Tanja Posted April 19, 2013 Share Posted April 19, 2013 On my dog database I want to run a statistic, how many litters was born in a year. But i can´t get the sum On this testpage you can see in first table (all other is for testing ;-)) which contains the year, the kennelname, date of birth and how many puppys in this litter. This data i get with $result = mysql_query(" SELECT dog.dogname, dog.breeder_id, dog.mother_id, dog.date_of_birth, YEAR(dog.date_of_birth) AS year, owner.kennelname, COUNT(dog.dogname) anzahl FROM dog LEFT JOIN owner ON (dog.breeder_id = owner.id) WHERE owner.country_short='de' AND dog.date_of_birth >= DATE_SUB(CURDATE(), INTERVAL 20 YEAR) AND owner.kennel_note ='' GROUP BY dog.mother_id, dog.date_of_birth ORDER BY date_of_birth ASC ", $db) OR die(mysql_error()); while($row = mysql_fetch_array($result)) ... to get all puppys of one year, I change the GROUP BY to year - works also fine. But how can I get the sum of litters / year? In Year 1997 it should be 2, in 1998 0, in 1999 2, in 2000 1 and so on. The Array (reduced) looks following: Array ( [0] => 1997 [year] => 1997 ) Array ( [0] => 1997 [year] => 1997 ) Array ( [0] => 1999 [year] => 1999 ) Array ( [0] => 1999 [year] => 1999 ) Array ( [0] => 2000 [year] => 2000 ) I don´t care how the sum is calculate (sql/php or other), most important is to get it. Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/ Share on other sites More sharing options...
Solution Tanja Posted April 19, 2013 Author Solution Share Posted April 19, 2013 Problem solved ;-) SELECT *, COUNT(*) FROM ( SELECT YEAR(dog.date_of_birth) AS year FROM dog LEFT JOIN owner ON (dog.breeder_id = owner.id) WHERE owner.country_short='de' AND dog.date_of_birth >= DATE_SUB(CURDATE(), INTERVAL 20 YEAR) AND owner.kennel_note ='' GROUP BY dog.mother_id, dog.date_of_birth, year ) AS T1 GROUP BY year Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425764 Share on other sites More sharing options...
Jessica Posted April 19, 2013 Share Posted April 19, 2013 No, add the year into your original group buc Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425766 Share on other sites More sharing options...
Jessica Posted April 19, 2013 Share Posted April 19, 2013 Group by Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425767 Share on other sites More sharing options...
Tanja Posted April 19, 2013 Author Share Posted April 19, 2013 If I group by year instaed of dog.mother_id, dog.date_of_birth, year i get "only" all puppies in sum of the year, but not the sum of litters. Take a look (Countrys are not working here) , at this moment only in german. Anzahl Welpen means Puppies at all, Anzahl Würfe means Litters at all and at the end there is a list with all dates. Hmmm.... Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425869 Share on other sites More sharing options...
Jessica Posted April 19, 2013 Share Posted April 19, 2013 In addition to. Not instead of. Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425870 Share on other sites More sharing options...
Barand Posted April 20, 2013 Share Posted April 20, 2013 You doing a LEFT JOIN to the owner table so any selection conditions on the owner table need to be in the JOIN ON clause and not in the WHERE clause LEFT JOIN owner ON (dog.breeder_id = owner.id) AND owner.country_short='de' AND owner.kennel_note ='' Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425883 Share on other sites More sharing options...
Tanja Posted April 20, 2013 Author Share Posted April 20, 2013 @Jessica: i can put year in the group by in addition, but no count of litters will be done. @Barand: if i change my query in this way i get wrong counts (for Germany i can take a look in a real book, so i know that the calculation is right). I don´t know why it is so difficult to get the sum which is already at the ground in array. In array i can´t count all 2008.... By the way, is my solution bad? Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425907 Share on other sites More sharing options...
Barand Posted April 20, 2013 Share Posted April 20, 2013 The LEFT JOIN will include all dogs, even those with no owner on file. INNER JOIN will include only dogs with owners. Grouping by year within date of birth is pointless - there is only a single year in a date Quote Link to comment https://forums.phpfreaks.com/topic/277135-count-how-many-in-year/#findComment-1425934 Share on other sites More sharing options...
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