mysql_fetch_assoc() ?

[managerstats]

<ol>
<?php
include '../globals.php';

$manager = $_GET['manager'];  
$query = "SELECT 'manager' FROM 'tablename' WHERE manager='.$manager.' ";
$rs = mysql_query($query); 
while ($row = mysql_fetch_assoc($rs)) 

{
echo '<li>' . $row['manager'] . '</strong> '; 
echo '<strong>' . $row['won'] . '</strong> '; 
echo '<strong>' . $row['drawn'] . '</strong> '; 
echo '<strong>' . $row['lost'] . '</strong> '; 
echo '<strong>' . $row['total'] . '</strong> '; 
echo '<strong>' . $row['club'] . '</strong></li> '; 
} 

mysql_close(); ?>
</ol>

I have been around in circles trying to solve this without success.

 

Essentially I am trying to set up anchors such as;

<a href="sitename.com/?manager=Micky Adams">Micky Adams</a>

But I get;

 

  Quote

PHP Warning:  mysql_fetch_assoc() expects parameter 1 to be resource

 

Can someone please point me in the right direction or let me know where I have gone wrong in my code?

[Barand]

Use backtick ` and not single quotes around the tablename

 

Check your queries have worked and use mysql_error() to find out why it failed

[managerstats]

The backtick around the table name worked at removing the error notice but not fetching any results

 

http://managerstats.co.uk/tests/?manager=Micky Adams

 

Maybe something in the query itself?

[managerstats]

Not sure how to implement the mysql_error()

 

(newb)

[litebearer]

Try echoing your query

[Barand]

  On 5/10/2013 at 12:29 PM, managerstats said:

Not sure how to implement the mysql_error()

 

(newb)

 

mysql_query - see examples on this page

[managerstats]

Added mysql_query()

 

Just returning blank, but this time with the HTML and no results (see above link)

[litebearer]

Did you echo your query to see if it contains what you expect it to contain?

[managerstats]

  On 5/10/2013 at 1:02 PM, litebearer said:

Did you echo your query to see if it contains what you expect it to contain?

 

Not sure how to do that either?

[mac_gyver]

the syntax you are using for the $manager variable in the WHERE clause is adding dots . before and after the value, so your WHERE clause is false and is not matching anything.

 

you can put a php variable inside of a double quoted string. you also had single quotes around the column name in the SELECT clause, which would have literally returned the string 'manager' -

$query = "SELECT manager FROM tablename WHERE manager='$manager'";

[litebearer]

$query = "SELECT manager FROM tablename WHERE manager='$manager'";
echo $query;
exit();

 

 

[managerstats]

  On 5/10/2013 at 1:12 PM, mac_gyver said:

 

the syntax you are using for the $manager variable in the WHERE clause is adding dots . before and after the value, so your WHERE clause is false and is not matching anything.

 

you can put a php variable inside of a double quoted string. you also had single quotes around the column name in the SELECT clause, which would have literally returned the string 'manager' -

$query = "SELECT manager FROM tablename WHERE manager='$manager'";

 

Thank you Mac_Gyver! you absolute beauty, this solved it.

 

Thank you all for your help, this has had me going insane all day, happy Friday and have a good weekend all.