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I have a table with images in BLOBs. I want to show one of those images where the height isn't bigger than 100px and the width not bigger than 120px. If such an image isn't found, it will display a standard image. 

 

I'm getting this error:

 

 

Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource in /home/server15/public_html/cards/view.php on line 50

 

 

 

 

<?php
class MySQL
{
/*
* Set up private variables for connection
*/
// private $host   = 'localhost';
// private $user   = 'admin';
// private $pass   = 'root';
// private $dbname = 'database';


private $host   = 'localhost';
private $user   = 'admin';
private $pass   = 'root';
private $dbname = 'database';


/*
* Error messages variables
*/
private $error_open = '<div style="color: red;">';
private $error_close = '</div>';


/*
* Create a construct method to handle the connection
*/
function __construct()
{
$host   = $this->host;
$user   = $this->user;
$pass   = $this->pass;
$dbname = $this->dbname;


$this->sql_link = mysql_connect($host, $user, $pass) or die('error 1!');
mysql_select_db($dbname, $this->sql_link) or die('error!');
}


/*
* Create query method to select things from the mysql database
*/
function query($sql)
{
return mysql_query($sql);
}


/*
* Create fetch_object method to fetch the previously ran query
*/
function fetch_object($query)
{
return mysql_fetch_object($query);
}


function fetch_array($query)
{
return mysql_fetch_array($query);
}


/*
* Create num_rows method to fetch the previously ran query rows in an int
*/
function num_rows($query)
{
return mysql_num_rows($query);
}


/*
* Escape chars from SQL Injection
*/
function escape($string)
{
return mysql_real_escape_string($string);
}


}
$db = new MySQL();
$loadCards = $db->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 ");
while ($row = $db->fetch_object($loadCards))
{
$loadImages = $db->query("SELECT * FROM `images` WHERE `cid` = '$row->id'");
while ($rowIMG = $db->fetch_object($loadImages))
{
$img = imagecreatefromstring($rowIMG->img); 
$height = $imagesy($img);
$width = imagesx($img);
if (($height > 100) OR ($width > 120))
{
echo '<img src="noimage.png" />';
} else {
echo '<img src="'; 
echo image($img); 
echo ' ">'; 
}
}
}
?>

Does anyone know how to fix this?

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You should look into using the PDO class. It looks like you're actually trying to set up your own PDO type class, but you're using lots of deprecated functions..

 

$pdo = new PDO('mysql:host=localhost;dbname=YOUR-DB-NAME', 'USERNAME', 'PASSWORD');
$query = $pdo->query("Your query written correctly");
$results = $query->fetchAll();

That code should get you started :)

Denno

I've 'cleaned' the file and it's now like this (the row img from the tabel images stores the blob image file):

<?php

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');

$query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 ");
$results = $query->fetchAll();

$query2 = $pdo->query("SELECT * FROM `images` WHERE `cid` = '$results->id'");
$results2 = $query2->fetchAll();

$img = imagecreatefromstring($results2->img); 
$height = $imagesy($img);
$width = imagesx($img);
if (($height > 100) OR ($width > 120))
{
	echo '<img src="noimage.png" />';
} else {
	echo '<img src="'; 
	echo image($img); 
	echo ' ">'; 
}
?>

The following errors appear on my screen:

 

Warning: imagecreatefromstring() [function.imagecreatefromstring]: Empty string or invalid image in /home/server15/public_html/cards/view.php on line 11

Fatal error: Function name must be a string in /home/server15/public_html/cards/view.php on line 12

you've got

 

$height = $imagesy($img);

 

You need to get rid of the dollar sign before imagesy:

 

$height = imagesy($img);

 

You've done it right on the next line for $width

 

As for the warning, just make sure you have actually got a result by using var_dump($result).

I've changed SELECT * FROM `images` in SELECT img FROM `images` and $results2->img in $results2 and the height/width thing.

 

When I use var_dump($results2) I get this on my screen:

array(1) { [0]=> array(2) { ["img"]=> string(37683) "
[the image file as code]
Warning: imagecreatefromstring() [function.imagecreatefromstring]: Empty string or invalid image in /home/server15/public_html/cards/view.php.php on line 11


Warning: imagesy(): supplied argument is not a valid Image resource in /home/server15/public_html/cards/view.php.php on line 12


Warning: imagesx(): supplied argument is not a valid Image resource in /home/server15/public_html/cards/view.php.php on line 13

According to the code it isn't a valid image I think, but it is a PNG file. I've tried gifs/jpegs, but I got the same result.

