public Posted May 6, 2013 Share Posted May 6, 2013 I have a table with images in BLOBs. I want to show one of those images where the height isn't bigger than 100px and the width not bigger than 120px. If such an image isn't found, it will display a standard image. I'm getting this error: Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource in /home/server15/public_html/cards/view.php on line 50 <?php class MySQL { /* * Set up private variables for connection */ // private $host = 'localhost'; // private $user = 'admin'; // private $pass = 'root'; // private $dbname = 'database'; private $host = 'localhost'; private $user = 'admin'; private $pass = 'root'; private $dbname = 'database'; /* * Error messages variables */ private $error_open = '<div style="color: red;">'; private $error_close = '</div>'; /* * Create a construct method to handle the connection */ function __construct() { $host = $this->host; $user = $this->user; $pass = $this->pass; $dbname = $this->dbname; $this->sql_link = mysql_connect($host, $user, $pass) or die('error 1!'); mysql_select_db($dbname, $this->sql_link) or die('error!'); } /* * Create query method to select things from the mysql database */ function query($sql) { return mysql_query($sql); } /* * Create fetch_object method to fetch the previously ran query */ function fetch_object($query) { return mysql_fetch_object($query); } function fetch_array($query) { return mysql_fetch_array($query); } /* * Create num_rows method to fetch the previously ran query rows in an int */ function num_rows($query) { return mysql_num_rows($query); } /* * Escape chars from SQL Injection */ function escape($string) { return mysql_real_escape_string($string); } } $db = new MySQL(); $loadCards = $db->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 "); while ($row = $db->fetch_object($loadCards)) { $loadImages = $db->query("SELECT * FROM `images` WHERE `cid` = '$row->id'"); while ($rowIMG = $db->fetch_object($loadImages)) { $img = imagecreatefromstring($rowIMG->img); $height = $imagesy($img); $width = imagesx($img); if (($height > 100) OR ($width > 120)) { echo '<img src="noimage.png" />'; } else { echo '<img src="'; echo image($img); echo ' ">'; } } } ?> Does anyone know how to fix this? Quote Link to comment Share on other sites More sharing options...
denno020 Posted May 6, 2013 Share Posted May 6, 2013 You should look into using the PDO class. It looks like you're actually trying to set up your own PDO type class, but you're using lots of deprecated functions.. $pdo = new PDO('mysql:host=localhost;dbname=YOUR-DB-NAME', 'USERNAME', 'PASSWORD'); $query = $pdo->query("Your query written correctly"); $results = $query->fetchAll(); That code should get you started Denno Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 I've 'cleaned' the file and it's now like this (the row img from the tabel images stores the blob image file): <?php $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 "); $results = $query->fetchAll(); $query2 = $pdo->query("SELECT * FROM `images` WHERE `cid` = '$results->id'"); $results2 = $query2->fetchAll(); $img = imagecreatefromstring($results2->img); $height = $imagesy($img); $width = imagesx($img); if (($height > 100) OR ($width > 120)) { echo '<img src="noimage.png" />'; } else { echo '<img src="'; echo image($img); echo ' ">'; } ?> The following errors appear on my screen: Warning: imagecreatefromstring() [function.imagecreatefromstring]: Empty string or invalid image in /home/server15/public_html/cards/view.php on line 11Fatal error: Function name must be a string in /home/server15/public_html/cards/view.php on line 12 Quote Link to comment Share on other sites More sharing options...
