validate :inputs $(":input").blur(function () { let controlType = this.type; switch (controlType) { case "text": case "password": case "textarea": validateText($(this)); break; case "email": validateEmail($(this)); break; default: break; } }); // each :input focusin remove existing validation messages if any. $(":input").click(function () { $(this).removeClass("is-valid is-invalid"); }) /* OPTIONAL ':input' KEYDOWN validation messages remove */ // Reset Form and remove all validation messages. $(":reset").click(function () { $(":input").removeClass("is-valid is-invalid"); $(form).removeClass("was-validated"); }); }); // Validate Text Function function validateText(control) { let textField = control.val(); if (textField.length > 1) { $(control).addClass("is-valid"); } else { $(control).addClass("is-invalid"); } } // Validate Email Function (Email newer regex: /^([\w-\.]+@([\w-]+\.)+[\w-]{2,6})?$/ ) function validateEmail(control) { let textField = control.val(); let regexPattern = /^\b[A-Z0-9._%-]+@[A-Z0-9.-]+\.[A-Z]{2,6}\b$/i; if (regexPattern.test(textField)) { $(control).addClass("is-valid"); } else { $(control).addClass("is-invalid"); } } </script> <?php $from = 'SampleEmail@YourEmail.com'; $sendTo = 'sample@Gmail.com'; $subject = 'Your Message Subject Here';// Email Message Contact Form Fields // Array - ($varName => Text from controls) $controls = array('txtName' => 'Name', 'txtEmail' => 'Email', 'txtSubjext' => 'Subject', 'txtMessage' => 'Message'); $successMessage = 'Contact Message Successfully Sent. Thank you, I will get back to you soon.'; $errorMessage = 'There was an error submitting your message, Please try again. Or try later.'; error_reporting(E_ALL & ~E_NOTICE); try { if(count($_POST) == 0) throw new \Exception('Contact Form Message is empty'); $emailText = "You have a new message from your contact form\n------------------------------------------------------\n"; foreach($_POST as $key => $value) { if(isset($controls[$key])) { $emailText .= "$controls[$key]: $value\n"; } } $headers = array('Content-Type: text/plain; charset="UTF-8";', 'From: ' . $from, 'Reply-To: ' . $from, 'Return-Path: ' . $from, ); // Send email mail($sendTo, $subject, $emailText, implode("\n", $headers)); $responseArray = array('type' => 'success', 'message' => $successMessage); } catch(\Exception $e) { $responseArray = array('type' => 'danger', 'message' => $errorMessage); } // If AJAX request return JSON response **RARE** if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') { $encodedJSON = json_encode($responseArray); header('Content-Type: application/json'); echo $encodedJSON; } else { echo $responseArray['message']; } ?>
  2. ttsprez

