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I don't understand why this isn't doing anything.


Go to solution Solved by jcbones,

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 $data = mysql_query("SELECT ip,points FROM information") 
 or die(mysql_error()); 
 if (!empty($_SERVER['HTTP_CLIENT_IP'])){
  $ip=$_SERVER['HTTP_CLIENT_IP'];
}elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){
  $ip=$_SERVER['HTTP_X_FORWARDED_FOR'];
}else{
  $ip=$_SERVER['REMOTE_ADDR'];
}
$ip = ip2long($ip);
 while($info = mysql_fetch_array( $data )) 
 { 
 if($info['ip'] != null && $info['ip'] == $ip){
	Print "You have $info[points] points!";
 } else {
	 mysql_query("INSERT INTO information VALUES ('$ip','0')'");
	 Print "You have 0 points!";
 } 
 }

This is just giving me a blank page.

Just this.

  <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">   <html xmlns="http://www.w3.org/1999/xhtml">   <head>   <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />   <title>Wolf Empire</title>   </head>   <body>   </body>   </html>

 

There is nothing there. I got most of the code online and placed it together. 

At the moment, it returns MySQL returned an empty result set (i.e. zero rows). ( Query took 0.0004 sec )

I don't have anything on it atm, but Im planning to add. Also the code seems to stop off here.

while($info = mysql_fetch_array( $data ))
{

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