Implode JSON

[NebuJohn]

Below Given is my Code.

        $array=$_POST[number];
        $jstring = json_decode($array,true);

        $sa = "'".implode("','",$jstring)."'";

The error is given below.

        Warning: implode() [function.implode]: Invalid arguments passed <root> on line <line no>

 

'number' is a JSON object.

Edited July 25, 2013 by NebuJohn

[Muddy_Funster]

need more info

[NebuJohn]

May i Know what all information you need more. number is a Jason object which holds numbers from mobile contact. I was able to append that into a file. Now i need that data to be fetched into a SQL query as comma separated string.

[NebuJohn]

I fixed this problem. Sharing with others.

        $array=$_POST[number];
        $jstring = (array)json_decode($array,true);

        $sa = "'".implode(',',$jstring)."'";