Pghmediaking Posted March 21, 2013 Share Posted March 21, 2013 I am new to PHP so bare with me but I am trying to display videos based on a date range without using a database. The videos are independently housed inside individual .php files that I am using as includes. Can anyone take a look into what Im doing so that I can figure out if my techniques is correct. Below is the coding that I have completed: --------------------------------------------------------------------------------------------------------------------- The include files are setup in this manor: video_name1.php contains this coding(as do all the other include files: <video width="640" height="480" controls> <source src="media/ogg/easter_720x480.ogv" type="video/ogg"> <source src="media/mp4/easter_720x480.mp4" type="video/mp4"> <source src="media/webm/easter_720x480.webm" type="video/webm"> <source src="media/wmv/easter_720x480.wmv" type="video/wmv"> <object data="movie.mp4" width="640" height="480"> <embed width="640" height="480" src="media/player.swf"></embed> </object></video> --------------------------------------------------------------------------------------------------------------------- My php constructed to complete the task: <?php $video_name1="includes/video_name1.php"; $video_name2="includes/video_name2.php"; $video_name3="includes/video_name2.php"; $video_name4="includes/video_name2.php"; $video_name5="includes/video_name2.php"; $video_name6="includes/video_name2.php"; ?> <?php date_default_timezone_set('America/New_York'); $today = strtotime(date('Y-m-d')); $startApr = strtotime(date('Y') . '-04-01'); $endMay = strtotime(date('Y') . '-5-31'); $startJune = strtotime(date('Y') . '-06-01'); $endJuly = strtotime(date('Y') . '-7-31'); $startAug = strtotime(date('Y') . '-08-01'); $endSept = strtotime(date('Y') . '-9-30'); $startOct = strtotime(date('Y') . '-10-01'); $endNov = strtotime(date('Y') . '-11-30'); $startDec = strtotime(date('Y') . '-12-01'); $endJan = strtotime(date('Y') . '-1-31'); $startFeb = strtotime(date('Y') . '-2-01'); $endMarch = strtotime(date('Y') . '-3-31'); if($today >= $startApr && $today <= $endMay) { include($video_name1); } else if($today >= $startJune && $today <= $endJuly) { include($video_name2); } else if($today >= $startAug && $today <= $endSept) { include($video_name3); } else if($today >= $startOct && $today <= $endNov) { include($video_name4); } else if($today >= $startDec && $today <= $endJan) { include($video_name5); } else if($today >= $startFeb && $today <= $endMarch) { include($video_name6); } ?> Quote Link to comment https://forums.phpfreaks.com/topic/275976-display-a-video-based-on-a-date-range/ Share on other sites More sharing options...
Pghmediaking Posted April 9, 2013 Author Share Posted April 9, 2013 So I posted this topic some time ago, roughly a month, and not one person responded. Is this what is to be expected from this online community. I am looking for a site that helps new developers learn while also contributing when I can. This had almost 50 views and not one response. Quote Link to comment https://forums.phpfreaks.com/topic/275976-display-a-video-based-on-a-date-range/#findComment-1423669 Share on other sites More sharing options...
Jessica Posted April 9, 2013 Share Posted April 9, 2013 Probably because you didn't A. Use code tags B. ask an actual question or describe a problem. Quote Link to comment https://forums.phpfreaks.com/topic/275976-display-a-video-based-on-a-date-range/#findComment-1423681 Share on other sites More sharing options...
mac_gyver Posted April 9, 2013 Share Posted April 9, 2013 if you want to match just the month number(s) to values, you would use a lookup array to do that - $map[4] = $video_name1; $map[5] = $video_name1; ... $today = date('n'); // 1-12 include $map[$today]; if you want to use any arbitrary month-day start and end you would use an array that lists the start and end values that you can loop through to find the matching entry - $map[] = array('04-01','05-31',$video_name1); $map[] = array('06-01','07-31',$video_name2); ... $map[] = array('12-01','12-31',$video_name5); // break up any value spanning the end/start of the year $map[] = array('01-01','01-31',$video_name5); ... $today = date('m-d'); // 01-01 - 12-31 foreach($map as $arr){ if($today >= $arr[0] && $today <= $arr[1]){ include $arr[2]; break; } } Quote Link to comment https://forums.phpfreaks.com/topic/275976-display-a-video-based-on-a-date-range/#findComment-1423743 Share on other sites More sharing options...
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