    Pdf to html Converter needed

    So I've done a search for pdf to html converters and there are plenty of free online options. The only problem is that they don't convert the pdf to html in an actual 8.5 x11 size, so that when you go to print or use them to be filled by code and then printed, they are to small. Now, some would say, simply resize the html file, but the issue there is when created it actually consists of two files. One an html file with absolute position values for all your text and the second as a jpeg for any backgrounds, frames or images. You can adjust the size of the background, borders and images, but then that would also mean you'd have to go line for line in the html to adjust the absolute positions of all the text. So my question would be, is there a converter that would create an html file in the actual 8.5 x 11 size that anyone knows of? And don't say, Acrobat, cause their conversion doesn't even come close to looking like the original document. Any insight on this matter would be greatly appreciated.
  3. I have a form that I decided to include Google recaptcha as an added measure of security. When I added the recaptcha it triggers an error because the recaptcha is not whitelisted. I read that HTML5 does not allow assigning the name attribute to div. i.e. <div name="myName"></div>. Against convention, I tried adding a name to the recaptcha div and adding that name to the whitelist. That approach failed. There is an iframe within the div that has the name attribute. I tried using the iframe name in the whitelist. That approach also failed. There is a hidden input that has an id="recaptcha-token". I added 'recaptcha-token' to the whitelist. This approach also failed. The hidden input is generated by the recaptcha api, so I don't think I have a means of assigning a name attribute to this input. Does anyone have a workaround or suggestion ? Note: form validation and whitelist all worked as expected prior to adding recaptcha. This is the div within the form. <div class="row"> <div class="col-md-12"> <div class="g-recaptcha" data-sitekey="<?php print $public_key;?>"></div> </div> </div> This is the code block using the whitelist. // VERIFY LEGITIMACY OF TOKEN if (verifyFormToken('form1')) { // Building a whitelist array with keys which will send through the form, no others would be accepted later on $whitelist = array('token','req-fName','req-lName','req-email','req-phone','req-address','req-city','req-state','req-zip','req-message','req_method','req-dateDepart','req-dateReturn','recaptcha-token','submit'); // Building an array with the $_POST-superglobal foreach ($_POST as $key=>$item) { // Check if the value $key (fieldname from $_POST) can be found in the whitelisting array, if not, die with a short message to the hacker if (!in_array($key, $whitelist)) { writeLog('Unknown form fields'); die('Hack-Attempt detected. Only the fields originally included in the form are allowed!'); } } } Thanks in advance for having a look at this.
  4. I'm having an issue related to creating forms within a foreach loop. As of now, I have 3 forms in a div, each with their own datepicker instance and submit button ( also using a hidden input for the pageID) The datepickers are unique and working independently, but when it comes to posting the data via ajax and handling it in a php script, It's not inserting data into my db because the names of my two inputs are not unique. I don't really know how to make them unique on the form and then handle those unique names back in the script. Only one form will be submitted at a time so I'm trying to make it to where the user can click on any of these datepickers, select a date and submit, and the ajax will handle only the page ID and the datepicker value for that form submitted and the PHP script will then insert. The sql in my php script works but my POST variables are where I'm having the issue here. Any help is much appreciated. <?php foreach($expiredPages as $expiredPage): ?> <form id="updateTime_<?php echo $expiredPage['id']?>" class="updateTime" method="POST"> <input type="hidden" name="currentPageID<?php echo $expiredPage['id']?>" value="<?php echo $expiredPage['id']?>"> <div class="datepick input-group date" id="datetimepicker_<?php echo $expiredPage['id']?>" data-target-input="nearest"> <input type="text" class="form-control datetimepicker-input" data-target="#datetimepicker_<?php echo $expiredPage['id']?>" name="datePicker<?php echo $expiredPage['id']?>" /> <span class="input-group-addon" data-target="#datetimepicker_<?php echo $expiredPage['id']?>" data-toggle="datetimepicker"> <span class="fa fa-calendar"></span> </span> </div> <input type="submit" name="Extend Date" class="extendDate"> </form> <?php endforeach; ?> <script type="text/javascript"> $(".extendDate").click(function(){ event.preventDefault(); var string = $('.updateTime').serialize(); console.log(string); // AJAX Code To Submit Form. $.ajax({ type: "POST", url: "extendTime.php", data: string, dataType: 'json', cache: false, success: function(response){ location.reload(); } }); }); </script> extendTime.php $pageID = $_POST['currentPageID']; $newTime = $_POST[$dtPick]; $newEndTime = DateTime::createFromFormat('m/d/Y h:i A', $newTime); $convertedDateTime = $newEndTime->format('Y-m-d H:i:s'); $extendExpiration = " UPDATE pages SET end_time = '$convertedDateTime' WHERE id = '$pageID'; "; if($mysqlConn->query($extendExpiration)=== TRUE){ echo "SUCCESS"; }else{ echo "Could not extend Time"; }
  5. Hi all, I currently have a table listed, with one of the rows being hyperlinked and linking to an input form, should be autopopulated from the code (ID or other unique identifier) of the row, however, when clicking the link the form does not load. I will insert relevant code to this thread and if anyone would be able to shed some light on this that would be great. NOTE: SQL code has already been tested using PHPMyAdmin and works fine. Although, it may need changed to help with this issue - I'm not quite sure. Please see screenshots for relevant code.
  6. fanboime

    Help with JSON in PHP

    here is my insert method public function add($values) { $sql = "insert into vehicles(`vehicle_plates`,`DA`,`type`, `model`, `driver`) values('$values')"; if(!mysql_query($sql)) { $this->error = mysql_error(); return true; } else { return false; } } And here is my Button click funtion $( "#button" ).button(); $( "#button" ).click(function( event ) { <?PHP if(isset($_POST["subBtn"])) { $fName = $g->clean($_POST["fullname"],1); $sDate = date('Y-m-d', strtotime($_POST["startdate"])); $roomNum = $g->clean($_POST["roomnumber"]); $driver = $g->clean($_POST["driver"],1); $model = $g->clean($_POST["model"],1); $json = '{"a":$fName, "b":$sDate, "c":$roomNum, "d":$model, "e":$driver}'; $array = json_decode($json, true); $values = implode(",", $array); $g->add($values); } ?> }); Everytime i click my button it Postsback and nothing inserts in my database...
  7. jason360