This is all my code in the file:

<?php

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');

$query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 ");
$results = $query->fetchAll();

$query2 = $pdo->query("SELECT img FROM `images` WHERE `cid` = '$results->id'");
$results2 = $query2->fetchAll();

$img = imagecreatefromstring($results2);
$height = imagesy($img);
$width = imagesx($img);
if (($height > 100) OR ($width > 120))
{
    echo '<img src="noimage.png" />';
} else {
    echo '<img src="';
    echo image($img);
    echo ' ">'; 
}
?>

It's a build pdo method.

 

First off I wanna get a result from first statement but I see that you don't executing it at all, so step-by-step.

 

Try this and give me the result back:

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');

$query = $pdo->query("SELECT * FROM `cardId` WHERE `status` = '1' ORDER BY `id` ASC LIMIT 10 ");

$query->execute(); 

$row = $query->fetch(); 
    
echo '<pre>'.print_r($row, true).'</pre>'; 

$query = null;
Edited by jazzman1

Alright then, before to join those two tables, just one question. 

 

Is it a foreign key between tables "cardId" and "images" , if so this column is called "cid" ?

 

Give me the result back of this statement:

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');
     
    $query = $pdo->query("SELECT img FROM `images` WHERE `cid` IN (1)");
     
    $query->execute();
     
    $row = $query->fetch();
    echo '<pre>'.print_r($row, true).'</pre>';
     
    $query = null;

 

It's a build pdo method.

 

First off I wanna get a result from first statement but I see that you don't executing it at all, so step-by-step.

 

 

$pdo->query() does execute the query.

 

the code you are posting with a $pdo->execute() produces a fatal runtime error.

$pdo->query() does execute the query.

 

the code you are posting with a $pdo->execute() produces a fatal runtime error.

 

Ops....sorry I just copy/paste his code .....of course this is wrong

 

Should be like:

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');
     
    $query = $pdo->prepare("SELECT img FROM `images` WHERE `cid` IN (1)");
     
    $query->execute();
     
    $row = $query->fetch();
    echo '<pre>'.print_r($row, true).'</pre>';
     
    $query = null;

Instead query() use prepare()..... sorry about that :)

If I do `cid` in (1), I get nothing.

 

If I replace it with an existing ID from my database (`cid` = '2091'), I get:

Array
(
    [img] => GIF89a,úÕ?ó]Mï†nÍÐÐ	\aZ;²ÏwÉÙç!ÑùʹŒŒŠ0lF­´µµÿØÐg‹îîîÿµ¯Iv~ºÐÿ–ŠshðA/à®óŒá¹¨ûñÅÿïîo…b¹®ŽÒêíü¨]I>>''¶™‡µÖˆ‡¬½~š±¹Ýæ„$:ê÷ùPÂØÿüâ2?9àzt®€ßàÞ¾(4˜U9ãïøè÷îè67‚¨ ž þßßÿÁÁÿïø÷÷÷ÿ÷÷ÿÿöóÿýÞ
ÿÿÿÿÿÿ!ÿNETSCAPE2.0!ÿXMP DataXMP        ÿþýüûúùø÷öõôóòñðïîíìëêéèçæåäãâáàßÞÝÜÛÚÙØ×ÖÕÔÓÒÑÐÏÎÍÌËÊÉÈÇÆÅÄÃÂÁÀ¿¾½¼»º¹¸·¶µ´³²±°¯®­¬«ª©¨§¦¥¤£¢¡ Ÿžœ›š™˜—–•”“’‘ŽŒ‹Š‰ˆ‡†…„ƒ‚€~}|{zyxwvutsrqponmlkjihgfedcba`_^]\[ZYXWVUTSRQPONMLKJIHGFEDCBA@?>=<;:9876543210/.-,+*)('&%$#"! 