denno020 Posted May 7, 2013 Share Posted May 7, 2013 you've got $height = $imagesy($img); You need to get rid of the dollar sign before imagesy: $height = imagesy($img); You've done it right on the next line for $width As for the warning, just make sure you have actually got a result by using var_dump($result). Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 I've changed SELECT * FROM `images` in SELECT img FROM `images` and $results2->img in $results2 and the height/width thing. When I use var_dump($results2) I get this on my screen: array(1) { [0]=> array(2) { ["img"]=> string(37683) " [the image file as code] Warning: imagecreatefromstring() [function.imagecreatefromstring]: Empty string or invalid image in /home/server15/public_html/cards/view.php.php on line 11 Warning: imagesy(): supplied argument is not a valid Image resource in /home/server15/public_html/cards/view.php.php on line 12 Warning: imagesx(): supplied argument is not a valid Image resource in /home/server15/public_html/cards/view.php.php on line 13 According to the code it isn't a valid image I think, but it is a PNG file. I've tried gifs/jpegs, but I got the same result. Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 (edited) No, you don't fetch the real binary data of this image only the length (file size). EDIT: Could you show us the structure of this fetchAll() method? Edited May 7, 2013 by jazzman1 Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 This is all my code in the file: <?php $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 "); $results = $query->fetchAll(); $query2 = $pdo->query("SELECT img FROM `images` WHERE `cid` = '$results->id'"); $results2 = $query2->fetchAll(); $img = imagecreatefromstring($results2); $height = imagesy($img); $width = imagesx($img); if (($height > 100) OR ($width > 120)) { echo '<img src="noimage.png" />'; } else { echo '<img src="'; echo image($img); echo ' ">'; } ?> Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 (edited) It's a build pdo method. First off I wanna get a result from first statement but I see that you don't executing it at all, so step-by-step. Try this and give me the result back: $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 "); $query->execute(); $row = $query->fetch(); echo '<pre>'.print_r($row, true).'</pre>'; $query = null; Edited May 7, 2013 by jazzman1 Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 An empty page Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 An empty page There is something wrong in your sql. Try to run this query via phpMyAdmin for example: SELECT * FROM `cardId` WHERE `status` = 1 ORDER BY `id` ASC LIMIT 10 Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 (edited) I had to turn something off in my mysql settings, but now I see all my table contents when I execute that sql. Edited May 7, 2013 by public Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 I had to turn something off in my mysql settings, but now I see all my table contents when I execute that sql. Good, let's see the results, please! Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 Array ( [id] => 1884 [0] => 1884 [status] => 1 [1] => 1 [name] => Card 1 [2] => Card 1 [time] => 1-2 days [3] => 1-2 days [cate_id] => 5 [4] => 5 [dateAdded] => 05/05/13 [5] => 05/05/13 [countries] => United States [6] => United States [cap] => 0 [7] => 0 ) Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 Alright then, before to join those two tables, just one question. Is it a foreign key between tables "cardId" and "images" , if so this column is called "cid" ? Give me the result back of this statement: $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $query = $pdo->query("SELECT img FROM `images` WHERE `cid` IN (1)"); $query->execute(); $row = $query->fetch(); echo '<pre>'.print_r($row, true).'</pre>'; $query = null; Quote Link to comment Share on other sites More sharing options...