    Posted Copied Text

    am coming across the problem. When I use copied text in my input form it gives some characters this � character. I am not sure how to post text so this doesn't happen. Example: This line copied: The 976cc, 101-hp Rotax® 1000R V-Twin engine is known for its reliable power. Produces: The 976cc, 101-hp Rotax� 1000R V-Twin engine is Can-Am's most powerful side-by-side engine. My code: if (get_magic_quotes_gpc()) { $description_clean_magic = stripslashes($description); } else { $description_clean_magic = $description; }
  8. I am trying to create a dynamic form using Jquery but don't know how to post those data using $_POST. The page <html> <head> <title> Dynamically create input fields- jQuery </title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script> <script type="text/javascript"> $(function() { var addDiv = $('#addinput'); var i = $('#addinput p').size() + 1; $('#addNew').live('click', function() { $('<p><input type="text" id="p_new" size="40" name="p_new_' + i +'" value="" placeholder="I am New" /><input type="text" id="p_new2" size="40" name="p_new_2' + i +'" value="" placeholder="I am New 2" /><a href="#" id="remNew">Remove</a> </p>').appendTo(addDiv); i++; return false; }); $('#remNew').live('click', function() { if( i > 2 ) { $(this).parents('p').remove(); i--; } return false; }); }); </script> </head> <body> <h2>Dynammically Add Another Input Box</h2> <form action="gen.php" method="post"> <div id="addinput"> <p> <input type="text" id="p_new" size="40" name="p_new" value="" placeholder="Input Value" /><input type="text" id="p_new2" size="40" name="p_new2" value="" placeholder="Input Value" /><a href="#" id="addNew">Add</a> </p> </div> </form> </body> </html> Here is live example.. A Pen by Captain Anonymous Whatever, The new fields got an unique name="" value as p_new_1, p_new_21 for first new field, p_new_2, p_new_22 for second new field ...... ...... Now, I know I can display inserted data using <?php echo $_POST["p_new_1"]; ?> and similar way like this... But as a growing field, this form can have unlimited input field. How can I display all of those data in the page gen.php? It must be something like this example: <html> <body> <div class="header">Generated content<div> <p><a href="inserted data of first field of default row">inserted data of second field of default row</a></p> <p><a href="inserted data of first field of first new row">inserted data of second field of first new row</a></p> <p><a href="inserted data of first field of 2nd new row">inserted data of second field of 2nd new row</a></p> <p><a href="inserted data of first field of 3rd new row">inserted data of second field of 3rd new row</a></p> <p><a href="inserted data of first field of 4th new row">inserted data of second field of 4th new row</a></p> And list go on according to submitted form.... </div></body></html> I actually lake of knowledge of PHP and no idea about array or something named loop. Can someone do it for me? What I have to do in gen.php?
  9. hi I am having problems trying to either include php file or execute a php script within <div with a class> which I use for a drop down menu, every bit of help much appreciated, thanks..singhy <h2 class="hidenextdiv"><a href="#">dropdown menu1</a></h2> <div class="another dropmenuclass"> <h3>Test</h3> want to add my php working code here, have tried includes but no joy, it either breaks the dropdown menu or I am not getting the results back from the database, my script works ok, have tested it separately. <h3> </h3> <div style="clear: both;"> </div> </div>
  10. Here is my java script $.each(data, function() { var myTable1 = '<tr bgcolor=#ffffff>' + '<td align=center>'+this.vehiclelog_plate+'</td>' + '<td align=center>'+this.vehiclelog_name+'</td>' + '<td align=center>'+this.vehiclelog_date+'</td>' + '<td align=center>'+this.vehiclelog_reftype+'</td>' + '<td align=center>'+this.vehiclelog_refid+'</td>' + '<td align=center>'+this.vehiclelog_description+'</td>' + '</tr>'; $('#tableField').append(myTable1); }); And here is my HTML <div id="tabs-6"> <div id="rform"> <form action = "home.php" method="post"> <fieldset> <legend>View Vehicle Service</legend><br><br> <div> <label class="label-left">Vehicle Name:</label> <span