Wierd problem

[KenHorse]

I'm trying to work out a problem with a suite of scripts and wrote a very simply "test" script to see if I could figure out what I'm doing wrong in another place. Here's my test one:

 

<?php

$id = 776; 


print '$id ' . "$id\n";   

if(isset($POST['cancel'])){
    print "Exiting";
	exit();
}

if(isset($_POST['submitted'])){
	print '$id ' . "$id";   
}

print "
   <input type=\"submit\" value=\"Save\" name=\"submitted\">
   <input type=\"submit\" value=\"Cancel\" name=\"cancel\">
";
?>

Normally $id is read in from a MySQL database and some of the above code appears in a script (as a pop up) referenced by another script. So I'm assigning $id in my test instead of reading it at the time the script is first run.

 

Anyway... the script loads fine in a browser with the first print statement properly showing "$id 776". Howver clicking either the Save or Cancel buttons do nothing at all. What am I doing wrong?

 

Edited February 27, 2013 by KenHorse

[requinix]

Besides the $POST['cancel'] typo, the buttons have to be in a form.

$id = 776;


print '$id ' . "$id\n";

if(isset($POST['cancel'])){
print "Exiting";
exit();
}

if(isset($_POST['submitted'])){
print '$id ' . "$id";
}

print "
</pre>
<form method='\"post\"'>


</form>
<br>";<br

[edit] Oookay, indentation doesn't want to work for me.

Edited February 27, 2013 by requinix

[QuickOldCar]

I added form to it, also you didn't have $_POST['cancel']

 

<?php

$id = 776;


print '$id ' . "$id\n";   

if(isset($_POST['cancel'])){
    print "Exiting";
    exit();
}

if(isset($_POST['submitted'])){
    print '$id ' . "$id";   
}

print "
   <form action=\"\" method=\"post\">
   <input type=\"submit\" value=\"Save\" name=\"submitted\">
   <input type=\"submit\" value=\"Cancel\" name=\"cancel\">
   </form>
";
?>

[QuickOldCar]

lol@requinix, at least we gave same advice