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MySqli error - Call to a member function execute() on a non-object


Go to solution Solved by Simber33,

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Hello, I´m trying to insert data from a form into a mysql table using mysqli and php. I use the code below to connect to the database:

 

$host = "myhost";
$db = "a5066994_tutors";
$user = "a5066994_tutors";
$pass = "mypassword";

$connection = mysqli_connect("$host", "$user", "$pass", "$db");

if ($connection->errno) {
printf("Connect failed: %s\n", $connection->error);
exit();

 

and the code below to insert:

$stmt = $connection->prepare("INSERT INTO tutorials (Author, Website, Title, Body1, Body2,
Body3, Body4, Subtitle1, Subtitle2, Subtitle3, Subtitle4, Category,
WTitle, Userid) VALUES ('$author','$website', '$title', '$text1', '$text2', '$text3', '$text4',
'$s1', '$s2', '$s3', '$s4', '$cat', '$wtitle', '$userid')
");

 

And it results in this error:

Call to a member function execute() on a non-object

 

I have also tried doing a var dump of the connection, which results in: object(mysqli)#1 (0) { }

and a var dump of the statement, which results in: bool(false)

 

Any help would be great, thank you!

what does putting the following debugging code after the prepare() statement show -

printf("Prepare failed: %s\n", $connection->error); 


i'm going to guess that the values you are inserting in the query are from a form?. why are you using a prepared statement, but still directly putting the data into the query. that bypasses what a prepared query is for. a prepared query should use placeholders for the data values and then supply the data when the query is executed.

Thanks! I found what the problem was - there is an unknown column. And yes, I'm new to using mysqli, so Im not sure how to use the prepared statement. Could you tell me how to use it? Thank you for your time!

 

what does putting the following debugging code after the prepare() statement show -

printf("Prepare failed: %s\n", $connection->error); 


i'm going to guess that the values you are inserting in the query are from a form?. why are you using a prepared statement, but still directly putting the data into the query. that bypasses what a prepared query is for. a prepared query should use placeholders for the data values and then supply the data when the query is executed.

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