role="status" aria-live="polite" class="ui-helper-hidden-accessible"></span> <input id="autocomplete" title="type "a"" class="ui-autocomplete-input" name="vehicle_service_search" autocomplete="off"> </div> <div> <button id="searchVehicleDesc" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" role="button" aria-disabled="false"> <span class="ui-button-text">View</span> </button> </div> <div> <table border="1" width="650" id = "tableField"> <tr bgcolor=#c0c0c0> <td width=100 align="center"><font face="helvetica"><b>Vehicle Name</b></font></td> <td width=80 align="center"><font face="helvetica"><b>Service Type</b></font></td> <td width=80 align="center"><font face="helvetica"><b>Others</b></font></td> <td width=100 align="center"><font face="helvetica"><b>Reference No.</b></font></td> <td width=80 align="center"><font face="helvetica"><b>Reference Date</b></font></td> <td width=80 align="center"><font face="helvetica"><b>Reference Type</b></font></td> </tr> </table> </div> </fieldset> </form> </div> </div> And here is my response [{"success":1,"plate":"SIX666","name":"YAMAHA ISUZU","date":"0000-00-00","type":"Add Vehicle","id":"0","desc":""},{"success":1,"plate":"VIE597","name":"Resource id #6","date":"2014-05-09","type":"OIL","id":"332142","desc":"castroil"}] Im getting the right response from ajax but I can't put my value to a table I get an alert that says undefined.
  11. I have a database written in and stored on a server. The table I will be accessing is called dataRep and houses Rep Data. This data is user input via form submission. Upon coming to the website there is an option to "View Rep Information" by submitting the Rep's ID that was given. That Rep ID will be the auto increment repID from the table. Upon clicking the button, it opens a new window that should display the rep's data. It does not, however. Here is the [html] the user will see: <div class="pop_box"> <a class="rms-button" href="#popup1">Enter Rep Number Here</a> </div> <div id="popup1" class="overlay"> <div class="popup"> <a class="close" href="#">×</a> <div align="center"><br> <br> <p>Enter rep number in box below. Submission will open new window.</p> <form method="get" action="/data/repPrepare.php" target="_blank" > <input type="text" id="repSelect" name="repSelect" placeholder="Enter Rep Number Given Here" /> <button type="submit" class="newbutton">VIEW</button> </form> </div> </div> ...and here is the [php] I have tried, which I get the following error: [indent]"Could not get data: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '[repSelect]' at line 1"[/indent] <?php $dbhost = 'mhhost'; $dbuser = 'myuser'; $dbpass = 'mypass'; $conn = mysql_connect($dbhost, $dbuser, $dbpass); if(! $conn ) { die('Could not connect: ' . mysql_error()); } $sql = 'SELECT * FROM dataRep WHERE repID = [repSelect]'; mysql_select_db('reviewmy_jos1'); $retval = mysql_query( $sql, $conn ); if(! $retval ) { die('Could not get data: ' . mysql_error()); } while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) { echo "Rep ID :{$row['repID']} <br> ". "Rep NAME : {$row['repName']} <br> ". "Rep Bio : {$row['repBio']} <br> ". "Rep Certs : {$row['repCerts']} <br> ". "--------------------------------<br>"; } echo "Fetched data successfully\n"; mysql_close($conn); ?> I am truly stuck and have been dealing with this issue for two weeks. I would appreciate any assistance that can be provided. I just need the [php] to pull the data tied the repID that the user puts in the box. When I started this I assumed it would be rather easy. I guess that's what I get for assuming. Either way, I'm missing something here. Is there a possibility that this can not be done? Like, I should be using AJAX instead?
  12. Hi everyone, I'm trying to get my head around blending in and out of php and html. I've seen some simple examples which work great but now I have this variable that comes from the database and I would like to style the variable in-line with html markup. Here's what I'm trying to do: <?php echo "Price : ",'<Font size="100"> $tournament["pricePerPlayer"] </font>'; ....more of the same code goes here... ?> I can't get $tournament["pricePerPlayer"] to be controlled by the font tag. How do I do this? Any help would be greatly appreciated. Thanks,
  13. adke001458