mac_gyver Posted May 7, 2013 Share Posted May 7, 2013 It's a build pdo method. First off I wanna get a result from first statement but I see that you don't executing it at all, so step-by-step. $pdo->query() does execute the query. the code you are posting with a $pdo->execute() produces a fatal runtime error. Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 $pdo->query() does execute the query. the code you are posting with a $pdo->execute() produces a fatal runtime error. Ops....sorry I just copy/paste his code .....of course this is wrong Should be like: $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $query = $pdo->prepare("SELECT img FROM `images` WHERE `cid` IN (1)"); $query->execute(); $row = $query->fetch(); echo '<pre>'.print_r($row, true).'</pre>'; $query = null; Instead query() use prepare()..... sorry about that Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 If I do `cid` in (1), I get nothing. If I replace it with an existing ID from my database (`cid` = '2091'), I get: Array ( [img] => GIF89a,úÕ?ó]Mï†nÍÐÐ \aZ;²ÏwÉÙç!ÑùʹŒŒŠ0lF´µµÿØÐg‹îîîÿµ¯Iv~ºÐÿ–ŠshðA/à®óŒá¹¨ûñÅÿïîo…b¹®ŽÒêíü¨]I>>''¶™‡µÖˆ‡¬½~š±¹Ýæ„$:ê÷ùPÂØÿüâ2?9àzt®€ßàÞ¾(4˜U9ãïøè÷îè67‚¨ ž þßßÿÁÁÿïø÷÷÷ÿ÷÷ÿÿöóÿýÞ ÿÿÿÿÿÿ!ÿNETSCAPE2.0!ÿXMP DataXMP ÿþýüûúùø÷öõôóòñðïîíìëêéèçæåäãâáàßÞÝÜÛÚÙØ×ÖÕÔÓÒÑÐÏÎÍÌËÊÉÈÇÆÅÄÃÂÁÀ¿¾½¼»º¹¸·¶µ´³²±°¯®¬«ª©¨§¦¥¤£¢¡ Ÿžœ›š™˜—–•”“’‘ŽŒ‹Š‰ˆ‡†…„ƒ‚€~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHGFEDCBA@?>=<;:9876543210/.-,+*)('&%$#"! !ùô?,,úÿÀpH,ȤrÉl:ŸÐ¨tJZ¯ØAoËíz¿à°xL.›Ïè´zÍn»ßð·0N¯Ûïø¼~Ï7Ïû€‚ƒ„…ƒ†‰Š‹Œ€ˆŽ‘’“”“•˜™š›q—œŸ ¡ ž¢¥¦§‰¤¨«¬tª[7³´µ¶³[,·¼³ ,®c½¾ÁÈh°=8>Î;ÏÑ>ÐÎ:[ÎÓÒÔÔ>×É_ÚÝÚ>ÇáêaËÍæïð:ØðõÚë]ãöÎ7éù{,ÛÀ¯ž‡9`€ö¡`~ûõ矀ÿàG_:‘ñtŒ‚õE(^Üàƒn|e¶jl@ÿÜ6ôPRØðjWhmÆE‡†ˆšj„Eqò‰l°Ôn¿ÒZau”`Yõ ÄÅ8À“P>éÀ ½ÍÀ²$à`_X@” Ø$&6$Gá4&=–@~ÃE Nƒì@”xæ™øpˆ¾mèY6tçCi>|×4ùM£vA¨¡ˆb‡RÍf8eáŠX°h!Cªg$u’%ªŸ6$Õp8†ÃŸ ©š£Ã \¾€¹ê@\gnyÛ1Eb”€ºÙà€Š‘¢FhPÅY@ì'†F#¤Aҵ̸ˆÇŒ¸i‡G}Úÿ¨"¥¾†—=´ŠamA6´C{OÅ„VbäJ{k»”¿ï\VFgš…Îo¨éö¨IxÀ§Œžc«,pëâC\©j„Áuª9òE¨äyg˜º’pëiƒ[óÆ•c}õk³6ŒŠYQ;;óa,’Á !