ThomasBalaban Posted May 15, 2013 Share Posted May 15, 2013 Hello, I am currently working on my first passion project which I am trying to create a account based system where users can register / log in / log out. I am having one small issue I can't seem to figure it out. The old version of the site can be found here http://thomasbalaban.com/pieces/afterlyfegaming/login.php (I have done many updates but this problem is happening on this one so why update it for this). The problem is when someone makes a account for some reason my code is making three accounts. Here is my code. //bring in the code to run a query: include("../includes/checkDb.php"); session_start(); //make vars to store what the user typed $userId = 0; $userUsername = $_POST['createUser']; $userPassword = $_POST['createPassword']; //add one to the highest id being used $result = run_my_query("select * from users order by userId desc limit 1"); while($row = mysql_fetch_array($result)){ $userId = $row["userId"]; } $userId++; echo "Account creation succesful, redirecting"; run_my_query(" INSERT INTO users VALUES (null, '$userUsername', '$userPassword', 'user', null, null, null, null) "); header("refresh:3;url=../index.php"); and this is the include /* Connects to local host and gets the sql file open */ function run_my_query($query){ $serverHandle = mysql_connect('localhost', 'root'); if($serverHandle == false){ die("bad server connection".mysql_error()); } $myDb = mysql_select_db('user_table') or die ('DB Problem - '.mysql_error()); $result = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result2 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result3 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); mysql_close($serverHandle); return $result; } function run_my_query2($query){ $serverHandle = mysql_connect('localhost', 'root'); if($serverHandle == false){ die("bad server connection".mysql_error()); } $myDb = mysql_select_db('user_table') or die ('DB Problem - '.mysql_error()); $result = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result2 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result3 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); mysql_close($serverHandle); return $result; } Can you guys see my problem? I have been trying to figure it out all day. Thank you very much! Quote Link to comment Share on other sites More sharing options...
Jessica Posted May 15, 2013 Share Posted May 15, 2013 Yes, you're running the query 3 times. $result = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result2 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result3 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); Quote Link to comment Share on other sites More sharing options...
ThomasBalaban Posted May 16, 2013 Author Share Posted May 16, 2013 Yes, you're running the query 3 times. $result = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result2 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); $result3 = mysql_query($query) or die ('Query Problem - '.$query.mysql_error()); I completely over looked that. Thank you so much! Quote Link to comment Share on other sites More sharing options...
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