    href to php function

    Hello, I have created a webpage that essentially generates an sql query and then puts the results into a table that is displayed. On one of the columns in this displayed table, I want to allow the user to click on each of the values which will in turn execute a php function. I have the hyperlink working but this is to a separate page. What I actually need to do is firstly - just ran a php function that will create a new table beneath the currently displayed one. Secondly, once this is achieved, I need to pass some value to the function so that the generated table is dependent on the value that was clicked. I've tried a few things and researched but I am struggling. I am a beginner. Any help would be greatly appreciated. Here is an extract of the code used for inputting data into the original table - showValuesSR is the function name <?php while (!$rsMetrics->EOF) { ?> <tr> <?php for ($x=0; $x<$numberOfFields; $x++) { if ($fieldNames[$x] == "Values_SR"){ ?> <td><a href= ?showValuesSR><?php echo $rsMetrics->fields[$fieldNames[$x]]->Value?></a></td> <?php } else{ ?> <td><?php echo $rsMetrics->fields[$fieldNames[$x]]->Value?></td> <?php } } ?> </tr> <?php $rsMetrics->MoveNext(); } ?> </table> <?php function showValuesSR(){ ?> <table border="0" cellpadding="5" width="100%"> <tr><td background="../images/table_toolbar_bkg.gif" align="center"><font color="Blue" face="verdana" size="2"><strong>function working</strong></td></tr> </table> <?php } ?>
  14. Great site!, Im trying to understand a bit more pdo.. I have the following: I have a svg and when I click on the map the country name is loaded into a var on the click event by the code below: <script> function fill_contact(evt) //display click event { var country_id = evt.target.id document.getElementById('country_name').firstChild.data = country_id } </script> My php code is as follows: <?php //Define constants define('DB_DRIVER', "mysql"); define('DB_SERVER', ""); define('DB_DATABASE', "aeea"); define('DB_USER', "root"); define('DB_PASSWORD', "root"); //Database connection try { $dbh = new PDO(DB_DRIVER . ":dbname=" . DB_DATABASE . ";host=" . DB_SERVER, DB_USER, DB_PASSWORD); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch(PDOException $e){ die("Sorry, we could not connect you to this database, please contact the Administrator to sort this out.". $e->getMessage()); } //Get data $query = "SELECT firstname, lastname, email, photo FROM reps WHERE country like ?"; $country = 'country_name'; //Create the statement $stmt = $dbh->prepare($query); $stmt->execute(array($country)); //Use data $row = $stmt->fetch(PDO::FETCH_ASSOC); echo '<pre>', print_r($row), '</pre>'; ?> My Html code is as follows: <div id="IndexPage"> <div id="IndexPage_Left"> <div id="IndexPage_Left_top"> <h3>Country: <span class="label" id="country_name"> </span></h3><!—This works fine--> <p></p> <h4>Regional Representative: <span class="label" id="firstname"> </span></h3></h4><!--get Rep ” firstname, lastname” from database based on country from svg to display--> <p></p> <h4>Photo</h4><!--get Rep “photo” from database based on country from svg to display--> <p></p> <input style='margin-top: 20px;' type="submit" value="Contact me." id='jqxSubmitButton' /><!-- if clicked, it opens a contact form below, the email address is hidden--> </div> <div id="IndexPage_Left_bottom"> <h4>email form here<h4><!-- if email is clicked, it opens a contact form here with “email” address from database --> </div> </div> <div id="IndexPage_Right"> <svg id="map" version="1.1" and rest of svg code. My database has a table called reps. It had dta of representatives in each country in Africa. It has a number of fields ie. rep_id(unique indexed), firstname, lastname, email, postal, city, state, country, contact_no, photo etc. I want to be able to get the fields in the database and display them in the html form on the click events. Ie. The database must also refresh the query every time a click event happens. Guests might click a few countries to look at reps. If they click off the map, it blanks out the details. How do I go about doing this? I’ve heard about XMLHttpRequest but don’t know how to go about doing it. Another question: Once I get the information, how do I display it correctly in the Html? I used <span>, but is it correct? Last question: Once I get the information email address, how do I show a contact form on "conact me" button? and then when guests click on another country, remove the contact form? This is my first website. Please help
  15. Good Day Guys I have a bit of a urgent problem. Here is my Query: $query = "SELECT distinct Img.propertyId as PropertyId, Title, ImageUrl, Location, Bedrooms, Bathrooms, Parking, Price FROM PROPERTIES as Prop LEFT JOIN IMAGES as Img ON Img.PropertyId = Prop.PropertyId WHERE 1=1 AND Price >=1000 AND Price <=5000 "; I have a problem and the problem is here - AND Price >=1000 AND Price <=5000. This works fine but the problem comes as soon as I add more: For example: if I add OR Price >5000 AND Price <=10000 then it displays all my results from 1000 to 10000 and I want it to be if I select 5000 - 10000 it needs to display only the results between 5000 and 10000. Can someone please help me?
  16. finder.com.au is making waves in the comparison space, and we are expanding our Design & Technology team massively this year. We are looking for several full-stack Senior PHP Developers who will be responsible for building a wide variety of web-based applications (using PHP and MySQL) in addition to maintaining existing PHP code, optimizing website and database performance and developing custom PHP solutions. This is a great opportunity for web people at heart to join a growing team delivering awesome products that get used by hundreds of thousands of users. As a developer at finder.com.au you will have the freedom, autonomy, and responsiblity to improve the code, tools, and architecture without having to cut through red tape. Why finder.com.au? We've just been named one of the top service companies in the Asia Pacific for 2014, taking silver in the Stevie Awards for Australian Service Company of the year. We’ve also been dubbed one of Anthill’s 50 coolest companies in Australia for 2013 thanks to our amazing team, wonderful users and cool company culture. As a development team, we move quickly, releasing code several times per day. You need to be willing to move fast, rely on automation, make decisions on less than perfect information, trust your teammates, and constantly strive to improve. A new Head of Design and Technology, with experience at two of local startup scene’s biggest success stories, recently joined us to lead the team on a mission to speed up the entire company to become the Australian brand for comparison. The team runs hackdays every other month that give all developers free time to show off their creativity and innovation. You will have choice of OS, laptop or desktop, IDE and toolset, and up to 3 monitors. What’s more, you will experience