Ýc´Á}• ÏÎZ¤]8íÔâ^c!º£Y¸»©»Z*è•‘,<´î$ô™5-óƒ4Å«¿#¿XwÐyÓY¬ß !=Æ[¾Y‚r}ñ`‚Ké&8£Œ÷ex_½ˆÙå‹”³Ì¤ºÏa°*·9ôfm˜ælàœ%Úó9a>´ÀkŽÿIg¯Ô®=±òcÝàÜÐ$½´õξü@Ô³6°0¢ñÐ&º=:8ë€ñ]gìH,EÂï_%gþ”6.ïlÞ~uåêÀv,|Ÿ:—3Ä‹ÎEõ8À€ØÅ©ˆ¶=4ɯã©M&vW´ŠûJlƨü9½ÃÄâqP¥ƒ в¸·¡ÉBùx¾1¤ïT±à;`Ÿ2@2þÐ ç—˜þdL@5Ü[5æQBgä6;œ›±Š·‘Äk…š` Oê‚“òÝmo¢0›ÜL=Q¾“Ä!F^b(M{”“"ŽÌ HRù ˜¹Šÿá…n9€ß±¾/\±€\й`ø«^™ÇuA4Åå‘‹" 9VÆš¨°™á ØH8Hq{tU'ÛW4IÁƒ‹[˜AwvšÃ5TCðA<‘ü«Êß"ŽiƒJYKT2ÙK>prš;ÕRvÙ¿X‚áÅ æñ”¢G¹Écƒð0$9‘™±A5ÚÐ¥3>S’Ë„[˜ç0·fpSŸŒæ_h*QšŒQ þ¬9Wžtg(brÉ6ô H‡âÂ?C9C)%ÙÓàØYw’ÊŽaÀã=B½ñùQ`ø<D ÿP€™ºR¤=p–˜Ïp³ÿ,@i5ú˜†´*ÇÜÂBÁàÇô”{»™#1—³›EýJfU¡IÆR;aî´HT!K‡áŒ)9ƒ¦Á(šºÑ¾øsšõi O™‹¬RW*œ’yÆzä0xŸ3µg¼Ôˆ£<SªÐ‚U¥¡¾IhŽÎ0Ôñµ(ìMØhC“ØaG“} N‘B6}VõÁj2Wò–&f ¤äL¢’‹é‘n®({ÏR°§ B† Õ£À¨îêÌÚ£gmØ”Në<±~r¶Pt€jžä3Ä$Æ|yÌ@¥\2©dw+Ùª¥3H9]¬â)³ûÉTž°ëhßÁÅ}¾#„ÓÿâAÌÊ»õ±À‚R±Ï,ôUg$`®ÌâY:rúp‡ŠBëÍ×zpSWq[šrP¨bñE©S›.Õ U.h¨Î€ÝU·«UÌ·S¹BGq_â‚çÃÅ휃><ÞÔ9ϼƒÄÌ{9˜b~Øò€ yÚ槡ä,‹ÍPIs„A uTˆÚpR&“ˆ¡.ÎlàåJ÷Oµî.lQæj¶Ã=ˆ€–nA_\£{²`®„G2G%bŽ—zФT™LT,ˆ@®Ê4¸¹†,Ðò–X×Ê‘U–¥-êØüò¼ n3\nàÞ±¸MœÚÝ3\”q·½ëæ)uÐãôR·‚^·—ÕÏ÷J:V€Ÿð®.Á/¬¨| ±§ÃÃëʽïì¾q•›é…¯Æ'tºGÅÞŽÐ@KrVÇ@ë‚-Åç6£a¸ "ÿ ŒoàJïn_0ð]x$€ša¥ÏL{Þ§ßa–Å7¶ÇàëÑòîxÇ» ðG»çýï€|ÝBöÀ;+3ð"êj²w¹”HðG¡Y\=—œX¢Ìï€/Ó\KãwJÔíp€rUY †e<òô¨O}åRÏúÖ»þôŽ|ý?œB%Ž{¯P—†³FÜ ä]Êý#Á` ÔKôò—¿|å3ÿùtt>ô§ÿéSÿúºÓjj„Ïýî{ÿûà¿øÇOþò›ÿüè?~· üáàýð¿üçOÿúÛÿþøÏ¿þ÷Ïÿþûÿÿ€8€ø~ñíWu·€Ø€ø€(ÿ®Å 8˜¸Ø Xì§U €X‚&x‚(˜‚‚Sw?$¨‚0ƒ28ƒÇ‚ª0‚4˜ƒ:¸ƒ@›>p–"™˜© © ÿéƒY–H9¡>‘ˆ˜‘x0!ðŸ”Y©Y0˜q9ž„™ ŠY.¹™ûYLyõ‘縙³ù’º)£/ú Ρ?* £9¤:ˆáù€éù¢GÚ£|étÉ ÊÐÝÉ‘‰i‘õˆ‰I¥VŠ”ššÖ)¦¤œ9 é ˆ¹£!