php error: Failed to Open Stream

[samg]

Hi,

 

I have the "include" in my code but it errors out with "failed to open stream: HTTP request failed! " error. 

I already have this set in php.ini "allow_url_include = On" but it still fails.

Can anybody help?

 

Thanks

Edited July 8, 2013 by samg

[samg]

=======

Edited July 8, 2013 by samg

[Svenskunganka]

Provide your code please...

[Irate]

You are including a file from your own server, right?

 

Otherwise, the server you're trying to send the request to might have set header('Access-Control-Access-Origin: http://owndomain.com'); so that only their own domain can send HTTP requests to their site and get responses.

Just an educated guess, though.

[AbraCadaver]

How about: allow_url_fopen

[samg]

Thanks for the quick response.

 

@Svenskunganka :     I tried to post my code but it doesn't allow me . As soon as I click save, it disappears . Let me try again.

@Irate: Yes I am trying to include a file on my sever itself.

 

1. Here is the dir structure:

a) /test/foo.php --> this has include to my own server. I tried to paste the exact code but it removed it . bascially its pointing to my own server using SERVER variables pointing to "bar.php"

b) /test/bar.php

 

2. Apache document root is pointing to "/test" like

=====

/var/www/html --> /test

=====

 

3. echo __DIR__  shows me "/test" so its definitely pointing to the right directory.

4. I have given full permssiion to this directory, in case that's the issue but no luck.

5. Exact error in apache error log. I had to remove the exact URL as this post doesn't allow me post that.

=====

[Mon Jul 08 10:41:49 2013] [error] [client ] PHP Warning:  include<URL>: failed to open stream: HTTP request failed!  in /test/foo.php

[Mon Jul 08 10:39:49 2013] [error] [client ] PHP Warning:  include(): Failed opening <URL> for inclusion (include_path='.:/usr/share/pear:/usr/share/php') in /test/foo.php

=====

 

Let me know if any other info is needed.

 

Thanks

Edited July 8, 2013 by samg

[samg]

@AbraCadaver: Yep. that property is already set to "On".

[AbraCadaver]

Why not just:

include('bar.php');

[samg]

@Shawn: with that I get, No such file or directory even though "echo __DIR__" returns "test" which contains "bar.php"

Edited July 8, 2013 by samg

[samg]

I may have figured out what the problem may be. I am passing query parameters to the file in include and I guess it considers those parameters as part of file name.

Do you know how I can pass query parameters in the "include"?

Edited July 8, 2013 by samg

[AbraCadaver]

You don't include with query parameters, just use variables:

//foo.php
$a = 1;
include('bar.php');

//bar.php
echo $a;

[samg]

If I have multiple "include" for the same file with same parameters but with different values for those parameters, should I re-initialize my parameters before each include?

Is that the way to go?

[AbraCadaver]

I assume you mean multiple includes in the same file.  If so, then two ways.  One is what you just described, but if you use a function you only need one include:

//foo.php
$a=1;
$b=2;
include('bar.php');

$a=3;
$b=4;
include('bar.php');

//bar.php
echo $a+$b;

Or using a function:

//foo.php
include('bar.php');
show_addition(1, 2);
show_addition(3, 4);

//bar.php
function show_addition($arg1, $arg2) {
   echo $arg1+$arg2;
}