an ultra modern office located in the heart of the Sydney CBD, catered lunches and breakfast supplied every day and all the snacks and drinks you want! Who are you? You live and breathe development and your code has soul. You are a great PHP coder that wants to join a team where you can flex your skills and grow further. You are an expert who understands complex problems and enjoys deploying solutions to business problems. You are keen to get your projects live and solve business problems and improve the development environment and tooling. You also have experience in getting code live multiple times per day. You may be applying from overseas – We are happy to provide support with sponsored relocation services. We already have a number of people on our team from overseas so you will be joining a community. Must have experience: 4+ years of PHP development experience for Senior Roles Experience with phpunit Knowledge of CI tools (Bamboo, Travis, CircleCI) Knowledge of CD tools (Beanstalk, Capistrano) Knowledge of Git Ability and desire to use and extend Git tools (GitHub, Bitbucket) to enhance workflow Ability to mentor junior developers Experience with Wordpress beneficial Knowledge of Front End technologies beneficial Knowledge of monitoring tools beneficial Please send us a resume to iwantin@finder.com.au and optionally provide us with a link to your GitHub or Bitbucket profile and a personal note as to why you would want to work with us at finder.com.au.
  17. First let me start by saying I'm not looking to copy someone else's code but better understand where the line is drawn for people copying my own code. All developers at some point will have used others code in there own work. If you see something that inspires you, you may decided to use that code in your design. In some degree this maybe classed as fair use depending on the quantity of code you copy. Another developer may taken an entire php file, function, class, CSS sheet, HTML file and use this in there work / pass this off as there own work. This is blatant plagiarism. However what is stopping a developer from taking an entire piece of code and editing every aspect of the file to make it his own? For instance a designer my change the names of the styles and perhaps change the order of the properties and there values slightly; He may also move around parts of the html. In doing so causes the design to look different to your own but still the copying your work no the less. Another instance maybe that a PHP developer uses your entire code / software package and change the names of the variables, classes and methods; He may also change the order in which the methods appear and even change some similar functions to use alternatives such as loops. Again this causes the program to do exactly what your intends to do, however the source code will now look different to your own. How far can someone go back doing these actions? Is this legal? How best would you be able to prove it?
  18. In the following pages I'm trying to validate if a user is signed in or not. If the user is signed in I would like to see 'Log Out' printed to the screen(I'll do more with that later). If the user is not signed in I would like to see a login form at the top right of the screen. As it stands I'm only seeing 'Log Out' on the screen, I can't get the form to show up anymore. I thought it might be because the session variable was still hanging around but I restarted my computer to make absolutely sure but I'm still just getting 'Log Out'. At the moment I need this program to work as is as much as possible. If you see an entirely different approach that you would use that's fine but I don't currently have the time to go changing a lot, I need to get this going kinda quick. Thanks. records-board.php <?php require_once('includes/init.php'); if(!isset($_SESSION)) { init_session(); } ?> <html> <head> <Title>Pop Report</title> <link rel="stylesheet" type="text/css" href="styles/popreport2.css"> <h1>Pop Report</h1> </head> <body> <?php if(isset($_POST['nameinput']) && isset($_POST['passinput'])) { $nameinput = $_POST['nameinput']; $passinput = $_POST['passinput']; User::sign_in($nameinput, $passinput); } if(!isset($_SESSION['user'])) { print_form(); } else { echo "Log Out "; echo $_SESSION['user']->name; // this line was just trouble shooting, it told me nothing! } ?> user.php <?php if(!isset($_SESSION)) { init_session(); } class User { public $name; public function __construct($username, $password) { $connection = get_db_connection(); $query = $connection->query("SELECT * FROM users WHERE username='$username' AND password='$password'"); if(!$query) { echo "Invalid username or password"; } else { $result = $query->fetch(PDO::FETCH_ASSOC); if(!$result['username'] == $username || !$result['password'] == $password) { echo "Invalid username or password"; } else { $this->name = $result['username']; } } } public static function sign_in($username, $password) { $_SESSION['user'] = new User($username, $password); } } ?> <?php function print_form() { echo "<form id='loginform' name='loginform' action='records-board.php' method='post'>"; echo "Username: <input type='text' name='nameinput'>"; echo "Password: <input type='text' name='passinput'><br />"; echo "<input type='submit' value='Sign In'>"; echo "</form>"; } ?>
  19. Hey guys, i am trying to create a box to show images or content once a user selects a link within a gallery. So for example i have an image --> user scrolls over --> image overlay shows a link ---> link actions to a jquery action to where a hidden field shows more data. right now i have everything to the point to where the links default action is disabled and the "overlay" div that will show the content is hidden. when i then go ahead and add some jquery to add a class when the link is clicked nothing seems to happen. <section class="work_area" id="WORK"> <div class="container"> <div class="row"> <div class="col-md-12 text-center"> <div class="work_title wow fadeInUp animated"> <h1>demo<span style="color: #64bdec; font-weight: bolder;">33</span> PORTFOLIO</h1> <img src="images/arrow486.png" alt=""> </div> <div id="dataBox"></div> </div> </div> </div> <div class="container-fluid"> <div class="row"> <div class="col-md-2 no_padding"> <div class="single_image"> <img src="images/REGISTERE.png" alt=""> <div class="image_overlay"> <h2>Lorem ipsum</h4> <a id="link" href="portfolio.php" >Popup link</a> </div> </div> </div> </div> </div> </section> CSS #dataBox{ width: 800px; height: 500px; margin: auto; padding: 100px 100px; position: relative; border: 2px solid black; margin-bottom: 10px; } #pData{ background: red; width: 800px; height: 500px; margin: auto; padding: 100px 100px; position: relative; border: 2px solid black; } JS. $(document).ready(function(){ $('#dataBox').hide(); $('#link').click(function(e){ e.preventDefault(); $('div #dataBox').removeClass().addClass('pData'); console.log("link is working"); }); }); everything works other than the div showing up.
  20. jazza96