º¦J™Eê@j—UZ§ÿ©¡‡È¡˜3 —õОlj¢¿É–%©šûöÈ”nY¨a}ê¨5z˜FÚ£,Š º—Ð’R @*§B:‘"z“ƒ ù™Œš™ð—mZ¬ZŽYJªcê0˜ü¨¦{¹šjÿèh«úŸüY¦>à˜Ç™œÚ ɪ–Y ¤±Z«’J¬1‰¤¦Š&¨ŠgieÉg)«Ãêœ à˜ i¨:‘q™ âJêH£ê›“z Ô)›•*’ *—Ó òÊ©Bê©qz£ËZ©ÎIˆÕjˆˆ”äè€z°1‘°ß9qUº3UšZ "º32P§ð€±y:°ŒÈغ™ÞªŒIê±æЬ 5€—Ψ§$Û²Ù8°’è²2û²¥w„3{³ð0²8»,»³×¨³:8'áÄQrwHÃ?>»€=›ƒB{XH4FËO›´¬´LKT t¬ww¦cT‡{hUðдÿY;µšqÚq×jGƒq3kµâÆ+ý‘Dqq¿”Ýcf«Hk2$7CUq{þ% гÀ×Óò*·$»´—ɲ1@óy]…ËQ˜ËQàv?4‡XF$u;Dz\¹Ü(·âF)w]Hƒf£‚B}‹Å” ;¥AÁ ¡+»/¢)UB9±APs];+¹â¶14‘3PNÃ6»ZëþåR+w¹„µ§KiÕ†4(ļ¿Äi—º0+¶ ±(%pX›µ™$½AM†;*Ù°‹Ñ¶Ûk½å½‡{ý»>‹¼â¶'·«½ë[š;´ZKÙ`Àì_Û»1ÿü£¿íV!ÿ[¾Xj"’uƒ¾æ@Mì´Î€¾¼Ð*ÑÁ,ºø`&ºìE·€u+¶%èé zÔ´¼»›«µ7ÌK$|¿YëÀšÆ½´'ß»¾ý´ª;qÊæá«„34᾿†Á#<À`!Å„Î!])ì»Ó`¼²°%w¼2\‚cq@¦ëÄ:ŒÀü£h(ŒUBŒÂó&9CÌ[VÁ5û„æ;qP 1ï’Xë·uÅ%¾…W¿k¿y¼IÑ°'òsK2¦Äi¼ƒµ n@‚æ{¨[8Ó@´Pv2»Ä”¸ÔR\õµïÀ©œ0Œ³¨<‰·‡&ùâÊÿU˜Éºì±µÜ˹ËÀÌ<ÌäÛÇWhÌÇŒ€Z³èÉ©³ÉˆÈ)HÍI‚ÄČ̀è^œµZÛÖ|‚á¬Øl3×»¡ÅÌ^¬Œã\‚ïlÈÃ6:ç¼±Ú\†ÌÒµ'‚|[QwRñ¼3k‹nýÆ1õPÏÔzÏlÈÍËñ¹ÕvU<Ô„´,§¹œ·4ó¾†ëm†K5l·oAUpŒW!Ð2Ò2ã3( ¸˜! 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jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 Again, is it a foreign key between tables "cardId" and "images"? Is it the column "cardId.id" in relation to the column "images.cid" ? Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 Yes, the images.cid must be the same as the cardId.Id to be shown. Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 7, 2013 Share Posted May 7, 2013 Sorry I am in a hurry, I will be back home after 6-7 hours. Try that, $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $cid = $_GET['cid']; // it's a link to category's id $query = $pdo->prepare(" SELECT `i`.`img`, `c`.* FROM `images` as `i` INNER JOIN `cardId` as `c` ON (`i`.`cid` = `c`.`id`) WHERE `i`.`cid`=:cid AND `c`.`status` = 1"); $query->bindParam('cid', $cid); $query->execute(); $row = $query->fetch(); echo '<pre>'.print_r($row, true).'</pre>'; $query = null; Quote Link to comment Share on other sites More sharing options...