	!ùô?,,úÿÀpH,ȤrÉl:ŸÐ¨tJ­Z¯ØAoËíz¿à°xL.›Ïè´zÍn»ßð·0N¯Ûïø¼~Ï7Ïû€‚ƒ„…ƒ†‰Š‹Œ€ˆŽ‘’“”“•˜™š›q—œŸ ¡ ž¢¥¦§‰¤¨«¬­tª[7³´µ¶³[,·¼³	,®c½¾ÁÈh°=8>Î;ÏÑ>ÐÎ:[ÎÓÒÔÔ>×É_ÚÝÚ>ÇáêaËÍæïð:ØðõÚë]ãöÎ7éù{,ÛÀ¯ž‡9`€ö¡`~ûõ矀ÿàG_:‘ñtŒ‚õE(^Üàƒn|e¶jl@ÿÜ6ôPRØðjWhmÆE‡†ˆšj„Eqò‰l°Ôn¿ÒZau”`Yõ ÄÅ8À“P>éÀ
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¢b’_‚¦˜c’Y&˜]þE

Sorry I am in a hurry, I will be back home after 6-7 hours.

 

Try that,

$pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');
    
    $cid = $_GET['cid']; // it's a link to category's id 
    
    $query = $pdo->prepare("
     SELECT `i`.`img`, `c`.* FROM `images` as `i`
     INNER JOIN `cardId` as `c` ON (`i`.`cid` = `c`.`id`)    
     WHERE `i`.`cid`=:cid AND `c`.`status` = 1");
    
    $query->bindParam('cid', $cid);
     
    $query->execute();
     
    $row = $query->fetch();
    
    
    echo '<pre>'.print_r($row, true).'</pre>';
     
    $query = null;

Hey public,

First off: You got an empty result maybe the requirements of the sql are not satisfied.  

Secondly: Do you understand my entire script, especialy the part of the sql? So if does not what part of the script it's not clear to you?

Thirdly: Turn on the error_reporting, put it on top of the page - error_reporting(-1);

Four: You can customise your outputs of the SELECT statement to whatever you want, c.* is not very efficiency.

Five: You can also EXPLAIN those two tables, so someone could suggest you a better database design.

Lastly: I modify (I don't know the past tense) a little the script in case you have more than 1 image to this category id (cid).

    $pdo = new PDO('mysql:host=localhost;dbname=database', 'admin', 'root');
    
    $cid = $_GET['cid']; // it's the value from the category id coming from the link
    
    $query = $pdo->prepare("
     SELECT `i`.`img`, `c`.* FROM `images` as `i`
     INNER JOIN `cardId` as `c` ON (`i`.`cid` = `c`.`id`)    
     WHERE `i`.`cid` IN (:cid) AND `c`.`status`=1");
    
    $query->bindParam('cid', $cid);
     
    $query->execute();
    
    while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
    
   echo '<pre>'.print_r($row, true).'</pre>';
   
   } 
   $query = null;
Edited by jazzman1

there's so much wrong with this thread, i don't know where to begin. the current problem is that the bind_parm() statement is using the wrong syntax for the placeholder. it would need to be ':cid'. but since you are actually trying to retrieve the first 10 rows with ascending ids, you wouldn't need to match any cid in the query at the point of outputting the <img > tags on a web page. you will need to match individual cid's when you actually output the image to the browser (read on to find out what this means.)

 

back to the stated task and the first posted code. you are trying to output x number of images on a web page. to do that you must output an <img src=' ... '> tag for each image. to determine the image dimensions, since you apparently didn't store them with the image data, you must retrieve all the matching image data and use GD to create each image to find it's dimensions. (as a side note, you cannot output the image data in your html page, so you must repeat this process in a separate .php script to output each stored image, one at a time when the browser requests each image.) this will require a huge amount of processing each time your page gets requested. if it is an option, you should add height and width columns to the images table and populate them with the dimensions of each stored image.

No, the syntax is OK :)

 

It is not really need to put quotes.

 

See the prove:

$dbh = new PDO('mysql:host=localhost;dbname=sakila', 'jazzman', 'password');

$name = 'PENELOPE';

$stmt = $dbh->prepare("select * from actor where first_name IN (:name)");

$stmt->bindParam('name',$name);

$stmt->execute();
 
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
    
   echo '<pre>'.print_r($row, true).'</pre>';
   
}   

$stmt = null;

Results:

 

Array(    [actor_id] => 1    [first_name] => PENELOPE    [last_name] => GUINESS    [last_update] => 2006-02-15 04:34:33)
Array(    [actor_id] => 54    [first_name] => PENELOPE    [last_name] => PINKETT    [last_update] => 2006-02-15 04:34:33)
Array(    [actor_id] => 104    [first_name] => PENELOPE    [last_name] => CRONYN    [last_update] => 2006-02-15 04:34:33)
Array(    [actor_id] => 120    [first_name] => PENELOPE    [last_name] => MONROE    [last_update] => 2006-02-15 04:34:33)
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