    Why isn't my form sending?

    Hi I am trying to build a contact form and my form isnt sending. Here is my code. (its in a modal window)(I have my email address in the $to variable in the code) <?php $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message']; $from = 'From: Jarrod'; $to = 'email'; $subject = "Landing page"; $body = "From: $name\n Email: $email\n Message:\n $message"; ?> <?php if ($_POST['submit']){ if(mail ($to, $subject, $body, $from)) { echo '<p>Your message has been sent!</p>'; }else{ echo '<p>Something went wrong, go back!</p>'; } } ?> <div class="modal fade" id="contact" role="dialog"> <div class=" modal-dialog"> <div class="modal-content"> <div class="modal-header"> <h2>Contact us</h2> </div> <div class="modal-body"> <form method="post" action="index1.php"> <div class="form-horizontal"> <label for="Name">Your Name</label> <input type="text" class="form-control" id="name" placeholder="Name"> <label for="Email">Your Email</label> <input type="Email" class="form-control" id="email" placeholder="Email"> <label for="Message">Message</label> <textarea class="form-control" id="message" placeholder="Message"></textarea> <input type="submit" value="Send">Send</button> </form> <div class="modal-footer"> <a class="btn btn-default" data-dismiss = "modal">Close</a> </div> </div> </div> </div>
  21. I am running this query and the only thing i want is the title and for some reason it is giving me this. Recourse id # 7 ? Here is my query that i am running. $photo = $_GET['image']; $retrievetitle = "SELECT title FROM photo_from_user WHERE picture = '$photo' limit 1"; $title = mysql_query($retrievetitle);
  22. carlitosfigue

    Problem with Login form.