public Posted May 7, 2013 Author Share Posted May 7, 2013 No problem. Result of the code above is a empty screen. Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 8, 2013 Share Posted May 8, 2013 (edited) Hey public,First off: You got an empty result maybe the requirements of the sql are not satisfied. Secondly: Do you understand my entire script, especialy the part of the sql? So if does not what part of the script it's not clear to you?Thirdly: Turn on the error_reporting, put it on top of the page - error_reporting(-1);Four: You can customise your outputs of the SELECT statement to whatever you want, c.* is not very efficiency.Five: You can also EXPLAIN those two tables, so someone could suggest you a better database design.Lastly: I modify (I don't know the past tense) a little the script in case you have more than 1 image to this category id (cid). $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root'); $cid = $_GET['cid']; // it's the value from the category id coming from the link $query = $pdo->prepare(" SELECT `i`.`img`, `c`.* FROM `images` as `i` INNER JOIN `cardId` as `c` ON (`i`.`cid` = `c`.`id`) WHERE `i`.`cid` IN (:cid) AND `c`.`status`=1"); $query->bindParam('cid', $cid); $query->execute(); while ($row = $query->fetch(PDO::FETCH_ASSOC)) { echo '<pre>'.print_r($row, true).'</pre>'; } $query = null; Edited May 8, 2013 by jazzman1 Quote Link to comment Share on other sites More sharing options...
mac_gyver Posted May 8, 2013 Share Posted May 8, 2013 there's so much wrong with this thread, i don't know where to begin. the current problem is that the bind_parm() statement is using the wrong syntax for the placeholder. it would need to be ':cid'. but since you are actually trying to retrieve the first 10 rows with ascending ids, you wouldn't need to match any cid in the query at the point of outputting the <img > tags on a web page. you will need to match individual cid's when you actually output the image to the browser (read on to find out what this means.) back to the stated task and the first posted code. you are trying to output x number of images on a web page. to do that you must output an <img src=' ... '> tag for each image. to determine the image dimensions, since you apparently didn't store them with the image data, you must retrieve all the matching image data and use GD to create each image to find it's dimensions. (as a side note, you cannot output the image data in your html page, so you must repeat this process in a separate .php script to output each stored image, one at a time when the browser requests each image.) this will require a huge amount of processing each time your page gets requested. if it is an option, you should add height and width columns to the images table and populate them with the dimensions of each stored image. Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted May 8, 2013 Share Posted May 8, 2013 No, the syntax is OK It is not really need to put quotes. See the prove: $dbh = new PDO('mysql:host=localhost;dbname=sakila', 'jazzman', 'password'); $name = 'PENELOPE'; $stmt = $dbh->prepare("select * from actor where first_name IN (:name)"); $stmt->bindParam('name',$name); $stmt->execute(); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo '<pre>'.print_r($row, true).'</pre>'; } $stmt = null; Results: Array( [actor_id] => 1 [first_name] => PENELOPE [last_name] => GUINESS [last_update] => 2006-02-15 04:34:33) Array( [actor_id] => 54 [first_name] => PENELOPE [last_name] => PINKETT [last_update] => 2006-02-15 04:34:33) Array( [actor_id] => 104 [first_name] => PENELOPE [last_name] => CRONYN [last_update] => 2006-02-15 04:34:33) Array( [actor_id] => 120 [first_name] => PENELOPE [last_name] => MONROE [last_update] => 2006-02-15 04:34:33) Quote Link to comment Share on other sites More sharing options...
mac_gyver Posted May 8, 2013 Share Posted May 8, 2013 it's not supposed to work, but does, with named placeholder if the : is not there. i would suggest that leaving it out may cause your code to break at any version change. Quote Link to comment Share on other sites More sharing options...
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