Parse error: syntax error, unexpected '=' in C:\wamp\www\storefront\showitem.php on line 55

shwetapandit · July 31, 2013

i don't know why i m getting this error.Parse error: syntax error, unexpected '=' in C:\wamp\www\storefront\showitem.php on line 55.my script is:

if anyone can help me to fix bug then plz.thanks in advance......

<?php
//connect to database
$mysqli = mysqli_connect("localhost", "root", "", "storefront");
$display_block = "<h1>My Store - Item Detail</h1>";

//create safe values for use
$safe_item_id = mysqli_real_escape_string($mysqli, $_GET['item_id']);

//validate item
$get_item_sql = "SELECT c.id as cat_id, c.cat_title, si.item_title,
si.item_price, si.item_desc, si.item_image FROM store_items
AS si LEFT JOIN store_categories AS c on c.id = si.cat_id
WHERE si.id = '".$safe_item_id."'";
$get_item_res = mysqli_query($mysqli, $get_item_sql)
or die(mysqli_error($mysqli));

if (mysqli_num_rows($get_item_res) < 1) {
//invalid item
$display_block .= "Invalid item selection.";
} else {
//valid item, get info
while ($item_info = mysqli_fetch_array($get_item_res)) {
$cat_id = $item_info['cat_id'];
$cat_title = strtoupper(stripslashes($item_info['cat_title']));
$item_title = stripslashes($item_info['item_title']);
$item_price = $item_info['item_price'];
$item_desc = stripslashes($item_info[‘item_desc’]);
$item_image = $item_info[‘item_image’];
}

//make breadcrumb trail & display of item
$display_block .= <<<END_OF_TEXT
You are viewing: 
<a href="seestore.php?cat_id=$cat_id">$cat_title</a> >
$item_title
<div style="float: left;"><img src="$item_image" alt="$item_title"
/></div>
<div style="float: left; padding-left: 12px">
Description: $item_desc
Price: \$$item_price
END_OF_TEXT;

//free result
mysqli_free_result($get_item_res);

//get colors
$get_colors_sql = "SELECT item_color FROM store_item_color WHERE
item_id = '".$safe_item_id."' ORDER BY item_color";
$get_colors_res = mysqli_query($mysqli, $get_colors_sql)
or die(mysqli_error($mysqli));

if (mysqli_num_rows($get_colors_res) > 0) {
$display_block .= "Available Colors: ";
while ($colors = mysqli_fetch_array($get_colors_res)) {
item_color = $colors['item_color'];
$display_block .=$item_color." ";
}
}
//free result
mysqli_free_result($get_colors_res);

//get sizes
$get_sizes_sql = "SELECT item_size FROM store_item_size WHERE
item_id = ".$safe_item_id." ORDER BY item_size";
$get_sizes_res = mysqli_query($mysqli, $get_sizes_sql)
or die(mysqli_error($mysqli));

if (mysqli_num_rows($get_sizes_res) > 0) {
$display_block .= "Available Sizes: ";
while ($sizes = mysqli_fetch_array($get_sizes_res)) {
$item_size = $sizes['item_size'];
$display_block .= $item_size." ";
}
}
//free result
mysqli_free_result($get_sizes_res);

$display_block .= "</div>";
}
//close connection to MySQL
mysqli_close($mysqli);
?>
<!DOCTYPE html>
<html>
<head>
<title>My Store</title>
</head>
<body>
<?php echo $display_block; ?>
</body>
</html>

Muddy_Funster · July 31, 2013

Line 53 - you missed the $ at the start of the item_color variable name

Barand · July 31, 2013

... and line 55 is ???

Use the code button <> and apply line numbering when posting code

PravinS · July 31, 2013

Line 53 - you missed the $ at the start of the item_color variable name

search this line and apply $

item_color = $colors['item_color'];

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Parse error: syntax error, unexpected '=' in C:\wamp\www\storefront\showitem.php on line 55

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