    Hello guys, first post here. I have a web system which contains a login form programmed in 3 different languages HTML, PHP and JS. The problem is that it's not working, you can access without entering any data, you just press enter and it will work, I don't know why it is not validating any credentials. I was thinking about some query problems but I don't know. I am a newbie on this. I have read a lot but haven't found an answer. A friend helped me build the system but left that uncompleted and he's nowhere to be found. I was wondering if you could help me out with this. <form role="form" ng-submit="login(user,password)"> <div class="form-group"> <input type="user" class="form-control" ng-model='user' placeholder="Usuario"> </div> <div class="form-group"> <input type="password" class="form-control" ng-model='password' placeholder="Contraseña"> </div> <div class="alert alert-warning" id='alert' style="display:none">Revise la informacion...</div> <div class="alert alert-danger" style="display:none" id='alertErr'>Error Usuario o Contraseña Erronea intentelo de nuevo</div> <button type="submit" class="btn btn-primary">Ingresar</button> </form> <?php require_once 'database.php'; $db = new Database(); $body = json_decode(file_get_contents('php://input')); $user =$db->query("SELECT * FROM usuario WHERE usua_login = '".$body->user."' AND usua_pass = '".$body->password."'"); if($user == false){ http_response_code(404); } else{ http_response_code(200); echo json_encode($user); } ?> 'use strict'; /** * @ngdoc function * @name belkitaerpApp.controller:MainCtrl * @description * # MainCtrl * Controller of the belkitaerpApp */ angular.module('belkitaerpApp') .controller('MainCtrl', function ($scope,$http,$location) { $scope.login = function(user,password){ console.log('Login...'); if(user =='' || password ==''){ $('#alert').show("slow"); setTimeout(function() { $('#alert').hide('slow'); }, 3000); } else{ $http.post('../serverSide/login.php',{user:user,password:password}).success(function(data){ console.log('OK!'); $location.path('/products'); }).error(function(data){ $('#alertErr').show("slow"); setTimeout(function() { $('#alertErr').hide('slow'); }, 3000); }); } } });
  23. Code works when... <script type="text/javascript"> var currenttime = '<?php print gmdate('F d, Y H:i:s', time() + (1 * 60 * 60))?>' var montharray=new Array("January","February","March","April","May","June","July","August","September","October","November","December") var serverdate=new Date(currenttime) function padlength(what){ return (what.toString().length==1)? "0"+what : what } function displaytime(){ serverdate.setSeconds(serverdate.getSeconds()+1) var datestring=montharray[serverdate.getMonth()]+" "+padlength(serverdate.getDate())+", "+serverdate.getFullYear() var timestring=padlength(serverdate.getHours())+":"+padlength(serverdate.getMinutes())+":"+padlength(serverdate.getSeconds()) document.getElementById("servertime").innerHTML=datestring+" "+timestring } window.onload=function(){ setInterval("displaytime()", 1000) } </script> Code not works when... <script type="text/javascript" src="clock.js"> I want to use second option. Any help?
  24. There is no SEO section so I do not know where exactly to ask this question, but here it is. https://www.google.ca/?gfe_rd=cr&ei=jgm3VIqFNtCy8wfH3YD4CA#q=twitter.com Do you see how Google lists Twitter results in two columbs underneath the main heading title? How does one achieve that result with their website? Does only Google decides to make it show up that way?
  25. TubaTobu

    passing on values

    Hi guys I would like to get whole content of html file after I submitted a password. The problem is that the my code doesn't access the value for the file. I tried to create a session but i doesn't work. What other option do I have to get the content of the html file? session_start(); $selected_file = $_POST['radio1']; // get the filename of the file $fileinfo = pathinfo($selected_file); $filename = $fileinfo['dirname'] . DIRECTORY_SEPARATOR . $fileinfo['filename']; $password = 'code'; $lines = file("$filename.html"); $_SESSION['selectedfile'] = $selected_file; $_SESSION['file'] = $filename; $_SESSION['Scipt'] = ("$filename.html"); $_SESSION['Scipttext'] = $lines; $_SESSION['file2'] = $fileinfo; if (isset($_POST['submitradio'])) { echo '<div class="imageselected">'; echo '<img src="'.$_SESSION['selectedfile'].'" /></br>'.PHP_EOL; echo '</div>'; // check to see if a html file named the same also exists if(file_exists($_SESSION['Scipt'])) { echo "<form action='test_result.php' method='post'>"; echo '<div class="Password">'; echo 'Type in password to view full Script'; echo "<label><div class=\"Input\"><input type='password' name='passIT' value='passit'/></div>"; echo "<input type='submit' name='submitPasswordIT' value='Submit Password'/></div>"; echo '</div>'; echo "$filename.html shares the same name as $selected_file"; for($x = 1;$x<=15;$x++) { header( "Content-Type: file/html" ); $lines = ($_SESSION['Scipttext']); $new = strip_tags($lines); echo $lines[rand(0, count($lines)-1)]."<br>"; } // end of forloop } // end of check // start Sorrytext else { echo '<div class="NoScript">'; echo "Nothing available at the moment."; echo '</div>'; } // end Sorrytext } // End of submitradio if($_POST['submitPasswordIT']){ if ($_POST['passIT']== $password ){ echo "You entered correct password"; readfile($_SESSION['Scipt']); } else{ echo "You entered wrong password"; } } echo '</form>'; I would be grateful for help.

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